The present age of a brother is 6 years more than four times the age of his sister. Six years hence, brother’s age will be four years more than thrice the age of the sister. Find the present age of the brother.
Let the sister’s present age be ‘n’ years.
=> brother’s present age = (4n + 6) years
So, according to the question
(4n + 6 + 6) = 3 (n + 6) + 4
=> 4n + 12 = 3n + 22
=> n = 10
Hence, brother’s present age = (4n + 6) = 46 years
Rahul has solved 245 questions in an examination. If he got only ‘0’ marks, then how many questions were wrong when one mark is given for each one correct answer and 2/3 mark is subtracted on each wrong answer.
How much amount would a person receive if he invests a sum of Rs. 12500 at the rate of 6.5% of simple interest for 12 years in a bank. Please note that bank levies a charge of Rs. 175 on every fixed deposit.
Advika's age is 1/6th of her father's age. Advika's father's age will be twice Rahul's age after 10 years. If Rahul's eleventh birthdays was celebrated two years before, then what is Advika's present age.
OPtion
1) 8 years
2) 12 years
3) 11 years
4) 5 years
5) 6 years
6) 9 years
7) 10 years
8) 4 years
9) 7 years
10) None of these
Solution
Let Advika's present age = x
Then, her father's age = 6x
Given that Advika's father's age will be twice Rahul's age after 10 years.
Therefore, Rahul's age after 10 years = (1/2) * (6x + 10) = 3x + 5
Also given that Rahul's eleventh birthday was celebrated two years before. So Rahu;s present age = 11+2
Therefore, Rahul's age after 10 years = 11 + 2 + 10 = 23
If I were again beginning my studies, I would follow the advice of Plato and start with mathematics.
Galileo Galilei
There r few things whch we knw whch r nt capable of mathmatical reasoning nd when these can nt it is a sign dt our knowledge of them is very smal nd confusd nd where a mathmaticl reasing can be had . It is as dark a foly to make use a candle stick as to g