Distribution of letters of the word CALCUTTA is A 2 times, C 2 times, L 1 time, T 2 times, U 1 time
Total 5 letter words having all letters different = 5*4*3*2*1 = 120
Total 5 letter words having 1 letter repeated = 3*(5*4*3*2*1)/2 = 180
Total 5 letter words having 2 letters repeated = 3*(5*4*3*2*1)/2*2 = 90
so total words are 390
The cost of n dozen banana is x rupee more than 100 rupee and the cost of 6n dozen banana is 14x rupee less than 700 rupee. Which of the following is the cost of 1 dozen banana (Given that n and x are positive integers)
let the cost of 1 dozen banana is y rupee
then n*y = 100+x
and 6n*y = 700-14x
take n*y = 100+x from first equation in the second equation, we will get
6(100+x) = 700-14x
or 600+6x = 700-14x
or 20x = 100
or x = 5
on putting x=5, n*y = 100+5 = 105
The sum of 2 numbers is 12, and sum of reciprocals of these numbers is 35th part of the sum of these numbers. Positive difference of the numbers will be
OPtion
1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) data are wrong
9) data are not sufficient to give answer
10) none of these
Solution
x+y=12
and (1/x)+(1/y)=12/35
on solving numbers will be 7 and 5
In an exam total 15 questions are asked. You have to give answer of any 12 questions. Questions are divided in 3 sections. Each section contains 5 questions. You have to solve at least 3 questions from each section. How many methods are possible to give answers of all 12 questions.
Two cases arise
1) solve 3,4 and 5 questions from sections
total methods = 6*(5*4/2*1)*(5/1)*(1)= 300
2) sole 4 from each section
total methods = 5*5*5 =125
so answer = 300+125 = 425
Given that x+y>z, x,y,z are positive integers
then
1) x>z
2) y>z
3) x-y>z
4) xy>=z
5) x/y>
How many of these 5 conditions are definitely true for all values of x,y and z
1 dozen orange weights 1200 gram. If cost of orange in dozen is 60 Rs/Dozen and that in Kg. is 50 Rs/Kg, then profit in purchasing 5 Kg orange taking the price in Dozen as reference price will be