A train travelling at a speed of 76 mph enters a tunnel 9/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
Lets represent each term of series x+iy
x and y are two different series as described below:
x = Square of natural numbers + 1 = (1+1), (4+1), (9+1), (16+1), (25+1), (36+1)
y= Prime numbers Series = 2, 3, 5, 7, 11, 13
So the 6th term is = [(6^2+1) + (6th Prime number)i = 37+13i
Lets arrange the letters of RANKING alphabetically
AGIKNNR
Please note that only N is repeated twice
Words starting with letter A = 6!/2! = 360
Words starting with letter G = 6!/2! = 360
Words starting with letter I = 6!/2! = 360
Words starting with letter K = 6!/2! = 360
Words starting with letter N = 6! = 720
Words starting with letter RAG = 4!/2! = 12
Words starting with letter RAI = 4!/2! = 12
Words starting with letter RAK = 4!/2! = 12
Words starting with letter RANG = 3! = 6
Words starting with letter RANI = 3! = 6
Words starting with letter RANKG = 2! = 2
Words starting with letter RANKIG = 1 = 1
And next word is RANKING, so + 1 = 1
Sum of all = 4*360 + 720 + 3*12 + 2*6 + 2 + 1 +1 = 2212
The present ages of two persons differ by 16 years. 3 years ago, the elder one was 3 times as old as the younger one. What is the present age of the elder person?
OPtion
1) 37 years
2) 35.5 Years
3) 25 years
4) 29 years
5) 27.5 years
6) 31 years
7) 23 years
8) 24 years
9) 29 years
10) None of these
Solution
Let the present age of elder one be x and younger one be y
So x-y = 16 ----(i)
3 year ago
(x-3) =3(y-3)
=> x = 3y - 6
Putting x value in (i)
3y - 6 - y = 16
=>2y = 22
=> y = 11
and x = 11+ 16 = 27
Hence Option 10)
P can do a work in 12 days. Q can do the same work in 6 days and R can do the same in 8 days. Q and R start the work and leave after 2 days. P finishes the remaining work in X days. What is the value of X?
OPtion
1) 2 days
2) 2.5 days
3) 3 days
4) 3.5 days
5) 4 days
6) 4.5 days
7) 5 days
8) 5.5 days
9) 6.0 days
10) 10 days
Solution
Amount of work done by Q and R in 2 days = 2*(1/6 + 1/8) = 7*2/24 = 7/12
Amount of work remianing after 3 days = 5/12
Amount of work done by P in 1 day = 1/12
So for 1/12 work P takes 1 day
Hence for 5/12 work P would take (1/(1/12))*5/12 = 5 days