M4maths Previous Puzzles

25 Jan 2017 Rank of word

Rank of the word EUCALYPTUSin the dictionary of words formed by the letters of the word EUCALYPTUS

OPtion

1) 488979
2) 488980
3) 488939
4) 488940
5) 488959
6) 488960
7) 488920
8) 488919
9) 488999
10)488990

Solution

Arranging letters in alphabetical order: ACELPSTUUY, only U is repeated (2 U’s)
Words starting with Alphabet A = 9!/2!
Words starting with Alphabet C = 9!/2!
Words starting with Alphabet EA = 8!/2!
Words starting with Alphabet EC = 8!/2!
Words starting with Alphabet EL = 8!/2!
Words starting with Alphabet EP = 8!/2!
Words starting with Alphabet ES = 8!/2!
Words starting with Alphabet ET = 8!/2!
Words starting with Alphabet EUA = 7!
Words starting with EUCALP= 4!
Words starting with EUCALS= 4!
Words starting with EUCALT= 4!
Words starting with EUCALU= 4!
Words starting with EUCALYPS = 2!
Words starting with Alphabet EUCALYPTS= 1
And next word is EUCALYPTUS
Sum of all words = 2*9!/2! + 6*8!/2! + 7! + 4*4! + 2! +1 = 488980

Option 2)

Correct Option: 2 Best Solution (2)

Ajay Sharma   7 years AGO

EUCALYPTUS
Now according to rank,
2*9!+3*8!+1+0*6!+0*5!+4*4!+0*3!+1*2!+1*1!+0*0!+1=488980

Like? Yes (1) | No   

Mukund Manohar   7 years AGO

Total no. of words = 10*9*8*7*6*5*4*3*2*1/2*1 = 1814400
Rank of word EUCALYPTUS
= (1814400/10)*2 + (181440/9)*6 + (40320/8)*1 + (5040/7)*0 + (720/6)*0 + (120/5)*4 + (24/4)*0 + (6/3)*1 + (2/2)*1 + 1
= 362880 + 120960 + 5040 + 0 + 0 + 96 + 0 + 2 + 1 + 1
= 488980

Like? Yes (1) | No   

24 Jan 2017 Interest

There is 40% increase in an amount in 8 years at simple interest. What will be the compound interest of Rs. 1,600 after 3 years at the same rate?

OPtion

1) Rs. 242.5
2) Rs. 244.2
3) Rs. 248.5
4) Rs. 252.2
5) Rs. 256.5
6) Rs. 260.2
7) Rs. 264.5
8) Rs. 268.2
9) Rs. 272.5
10)Rs. 276.2

Solution

Let investment in 1st case be Rs. 100, then SI= Rs. 140
Rate = 100*40/(100*8) = 5%
CI= P (1 + r/100) ^T – P
=1600 * (1+0.05)^3 ) – 1600 = 1852.2 – 1600 = 252.2

Option 4)

Correct Option: 4 Best Solution (25)

G.S.Kantharao   7 years AGO

I=PTR/100
1600*40/100=1600*8*R/100
R=5%
A=P(1+R/100)³
=1600{1+(5/100)}³
=1600(1.05)³=1852.2
Compound Interest = 252.2
Hence it is 4 to choose.

Like? Yes (4) | No   

Devendra Marghade   7 years AGO

Let the amount be x, then
S.I. in 8 years at the rate of r% = x*8*r/100 = 0.4x =>r=5
So C.I. of Rs 1600 @ 5% in 3 years=1600(1+ 5/100)^3 -1600 = 1600[ (21/20)^3 - 1] = 252.2 Rs.
Option 4)

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satish kumar   7 years AGO

let p=100 then Amt=140 then S.I=40
S.I=p*r*t/100
40=100*r*8/100
R=5%
c.i=p[(1+r/100)^3-1]
=1600[(1+5/100)^3-1]
252.2

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Mukund Manohar   7 years AGO

Let P = Rs 100
SI = Rs 40
Rate = (SI *100)/(P*T) = 4000/800 = 5%p.a.
Amount after 3 years = 100{1+ (5/100)}^3
= Rs 1852.2
CI = 1852.2 - 1600 = Rs 252.2

Like? Yes | No   

pravallika   7 years AGO

p=100
simple interest= rs.40
rate of interest= 100*40)/(100*8)=5%
now lets fine compound interest of 1600 for 3 years at 5%=1600(1+5/100)^3
ans:252.2

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mohammed fayis   7 years AGO

RI - 5%
1st yr- 80
2nd yr 84
3rd yr 88.2
80+84+88.2

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sujit   7 years AGO

SIMPLE INTEREST=
SUPPOSE I HAVE 100 RS,
then i will get 140 after 8 years..i.e.40 rs more than principle i.e 5% increase in per year,so rate is=5%,

now calculate C.I. for 3 years at the rate of 5%

CI for 1st year=1600*5/100=80;
similaraly for 3 year=252.2 rs

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ABHISHEK KUMAR   7 years AGO

Because rate of that amount is 5℅ so after calculation is simple like compound interest formula.

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Aakash kesarwani   7 years AGO

let the principal amt be x
so simple interest = 0.4*x
0.4*x=(x*R*8)/100
solving above equation we get,
R= 5%

C.I= p[(1+R/100)^n-1]
C.I=1600[(1+5/100)^3 -1]

solving above we get
C.I=252.2 Answer

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Siva   7 years AGO

I= [P(1+(r/n))^nt]-P
= [1600(1+(5/100)^3]-1600
=252.2

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sanju   7 years AGO

Let P=100
SI=40
R=100*SI/(PT)
R=5%
Amount=P(1+5/100)^3
Amount-P=252.2

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SATHEESH V   7 years AGO

40P/100=PTR/100
TR=40
R=40/8=5%

Compound interest=P(1+R/100)^3-P
C.I=1600(1+5/100)^3-1600
=1600(21/20)^3-1600
=1852.2-1600
C.I=252.2

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DIVYANSHU SHEKHAR   7 years AGO

let P=100 SI=Rs40 and T=8 yrs
rate=(100*40)/(100*8)=5%p.a
C.I=1600{(1+5/100)^3-1}=Rs 252.2

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Ajay Sharma   7 years AGO

since amount increased after 8 years is 40%
let 100 be priciple and time = 8
then amount=140=(100*r*8)/100
so,rate is 5%
by compound interest p=1600
r=5
t=3
so,amount = 252.2

Like? Yes | No   

Basant Bothra   7 years AGO

Let,P =100
So, R=40*100/100*8
R=5%.
Now, C.I=1600(1+5/100)^3
C.I=1852.2
Total interest=(1852.2-1600)=252.2

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Chinmay Swarup Chiranjeevi   7 years AGO

through simple interest formula rate is 5% p.a .then using compound interest formula we get the answer.

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Mukesh Kapoor   7 years AGO

Increase of 40% in 8 years will be on 5% of simple interest.
compound interest formula
A= P(1+r/n)^n*t
A= 1600(1+0.05/1)^3
= 1852.2
Compound interest = 1852.2-1600=252.2

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sruthi pujari   7 years AGO

rate of interest =5% since 40x=x*8*r
1600 after years of compound interst
1st year= 5% of 1600=80
2nd year=5% of (1600+80)=80+4=84
3rd year=5% of (1600+80+80+4)=80+4+4+0.2=88.2
total=252.2

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FFETS   7 years AGO

Simple rate of interest is 5%

From that, we can calculate Total amount with 5% compound interest after three years and thereby the interest by subtraction initial amount from total accumulated amount.

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RAJ   7 years AGO

140=100+8R
R=5%
1600(1+5/100)^3-1600=252.2

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TANIYA ROY   7 years AGO

Let the amount for si be x thn amount will be x+.40x=7x/5
7x/5=x+(x*r*8/100)=>r=5%
amount for ci=1600(1+5/100)^3=1852.2
the answer is 1852.5-1600=252.5

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amit kumar   7 years AGO

Let p =principal
principal (after 8 years)=1.4p
intrest (after 8 years)=0.4p
intrest (after 1 year)=0.4p/8=0.05p
so, rate per year (r) =5%
let CI be compound intrest
Amount after 3 years (A)= 1600*(1+0.05)^3=1852.208
so, CI=A-1600= RS 252.208

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gubba ranjith kumar   7 years AGO

S.I: P*T*R/100: X*8*R/100=40X/100
=>R=5
C.I=1600*5(1+105/100+(105/100)(105/100))/100
=252.2

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Shravya   7 years AGO

If the amount is 100 then interest becomes 5 and calculate CI for 1600 at 5% interest for 3 years ..it is 252.2

Like? Yes | No (1)  

DHANANJAY KUMAR   7 years AGO

Let 100 be the amount then interest is 40 % increase
r=(40*100)/(100*8)=5
compound interest = 1600(1+5/100)^3 -1600=252.2
so option 4 is answer

Like? Yes | No (1)  

23 Jan 2017 Sequence

What is the 9th term of below series?
6, 15, 35, 77, 143, .....

OPtion

1) 221
2) 323
3) 437
4) 657
5) 899
6) 223
7) 321
8) 473
9) 667
10)889

Solution

First 10 Prime Nos.:
2 3 5 7 11 13 17 19 23 29
Nth term of Series is formed by multiplication of nth*(n+1)th prime numbers
2*3, 3*5, 5*7 .....and so on
9th Term would be = 23*29 = 667

Option 9)

Correct Option: 9 Best Solution (30)

Baishali Roy   7 years AGO

6,15,35,77,143,___,___,___,___.
Now,
6=2*3
15=3*5 (1st number to be multiplied is 2nd multiplied digit of previous number and the 2nd number to be multiplied is a prime number)
35=5*7
77=7*11
143=11*13
Then,
6th no=13*17
7th no=17*19
8th no=19*23
9th no=23*29=667 (Opt. 9) (Ans).

Like? Yes (9) | No (2)  

div   7 years AGO

product of prime no. sequence
6->2*3
15->3*5
35->5*7
.
.
23*29->667

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Dr.Dipin Singh   7 years AGO

multiplication of 9th and 10 th prime number
i.e. 23*29=667

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MP    7 years AGO

29x23=667
product of consecutive prime numbers.

Like? Yes (1) | No (1)  

VIKAS BAIRWAL   7 years AGO

it follows the series of (3*2, 5*3, 7*5, 11*7, 13*11,........and so on.) so according to this series the 9th digit will be (29*23) that is equal to 667

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vemula haritha   7 years AGO

6=2x3,15=3x5,35=5x7,.....continues i.e product of consecutive prime numbers so product of 23x29=667 which is the 9th term

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srivatsan   7 years AGO

3*2=6
3*5=15
5*7=35
11*7=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667 the product of two consecutive prime numbers is the concept used here .
The ninth term is 667

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sanju   7 years AGO

Product of Consecutive Prime Numbers
2*3=6
3*5=15
5*7=35
7*11=77
11*13=143

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Aakash kesarwani   7 years AGO

In the series each number is the product of its consecutive prime no. as given below,
2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=664 which is the 9th term in the series. Answer

Like? Yes | No (1)  

THOTA VIJAYA   7 years AGO

2X3 =6
3X5 =15
5X7=35
7X11=77
11X13=143
13X17
17X19
19X23
23X29=667

Like? Yes | No (1)  

Neeraj   7 years AGO

this series is the product of two consecutive prime number
prime number are 2 3 5 7 11 13 17 19 23 29
2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667

Like? Yes | No (1)  

Ansh   7 years AGO

The given series is of the form = 2*3, 3*5, 5*7, 7*11---------
as we see tha every no. in the series is the producct of two consecutive prime no's hence if we go over them we get the ninth term as (23*29) which is eq. to 667

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DHANANJAY KUMAR   7 years AGO

In this series is a multiplication of two consecutive prime number from starting
prime numbers are 2,3,5,7,11,13,17,19,23,29....
Here, 2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=196
17*19=323
19*23=437
23*29=667
so ans is 667 and option is (9)

Like? Yes | No (1)  

Saraswat Rit   7 years AGO

3*2=6
5*3=15
7*5=35
11*7=77
13*11=143
similarly 29*23=667

Like? Yes | No (1)  

Rakesh   7 years AGO

2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
like these are prime numbers
so 9th term is 23*29=667
so opt is 9

Like? Yes (1) | No (2)  

DIVYANSHU SHEKHAR   7 years AGO

2*3=6
3*5=15
5*7=35
7*11=77
........
23*29=667

Like? Yes | No (2)  

Anandita Rani   7 years AGO

6 = 2*3
15 = 3 * 5
35 = 5 * 7
77 = 7 * 11
143 = 11 * 13
221 = 13 * 17
323 = 17 * 19
437 = 19 * 23
667 = 23 * 29

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Dharmendra kumar   7 years AGO

divide next term by previous term....
you got the pattern....

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Chinmay Swarup Chiranjeevi   7 years AGO

product of consecutive prime numbers starting from 2,3,5,7....

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RAJ   7 years AGO

2*3=6,
3*5=15
5*7=35
.
.
.
.
.
.
.
.
23*29=667(Answer)

Like? Yes | No (2)  

SORNA KAMALAM S   7 years AGO

2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667

Like? Yes | No (2)  

Pragati Rode   7 years AGO

Series having the pattern that product of prime number

First element = 2*3 = 6
second element = 3*5 = 15
Third element = 5*7 = 35
Fourth element =7*11= 77
Five element =11*13 = 143
six element =13*17 = 221
Seventh element =17*19= 323
Eighth element =19*23 = 437
Nineth element =23*29 = 667
so option is 9

Like? Yes | No (2)  

arvind rathod   7 years AGO

2*3=6
3*5=15
5*7=35
7*11=77
11*13=143
13*17=221
17*19=323
19*23=437
23*29=667
These r the consecutive prime numbers
Hence 9th number is 667

Like? Yes | No (2)  

Bhushan   7 years AGO

Multiply prime numbers
2*3, 3*5, 5*7 , 7*11, 11*13 and so on 9th term is 23 * 29

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sachidanand yadav   7 years AGO

6=2 * 3
15=3 * 5
35=5 * 7
77=7 *11
143=11*13
221=13*17
323=17*19
437=19*23
667=23*29

Like? Yes | No (2)  

sruthi pujari   7 years AGO

Product of successive primes 2*3;3*5 in this way 9th term is 23*29 =667

Like? Yes | No (3)  

shraboni   7 years AGO

2×3=6
3×5=15
5×7=35
7×11=77
11×13=143
13×17=221
in this order if we continue then at the 9th term we get 23×29 which is equals to 667
and the no we multiply each time must be a odd one
so I multiply 3 ,5, 7 ,11 ,13 ,17, 19 ,23 ,29

Like? Yes | No (3)  

SATHEESH V   7 years AGO

2*3 , 3*5 , 5*7 , 7*11 , 11*13 , 13*17 , 17*19 , 19*23 , 23*27,...............
23*27=667

Like? Yes | No (3)  

MOHAMMED JAFFAR   7 years AGO

Product of consecutive prime numbers...

1st term 2x3 = 6
2nd term 3x5 = 15
3rd term 5x7 = 35
4th term 7x11 = 77
5th term 11x13 = 143
6th term 13x17 = 221
7th term 17x19 = 323
8th term 19x23 = 437
9th term 23x29 = 667

Option (9)

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Sunil kumar   7 years AGO

multiple of two prime no.
2*3=6
3*5=15
5*7=35
......
..
..
23*29=667

Like? Yes | No (3)  

20 Jan 2017 Product of numbers

In binary system decimal numbers are represented as
0=0000 0000,
1=0000 0001,
2=0000 0010,
3=0000 0011
4=0000 0100 and so on

What is the resultant decimal number produced by multiplication of following 2 binary numbers (1011
1101) and (0110 0010)?

OPtion

1) 18022
2) 18122
3) 18222
4) 18322
5) 18422
6) 18522
7) 18622
8) 18722
9) 18822
10)18922

Solution

Let’s convert these numbers into decimal first
1011 1101 = 1*2^7 + 0*2^6 + 1*2^5 + 1*2^4 + 1*2^3 + 1*2^2 + 0*2^1 + 1*2^0 = 128+0+32+16+8+4+0+1 = 189
Similarly,
0110 0010 = 0*2^7 + 1*2^6 + 1*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 1*2^1 + 0*2^0 = 0+64+32+0+0+0+2+0 = 98

Product of 189*98 = 18522
Option 6)

Correct Option: 6 Best Solution (16)

G.S.Kantharao   7 years AGO

10111101=128+32+16+8+4+1=189
01100010 = 64+32+2=98
189*98 =18522
Hence the right option is 6.

Like? Yes (8) | No   

Pragati Rode   7 years AGO

convert number to decimal
1011 1101 ==> 189
0110 0010 ==> 98
multiplication of 189 * 98 = 18522
so option 6

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Neeraj   7 years AGO

10111101*01100010=100100001011010
which is binary of 18522

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Rakesh   7 years AGO

10111101 is binary number it converts decimal its value 189
01100010 its binary number converts decimal its value is 98
so multiplication of 189*98
value 18522
so opt is 6

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Deep   7 years AGO

first decimal number is 189 and second one is 98 so 189*98 = 18522

by following 1 2 4 8 16 32 64 128 so on

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Baishali Roy   7 years AGO

In decimal (1011 1101)=189
In decimal (0110 0010)=98
So in decimal--> (1011 1101)*(0100 0010)= (189*98)=18522 (Opt. 6) (Ans).

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Dharmendra kumar   7 years AGO

1st no - 189
2nd no - 98
so product of two above no - 18522

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sachidanand yadav   7 years AGO

=>(2^7*1 + 2^6*0 + 2^5*1 + 2^4*1 + 2^3*1 + 2^2*1 + 2^1*0 + 2^0*1) * (2^7*0 + 2^6*1 + 2^5*1 + 2^4*0 + 2^3*0 + 2^2*0 + 2^1*1 + 2^0*0)
=>189*98=18522

Like? Yes | No   

DHANANJAY KUMAR   7 years AGO

10111101 is a binary number and its decimal value is 189
and 01100010 is a also a binary number and its decimal value is 98
then multiplication of the numbers is 189*98= 18522

Like? Yes | No   

Dhanraj Wanjare   7 years AGO

Change binary to decimal first....

1011 1101 = 1*2^7 + 0*2^6 + 1*2^5 + 1*2^4 + 1*2^3 +
1*2^2 + 0*2^1 + 1*2^0;
=128 + 0 + 32 + 16 + 8 + 4 + 0 + 1;
= 189

0110 0010 = 0*2^7 + 1*2^6 + 1*2^5 + 0*2^4 + 0*2^3 +
0*2^2 + 1*2^1 + 0*2^0;
= 0 + 64 + 32 + 0 + 0 + 0 + 2 + 0;
= 98;

(1011 1101) * (0110 0010) = 189 * 98;
= 18522;
so Answer 6) :- 18522

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Sreevidya   7 years AGO

decimal number of first binary no is=189
second no is:98
multiplication is :18522

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Tapas Budhani   7 years AGO

Firstly we will convert given binary numbers into coreesponding decimal.
So, (1011 1101)2=(189)10
(0110 0010)2=(98)10
And then simply multiply numbers i.e
189×98=18522

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qwertyqaz   7 years AGO

there are two method to do this question
1) convert both to decimal then multiply
2) multiply as it is (you can multiply hem in the same way we multiply decimal numbers)

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sumit mohan   7 years AGO

we can convert the given binary number into decimal and then we'll get 189 and 98 respectively. multiply both number the result would be 18522

Like? Yes | No (1)  

Ansh   7 years AGO

(10111101) is 189
(01100010) is 96
hence there product is 18522

Like? Yes | No (1)  

Anandita Rani   7 years AGO

by Multiplying both binary , we get :-
100100001011010
now , convert this binary no to decimal
we get :- 18522

Like? Yes | No (2)  

19 Jan 2017 Work Done

Ram and Rahim each working alone can do a work in 22 and 33 days respectively. They started the work together but one day Rahim left the work in between and Ram finished the remaining work in 11 days. For how many days Rahim had worked for?

OPtion

1) 6 days
2) 6.1 days
3) 6.2 days
4) 6.3 days
5) 6.4 days
6) 6.5 days
7) 6.6 days
8) 6.7 days
9) 6.8 days
10)6.9 days

Solution

Ram's one day's work=1/22
Rahim's one day's work=1/33
In 11 days Ram worked =11/22 = 1/2
So Ram and Rahim together completed 1/2 work
(Ram+Rahim)'s one day's work= (3+2)/66 = 5/66
5/66 work is done by Ram and Rahim together in 1 day
1 work is done by Ram and Rahim together in 66/5 days
1/2 work is by Ram and Rahim together in 1/2*(66/5) days = 33/5 days = 6.6 days
Option 7)

Correct Option: 7 Best Solution (22)

G.S.Kantharao   7 years AGO

Ram,Rahim can do indepently=22,33 days respectively.
In 1day they can do 1/22,1/33 respectively.
Left over work finished by Ram in 11days.
Part of the work done by Ram is= 1*11/22= 1/2
So together worked 1/2 of the work.
Together's work in1 day = (1/22) + (1/33) = (3+2)/66 = 5/66
1/2 of the work they can do in =
(66/5)*(1/2) = 6.6.
Hence the right option is 7.

Like? Yes (3) | No   

Mukund Manohar   7 years AGO

Let Rahim worked for x days
Ram + Rahim 1 day's work = 1/22 + 1/33 = 5/66
(5/66)*x + (1/22)*11 = 1
=> (5x + 33)/66 = 1
=> x = 33/5
=> x = 6.6
Rahim worked for 6.6 days

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Devendra Marghade   7 years AGO

Let Ram and Rahim works for x days and then Rahim left and remaining work is done by Ram in 11 days, then x[(1/22) + (1/33)] + 11*(1/22) = 1
=> (5x+33)/66 = 1
=> x = 33/5 = 6.6

Like? Yes | No   

Dharmendra kumar   7 years AGO

let rahim left the work after x days....
so according to question...
x ( 1/22 + 1/33 ) + 1/22 = 1

so we get x = 6.6

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Siva   7 years AGO

[(1/22)+(1/33)]x+(1/2)=1
[(1/22)+(1/33)]x =1/2
(5/66)x=1/2
X=6.6

Like? Yes | No   

Dr.Dipin Singh   7 years AGO

Ram completed 11/22 work i.e. 1/2 work alone.
1/2 work was completed by Ram & Rahim together in (66/5)*(1/2)=33/5=6.6 days.
So Rahim worked for 6.6 days.

Like? Yes | No   

Sujata   7 years AGO

In one day, Ram and rahim can do (1/22+1/33) of work,
so, in x day they can do x*1/22+1/33)(of work,
that equals 5*x/66
now, this form direct relationship, i.e
11 = 22*(1-5*x/66)
or, 11 = 22-5*x/3
or, x=6.6 days

Like? Yes | No   

Ansh   7 years AGO

Let the total work be 66 units
Speed of Ram = 66/22 = 3 units/day
Speed Of rahim = 66/33 = 2 units/day
Work done by Ram in 11 days = 3*11 = 33 units
Now the work done by ram and rahim together = 66-33 = 33units
No. of days rahim worked = 33/(2+3) = 6.6

Like? Yes | No   

PRAGATHI G   7 years AGO

ram-- a, raahim-- b
a can do in 22 days --- 1/22 per day
b can do in 33 days --- 1/33 per day
they work together for x days
let total work be 1
a did work alone for 11 days
therefore a work in 11 days is 11/22
hence
(x/22)+(x/33)+(11/22)= 1
solving .. we get x = 6.6

Like? Yes | No   

Anandita Rani   7 years AGO

ram and rahim 1 day work = 5/66 days
work done by ram in 11 days = 11/22 days = 1/2 days
remaining work = 1- 1/2 = 1/2
thus,
1/2 work done in 1 * 66/ 5 * 1/2 = 33/5 = 6.6 days
hence , rahim had worked for 33/5 days

Like? Yes | No   

Abhishek Gupta   7 years AGO

Let B left the work in x day
(A + B)'s 1 day's work = (1/22 + 1/33) = 5/66
Work done by A and B in x days = 5x/66
Remaning work = (1- 5x/66)
Now, 1/22 work is done in 1 day
1-5x/66 work will be done by a in 11days
x = 33/5 = 6.6 days

Like? Yes | No   

nilay gandhi   7 years AGO

ram one day work =1/22, rahim one day work=1/33 and rahim work for X days then ,X(1/22+1/33) + 11(1/22)=1. so X=6.6

Like? Yes | No   

Athulya   7 years AGO

Ram-->22
Rahim-->33 so taling LCM we get 66
in one day Ram--> 3 units
Rahim-->2 units
Total units 66
Ram works alone for 11 days--->33units
remaining--->33units
one day Ram+Rahim=5 units
5 units in one day
so 33 units can be done in 6.6 days

Like? Yes | No   

Saraswat Rit   7 years AGO

ram alone does 1/22 of work. rahim alone does 1/33 of work. together they do 5/66 of work. if rahim left working on 'x' days. then the equation becomes (5x/66)+(11/22)=1
so the answer comes x=6.6 days

Like? Yes | No   

Baishali Roy   7 years AGO

Ram works for one day 1/22 of whole work.
Rahim works for one day 1/33 of whole work.

So, let rahim works for x days before he left.
So, {x*(Ram's work+Rahim's work)}+{11*(Ram's work)}= Whole work=1

Therefore, x*(1/22+1/33)+11*1/22=1
Sol. of x=6.6 (Ans).

Like? Yes | No   

Udayabhanu   7 years AGO

ram's work = (x+11)/22

Rahim's work = x/33

so [(x+11)/22] + (x/33) =1

On solving

x=6.6

Like? Yes | No   

amit kumar   7 years AGO

Let the rahim work =x days, then ram work =x+11 Per day work by ram=1/22,per day work by rahim=1/33 therefore,x/33+x+11/22=1 on, solving this we get x=6.6 days

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Rakesh   7 years AGO

they doing total work in 66units
ram can do 1day work in 3 units
rahim 1day work in 2 units
ram is working 11 days so ram can do in 33 units
remaining 33 units they both can do
ram and rahim both 1day work 5 units so 6.6 days they complete remaining work
so ans is 7

Like? Yes | No   

urvara   7 years AGO

together they can work in 1 day = 5/66 work
let x no of days they work together
so remaining work = 1-(5x/66) which is equivalent to work done by ram in 11 days
on equating
got x= 6.6

Like? Yes | No   

DHANANJAY KUMAR   7 years AGO

Ram done work in 1 days is 1/22 parts.
Rahim done work in 1 days is 1/33 parts.
then equation is (1/22+1/33)x+1/22*11=1
so x=6.6 days.

Like? Yes | No   

pradeep   7 years AGO

ram one day work =3x
rahim one day work= 2x
both one day work= 5x
total work = 66
rahim left 11 days before then ram 11 days work will be = 11*3= 33
reaminingwork done by both = (66-33)/5 = 6.6

Like? Yes | No   

boby   7 years AGO

each day they complete 7.5757 percnt of work, so with in 6.6 days they complete 50 percent of the work

Like? Yes | No   

18 Jan 2017 Rank of word

Rank of the word NEIGHBOUR in the dictionary of words formed by the letters of the word NEIGHBOUR

OPtion

1) 208926
2) 208924
3) 208940
4) 208944
5) 208945
6) 208946
7) 206946
8) 209948
9) 209945
10)209946

Solution

No alphabets are repeated, arranging letters in alphabetical order: BEGHINORU

Words starting with Alphabet B = 8!
Words starting with Alphabet E = 8!
Words starting with Alphabet G = 8!
Words starting with Alphabet H = 8!
Words starting with Alphabet I = 8!
Words starting with NB = 7!
Words starting with NEB = 6!
Words starting with NEG = 6!
Words starting with NEH = 6!
Words starting with NEIB = 5!
Words starting with NEIGB = 4!
Words starting with Alphabet NEIGHBOR = 1
And next word is NEIGHBOUR
Sum of all words = 5*8! + 7! + 3*6! + 5! + 4! +2 = 208946
Option 6)

Correct Option: 6 Best Solution (6)

G.S.Kantharao   7 years AGO

The word Neighbour is =(5*8!)+(7!)+(3*6!)+(5!)+2=208946 rank.Hence my option is 6.

Like? Yes (2) | No   

ankit sharme   7 years AGO

first of all this dictionary contains all the words weather it has some meaning or not,
so first we set the ranking of n by ehich we ll get how many words are present in the dictionary started with n .. and by proper location of all alephabet in neighebour we can find the rank of neighbour by following the above algo

Like? Yes (1) | No   

suraj kumar   7 years AGO

n+e=19 increment by 1=20
next,skip the next letter i
g=7 incremented by 1 and it becomes 8 like wise h=9
hence we need to find o and u
so 208946

Like? Yes | No   

Mukund Manohar   7 years AGO

Rank of the word NEIGHBOUR in the dictionary of words formed by the letters of the word NEIGHBOUR
= 5*8! + 1*7! + 3*6! + 1*5! + 1*4! + 1*1! + 1
=201600 + 5040 + 2160 + 120 + 24 + 1 + 1 = 208946

Like? Yes | No   

SORNA KAMALAM S   7 years AGO

B,_,_,_,_,_,_,_,_ 8!
E,_,_,_,_,_,_,_,_ 8!
G,_,_,_,_,_,_,_,_ 8!
H,_,_,_,_,_,_,_,_ 8!
I,_,_,_,_,_,_,_,_ 8!
N,B,_,_,_,_,_,_,_ 7!
N,E,B,_._._._,_,_ 6!
N,E,G,_,_,_,_,_,_ 6!
N,E,H,_,_,_,_,_,_ 6!
N,E,I,B,_,_,_,_,_ 5!
N,E,I,G,B,_,_,_,_ 4!
N,E,I,G,H,B,O,R,U 1
N,E,I,G,H,B,O,U,R 1
208946

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MOHAMMED JAFFAR   7 years AGO

Arrange the Letter "NEIGHBOUR" in Alphabetical order "BEGHINORU"

B=8!=40320
E=8!=40320
G=8!=40320
H=8!=40320
I=8!=40320
[N]
[N]B=7!=5040
[NE]
[NE]B=6!=720
[NE]G=6!=720
[NE]H=6!=720
[NEI]
[NEI]B=5!=120
[NEIG]
[NEIG]B=4!=24
[NEIGH]
[NEIGHB]
[NEIGHBO]
[NEIGHBO]R=1!=1
[NEIGHBOU]
[NEIGHBOUR]

Now Add All

=40320+40320+40320+40320+40320+5040+720+720+720+120+24+1+(1)

Answer = 208946

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17 Jan 2017 Sequence

Next Number of Series
91, 364, 819, 1456, ?

OPtion

1) 2075
2) 2175
3) 2275
4) 2050
5) 2150
6) 2250
7) 2025
8) 2125
9) 2150
10)2215

Solution

Nth term of Series is formed by (7*n)*(13*n) where n = 1, 2, 3, 4, 5
So for n = 5 i.e. 5th term = 7*5*13*5 = 2275

Option 3)

Correct Option: 3 Best Solution (39)

Mukund Manohar   7 years AGO

91,364,819,1456,__
1st term * 2^2 = 2nd term
1st term * 3^2 = 3rd term and so on
91 * 2^2 = 91 * 4 = 364
91 * 3^2 = 91 * 9 = 819
91 * 4^2 = 91 * 16 = 1456
91 * 5^2 = 91 * 25 = 2275

Like? Yes (1) | No   

A.P.Singh   7 years AGO

91,364,819,1456.. ??
91*1=91
91*(2)^2=364
91*(3)^2=819
91*(4)^2=1456
91*(5)^2=2275

Like? Yes (1) | No   

G.S.Kantharao   7 years AGO

91,364,819,1456.....=7*13,7*52,7*117,7*208....Hence the next one should be a multiple of 7.
In the given options 2275 only can be written as 7*325.(as a multiple of 7)
Hence my choice is 3

Like? Yes (1) | No   

Sakthivel   7 years AGO

91*4
91*9
91*16
91*25

Like? Yes (1) | No   

Ramgopal   7 years AGO

91* 1^1, 91 * 2^2, 91 * 3^2, 91* 4^2, 91 * 5^2
91, 364, 819, 1456, 2275

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sachchida nand singh   7 years AGO

91*1=91
91*(1+3)
91*4+5
91*9+7
91*(16*9)=2275

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Vivek Agarwal   7 years AGO

364-91=273, 819-364=455, 1456-819=637
455-273=182, 637-455=182
so constant difference
637+182=819
and 1456+819=2275

Like? Yes | No   

himanshu kumar   7 years AGO

91*4=364
91*9=819
91*16=1456
91*25=2275

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Dharmendra kumar   7 years AGO

this pattern following....
10^2 - 3^2 , 20^2 - 6^2 , 30^2 - 9^2 , 40^2 - 12^2 , 50^2 - 15^2
so ans is 2275

Like? Yes | No   

Pragati Rode   7 years AGO

first element = 91 = 10^2 - (3*1)^2
second element = 364 = 20^2 - (3*2)^2
third element = 819= 30^2 - (3*3)^2
fourth element =1456 = 40^2 - (3*4)^2
so required number is = 50^2 - (3*5)^2=2500-225 = 2275
so option is 3

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Abhishek Gupta   7 years AGO

91 * 1 = 91
91 * 2^2 = 364
91 * 3^2 = 819
91 * 4^2 = 1456
91 * 5^2 = 2275

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Siva   7 years AGO

9×10+1=91
9×40+4=364
9×90+9=819
9×160+16=1456
9×250+25=2275

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MOHD FARHAN   7 years AGO

Answer
91×4=364
91×9=819
91×16=1456
91×25=2275
Thus answer is 2275

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Sujata   7 years AGO

It can be seen that, the first number 91 is formed using 3*3 and 1, similarly,
364 = 6*6 and 4 (1+3)
819 = 9*9 and 9 (4+5)
1456 = 12*12 and (9+7= 16) and ( 144+1 and 6 is 1456)
So the last one is,
(15*15 = 225 ) and ( 16+9= 25 and 225+2 and 5 is 2275) so option is 3

Like? Yes | No   

Ansh   7 years AGO

The no. is of the form ab... where a= a^2 (a=3,6,9,12.....)
while b=square of real no's...
combining there two we get the ans which is 2275

Like? Yes | No   

Veera Vignesh   7 years AGO

91*2^2=364
91*3^2=819
91*4^2=1456
91*5^2=2275

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Ajay Sharma   7 years AGO

91*1=91
91*4=364
91*9=819
91*16=1456
so series of second term in multiplication is= 1,4,9,16,?
hence next term is 25
==> 91*25=2275

Like? Yes | No   

SATHEESH V   7 years AGO

91*(1^2)=91
91*(2^2)=364
91*(3^2)=819
91*(4^2)=1456
91*(5^2)=2275

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Athulya   7 years AGO

Step 1-->364 - 91 =273, 819 - 364=455 ; 1456 - 819 = 637
Step 2--->455 - 213=182 ; 637 - 455=182
therefore--> 637 + 182 = 819
1456 + 819=2275

Like? Yes | No   

Neeraj   7 years AGO

91
91*2^2=364
91*3^2=819
91*4^2=1456
91*5^2=2275

Like? Yes | No   

pujithabollareddy   7 years AGO

9*1=91,9*[1+3]=364,9*[1+3+5]=819,9*[1+3+5+7@]=1456,9*[1+3+5+7+9]=2275
The no multipled is appended in units place

Like? Yes | No   

Dhaneshwar Prasad   7 years AGO

91=3^2_1^2
364=6^2_2^2
819=9^2_3^2
1456=12^2_4^2
2275=15^2_5^2
ans = 2275

Like? Yes | No   

SORNA KAMALAM S   7 years AGO

91*1*1=91
91*2*2=364
91*3*3=819
91*4*4=1496
91*5*5=2275

Like? Yes | No   

boby   7 years AGO

the second number is obtained by multyplyng the number with 2 square and the third by 3 square and so on...

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sravya   7 years AGO

91*4=364
91*9=819
91*16=1456
91*25=2275
we are multiplying 91 with square roots of 1,2,3,4,5

Like? Yes | No   

Aishwarya Jaiswal   7 years AGO

all the no.s in series are divisible by 91 i.e, first term of the series and option 3 i.e, 2275 is also divisible by 91. so, that one is the correct answer.

Like? Yes | No   

Lakshmi Narayanan.k   7 years AGO

91,364,819,1456
91*4=364
91*9=819
91*16=1456
91*25=2275

Like? Yes | No   

Aravindhalochanan   7 years AGO

seq
91*4=364
91*9=819
91*16=1456

we take
9-4=5
16-9=7

next no will be 9
16+9=25

so 91*25=2275

Like? Yes | No   

Deep   7 years AGO

simply multiply 91 with 2^2 then 3^2 , 4^2 and finally 5^2 =25 with 91 we get 2275

Like? Yes | No   

Divya   7 years AGO

5-3 for first would
9×3=27
1×5=5
hence ans is 2275

Like? Yes | No   

Quazi Mohammadi   7 years AGO

91*(1^2)=91*1=91
91*(2^2)=91*4=364
91*(3^2)=91*9=819
91*(4^2)=91*16=1456
91*(5^2)=91*25=2275

Like? Yes | No   

Anandita Rani   7 years AGO

13 * 7 = 91
13 * 28 = 364
13 * 63 = 819
13 * 112 = 1456
13 * 175 = 2275

Like? Yes | No   

HARSHIT GUPTA   7 years AGO

9*1=9(90+1=91)
9*4=36(360+4=364)
9*9=81(810+9=819)
9*16=144(1440+16=1456)
9*25=225(2550+25=2275)

Like? Yes | No   

Chirag Kothari   7 years AGO

91*4
91*9
91*16
91*25

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Pulok Barik   7 years AGO

(9*9)+(1*1+10)=91
(18*18)+(2*2+10)=364
(27*27)+(3*3+10)=819
(36*36)+(4*4+10)=1456
(45*45)+(5*5+10)=2275

Like? Yes | No   

Diksha negi   7 years AGO

364 - 91 = 3*91
819 - 364 = 5*91
1456 - 819 = 7*91
x - 1456 = 9*91
x = 811+1456
=2275

Like? Yes | No   

raghav   7 years AGO

91*1=91
91*4=364
91*9=819
91*16=1456
91*25=2275

Like? Yes | No   

shilpa   7 years AGO

1^2*91=91
2^2*91=364
3^2*91=819
4^2*91=1456
5^2*91=2275

Like? Yes | No   

Shrishti Jain   7 years AGO

The difference between the previous two numbers is added with the previous number and 182.For e.g. the difference between 1456 and 819 is 637.To obtain the next term we will add 637 with 182 and 1456 and the answer that is obtained is 2275.

Like? Yes | No   

16 Jan 2017 Rate of Interest

At what rate of compound interest per annum will a sum of Rs. 3200 become Rs. 3698 in 2 years?

OPtion

1) 6.75 %
2) 6.8 %
3) 6.9 %
4) 7.0 %
5) 7.1 %
6) 7.2 %
7) 7.3 %
8) 7.4 %
9) 7.5 %
10)None of these

Solution

Amount = P (1 + r/100)^T
P=3200, T= 2, A = 3698, r=?
3698 = 3200(1+r/100)^2
=> 1849/1600 = (1+r/100)^2
=> 1+r/100 = 43/40
=> r = 7.5%
Option 9)

Correct Option: 9 Best Solution (13)

G.S.Kantharao   7 years AGO

A=P(1+R/100)^n
(1+R/100)² = 3698/3600 = 1.155625
(1+R/100) = √1.15562-5 =1.075
R/100 = 1.075-1 = 0.075
R=7.5
Hence the right option is 9.

Like? Yes (2) | No   

aakash singhal   7 years AGO

a=p(1+r/100)^n
a=3698,p=3200,n=2
3698=3200(1+r/100)^2
3698/3200=1+r/100
answers=7.5

Like? Yes | No   

amit kumar   7 years AGO

p=3200.A=3698 apply formula A=P(1+R/100)^n where n =2 and r= rate of intrest putting the values we get R=7.5%

Like? Yes | No   

Mukund Manohar   7 years AGO

Let the rate be R%
3200(1 + R/100)^2 = 3698
=> 107.5 - 100 = R
Rate = 7.5%

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Nitish kesarwani   7 years AGO

P =3200 A =3698 yrs = 2
For A =p*(1+r/100)^2
So r= 7.5

Like? Yes | No   

Pabitra Paul   7 years AGO

we have to find r
so 3200(1+r/100)^2=3698
after calculating we get r =7.5%

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Athulya   7 years AGO

P=3200 A=3698 CI=3698 - 3200=498
check with the options
taking 7.5% its for 2 years so using the formula
x + y +xy/100 --> 7.5+7.5+7.5*7.5/100
15.0+56.25/100--->15.0+0.56-->15.56%
15.56% of 3200 gives 497.92 approx 498

Like? Yes | No   

Ajay Sharma   7 years AGO

In compound interest==> amount=principal(1+r/100)^n
here amount=3698,principle=3200
n=time and r=rate
so, 3698=3200(1+r/100)^2
solving this we get,r=15/2==7.5%

Like? Yes | No   

phani krishna   7 years AGO

A=P(1+r/100)^n
on applying this formula we get r=7.5%
where A=3698, P=3200, n=2yrs

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MOHAMMED JAFFAR   7 years AGO

Deposited Amount 3,200

1st Year = 3,200*7.5% (240) = 3,440
2nd Year = 3,440*7.5% (258) = 3,698

Compound Interest Rate per Annum is 7.5%

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UTTAM SINGH   7 years AGO

if in one year the interest is increases by 7.5% then it becomes=3200*7.5/100=3440
then if we will calculate the interest on it in one year then it will be=3440/100=34.40
now by giving 7.5% interest it becomes=7.5*34.40=258
therefore total in two year =3440+258=3698

Like? Yes | No   

Tapas Budhani   7 years AGO

Its Simple ,
Formula for compound interest is
A=P (1+r)^nt
Future amount A is given in que ie 3698
P=3200
t=2 years
n=1 since it is compounded annually .
So we can evaluate the value of r through above eq

Like? Yes | No   

Rakesh   7 years AGO

sum(1+rate/100)^time=amount
3200(1+rate/100)^2=3698
rate=7.5

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13 Jan 2017 Percentage

I bought 5 Rasgullas, 7 Ladoos and 4 Samosas. Preeti bought 6 Rasgullas, 8 Samosas and 14 Ladoos for an amount which was half more than what I had paid.
What percent of the total amount paid by me was paid for the Rasgullas?

OPtion

1) 50.0 %
2) 52.5 %
3) 55.0 %
4) 57.5 %
5) 60.0 %
6) 62.5 %
7) 65.0 %
8) 67.5 %
9) 70.0 %
10)72.5 %

Solution

Answer: 62.5 %

Assume R is Cost of one Rasgulla, L is cost of one Ladoo& S is cost of one Samosa
Let total cost of 5 Rasgullas, 7 Ladoos and 4 Samosas be X
5R+7L+4S=X -> Equation (i)

Preeti has bought 6 Rasgullas, 8 Samosas and 14 Ladoos at 1.5X cost (half more than mine)
So, 6R+14L+8S=1.5X -> Equation (ii)

Multiplying Equation (i) by 2 and subtracting 2nd equation from it:
10R+14L+8S=2X
06R+14L+8S=1.5X
--------------------------------
4R = 0.5X
=> R = 0.5X/4

Total amount paid by me for Rasgulla = 5R= (0.5X/4) * 5 = 2.5X/4
Percent of the total amount paid by me for the Rasgulla = {(2.5X/4)/X}* 100 = 62.5%

Option 6)

Correct Option: 6 Best Solution (15)

G.S.Kantharao   7 years AGO

Let 5R+4S+7L=P
6R+8S+14L=3P/2
Subtracting Second one from first one R+4S+7L=P/2Subtract third from first =4R=P/2=,>R=P/8
5R=[(5P/8)/P]*100=62.5%
Hence the right option is 6.

Like? Yes (6) | No   

Abhishek Gupta   7 years AGO

Let, the amount paid be x,
5R + 7L + 4S = x
Preeti Amount be
6R + 14L + 8S = x + x/2,
Solving both equations we get,
R = x/8
So the percentage amount the Rasgulla was
(5/8)*100 = 62.50

Like? Yes (1) | No   

Gaurav kumar   7 years AGO

5 Rasgullas+7 ladoos +4 samosas=Rs x....(1)
6 Rasgullas + 14 ladoos + 8 samosas= Rs y...y=1.5x...(2)
also 10 rasgullas + 14 ladoos + 8 samosas=Rs 2x(from1)...(3)
(3)-(2)=4
Rasgullas=0.5x=> 0.625x
% expenditure=0.625x/x*100=6.25%

Like? Yes (1) | No   

SHAH ALAM   7 years AGO

let, price for each rasogolla ladoos and samosa are a,b,c total paid by me is 100 so preeti 150.
5a+7b+4c=100
7b+4c=100-5a
6a+14b+8c=150
6a+200-10a=150
4a=50
5a=62.5

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Dr.Dipin Singh   7 years AGO

6R+8S+14L= 1.5*(5R+7L+4S)
1.5R= 2S+3.5L
3R=4S+7L
8R=5R+4S+7L= x ( say)
5R/x=5/8 = 0.625 means 62.5%.... option 6

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Vijay Kumar Sharma   7 years AGO

let total amount paid by me is 100.
so preeti paid 100*1.5 = 150.
let 5Rasgulla = 5x and 7 ladoos = 7y and 4 samosas = 4y
so, 5x + 11y = 100......(1)
same for preeti
6x + 22y = 150............(2)
by solving eq 1 and 2
x = 12.5
22y = 75
here price paid for 5 rasgulla = 5 * 12.5 = 62.5
total amount was 100 so the percentage paid for rasgullas 62.5 %

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Naveen Singh   7 years AGO

5*r + 7*l +4*s=x
6*r + 14*l +8*s=3x/2
where r=rasgulla l=laddu s=samosa x=total cost
after solving avove two equation we coclude
3*r=7*l + 4*s
by hit and trial method
l=5 s=5 r=15
now % is 75/120 *100=62.5

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Dharmendra kumar   7 years AGO

let i paid for the purchase = x
pretti = 3x/2
if preeti purchase 4 more rusgulaa then she has to pay total 2x.
so for 4 rusgulaa price is x/2.
then for 5 rasgula = 5x/8.
so % of money invested for rosgulaa by me . 5x/8x ×100 =62.5

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madhubala   7 years AGO

5r+7l+4s=p(for me);
6r+14l+8s=p+(p/2)=3p/2;
on solving we get 1r=25/2%
which implies for 5 rasagulas=5*25/2=62.5%

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SORNA KAMALAM S   7 years AGO

5R+7L+4S=x
6R+14L+8S=1.5x
solving ,7L+4S=3R

5R+3R=x
8R=x
5R=(5x/8)
5R=0.625x
IN percentage 62.5%

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Quazi Mohammadi   7 years AGO

Consider
5R+7L+4S=100
6R+14L+8S=150
(since money spent by preeti is half more than mine, therefore 100+(100/2)=150)

Solving these equations, we get
R=12.5
So 5R=62.5

(62.5/100)*100=62.5%

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Mayank Kumar   7 years AGO

5r+7l+4s=A
7l+4s=A-5r

6r+2(7l+4s)=3A/2

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amit kumar   7 years AGO

Let total money paid by me= x then, money paid by preeti=3x/2 also, let cost of of 1 rasgulla=R, cost of 1 ladoo=L cost of 1 samoas=S Total money paid by me 5R+7L+4S=x 3R+2R+7L+4S=x 3R+7L+4S=x-2R --------------------->1 Total money paid by preeti 6R+14L+8S=3x/2 2(3R+7L+ 4S)=3x/2
3R+7L+4S=3x/4 putting value of 3R+7L+4S from eq. 1 x-2R=3x/4 R=x/8 % of total amount paid by me=(5x/8)*100 62.5%

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Ajay Sharma   7 years AGO

let 5rasgullas+7ladoos+4samosas=100 --(equation 1)
then, 6 rasgullas + 8 samosas + 14 ladoos =150 -- (eq.2)
multiplying eq. 1 by 2 and subtracting eq. 2 from it
==> 4rasgullas=50
1 rasgulla = 12.5%
=> 5rasgullas=62.5%

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Mukund Manohar   7 years AGO

Let 5R + 7L + 4S = x ----------(i)
then 6R + 14L + 8S = 3x/2 --------(ii)
Multiplying (i) by 2,& subtracting (ii) from it,we get the cost of 1 Rasgulla = Rs x/8. So cost of 5 Rasgulla = Rs 5x/8
Required %age = (500/8)% = 62.5%

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12 Jan 2017 CODING/DECODING

REYKJAVIK 4032737411
WORCESTERSH 384427524240
MISSISSIPPI 728388993164
CZECHOSLOVA ?

OPtion

1) 540811235368
2) 540821235368
3) 540831235368
4) 540841235368
5) 540851235368
6) 540861235368
7) 540871235368
8) 540881235368
9) 540891235368
10) 540801235368

Solution

Answer : 540861235368

Each alphabet value is coded as below
A= 26, B=25, C=24, D=23, .....Z=1

The final code is generated as = Multiply value of all alphabets + Add Values of all alphabets

For CZECHOSLOVA we have = (24*1*22*24*19*12*8*15*12*5*26) + (24+1+22+24+19+12+8+15+12+5+26) = 540861235368

Option 6)

Correct Option: 6 Best Solution (2)

Mukund Manohar   7 years AGO

Z=1,Y=2,X=3,W=4,V=5,U=6,..............,C=24,B=25,A=26
REYKJAVIK = (R*E*Y*K*J*A*V*I*K) + (R+E+Y+K+J+A+V+I+K)
= (9*22*2*16*17*26*5*18*16) + (9+22+2+16+17+26+5+18+16)
= 4032737280 +131
=4032737411
Similarly, WORCESTERSH = 384427524096 + 144
= 384427524240
MISSISSIPPI = 728388993024 + 140
= 728388993164
CZECHOSLOVA = 540861235200 + 168
= 540861235368

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SHAH ALAM   7 years AGO

calculate the word number from opposite side a then multiply each word.you get the answer like,
C=24,Z=1.......
so answer=24*1*22*24*19*12*8*15*12*5*26=5.40861235*10^11
neglect last 3 number.

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