M4maths Previous Puzzles

28 Oct 2011 arrange masterchef

How many words can be formed by using all the letters of the word MASTERCHEF at a time if you have to arrange these letters in the same manner as these letters are arrange in english alphabet?
! represents factorial in options

OPtion

1) 10!
2) 10!/2!
3) 9!
4) 1
5) 10
6) 3
7) 5!
8) 11
9) 5
10) none of these

Solution

Only 1 method is possible on the basis of conditions given
this word is ACEEFHMRST

Correct Option: 4 Best Solution (0)

27 Oct 2011 Fill in the blank

4,2,1,7,6,6,10,10,11,13,14,16,16,?,21

OPtion

1) 17
2) 18
3) 19
4) 16
5) 20
6) 21
7) 14
8) 6
9) 22
10) none of these

Solution

There are 3 sequences
1) 4,7,10,13,16
2) 2,6,10,14,18
3) 1,6,11,16,21
Ans is 18

Correct Option: 2 Best Solution (0)

26 Oct 2011 maximum

The sum of 2 numbers x and y is 10. y(x^2) will be maximum for x = ....

OPtion

1) 2
2) 5/2
3) 10/3
4) 20/3
5) 4
6) 28/3
7) 21/4
8) 6
9) 8
10) none of these

Solution

Given that x+y = 10
For y(x^2) to be maximum we should divide 10 between y and x in such a way that y/1 = x/2 = 10/(1+2)
so x = 20/3, y = 10/3

Correct Option: 4 Best Solution (0)

25 Oct 2011 advertisement

The cost of an advertisement is 5000 rupee/square feet in a news paper. In more than 10 adds, their is a discount of 1000 rupee/add for all the adds after 10 adds. A man wants to use this add facility for 19 adds. Total cost of the adds will be

OPtion

1) 76000
2) 78000
3) 79000
4) 81000
5) 84000
6) 86000
7) 88000
8) 90000
9) 96000
10) none of these

Solution

Cost of first 10 adds = 5000*10 = 50000
cost of next 9 adds = 4000*9 = 36000
so total cost = 86000

Correct Option: 6 Best Solution (0)

24 Oct 2011 sequence

next number of the sequence 3, 6, 10, 16, 26,..... will be

OPtion

1) 28
2) 30
3) 32
4) 35
5) 36
6) 40
7) 44
8) 46
9) 48
10) none of these

Solution

This sequence is formed by two sequences
1) 2, 4, 6, 8, 10, 12
2) 1, 2, 4, 8, 16, 32
adding these two sequences, we get the result

Correct Option: 7 Best Solution (17)

21 Oct 2011 boys and girls

There are 3 boys and 4 girls. We have to arrange any 1 boy at the centre and any 2 girls at corners. In how many methods these persons can be arranged.

OPtion

1) 432
2) 488
3) 512
4) 580
5) 624
6) 725
7) 864
8) 1024
9) 1200
10) none of these

Solution

methods for arranging 1 boy at centre = 3
methods of arranging 2 girls at corner = 4*3 = 12
methods of arranging remaining 4 persons = 4*3*2*1 = 24
so total methods = 3*12*24 = 864

Correct Option: 7 Best Solution (12)

20 Oct 2011 sequence

10, 25, 55, 511, ......

OPtion

1) 637
2) 773
3) 823
4) 875
5) 899
6) 924
7) 970
8) 1040
9) 1123
10) none of these

Solution

10 = 2*5
25 = 5*5
55 = 5*11
511 = 7*73
so next number will be 773

Correct Option: 2 Best Solution (0)

19 Oct 2011 year

What will be the difference of two positive integers for which following condition hold
Product of these integers is equal to the number of days in a normal year.

OPtion

1) 46
2) 49
3) 51
4) 54
5) 56
6) 58
7) 62
8) 66
9) 68
10) none of these

Solution

Factors of 365 = 73 and 5
so difference = 73-5 = 68

Correct Option: 9 Best Solution (7)

18 Oct 2011 proportion

k, k^2, k^3, 8 are four proportional numbers, then k will be

OPtion

1) 8^(3/4)
2) 4^(3/4)
3) 2^(3/4)
4) 8
5) 4
6) 2
7) 1
8) 8^(1/2)
9) 2^(1/2)
10) none of these

Solution

According to the given condition k^2/k = 8/k^3
or k = 8/k^3
or k^4 = 8
or k = 8^(1/4)
or k = 2^(3/4)

Correct Option: 3 Best Solution (27)

17 Oct 2011 Fill the blank

1, ...., 30, 24, 60, 60

OPtion

1) 2
2) 4
3) 5
4) 6
5) 7
6) 8
7) 9
8) 10
9) 12
10) none of these

Solution

1 year = 12 month
1 month = 30 day
1 day = 24 hour
1 hour = 60 minute
1 minute = 60 second

Correct Option: 9 Best Solution (9)