There are 3 tapes in a tank, 2 for filling water and 1 for drain. The first 2 tapes can fill the tank alone in 10 and 12 hours respectively, whereas 8 hours are required to drain all the water by third tape alone.
If we open all the 3 tapes, then hours required to fill the tank completely are
The cost rupee per Kg. of potato, onion, tomato, garlic and ginger are respectively 9, 14, 18, 43 and 35. There are 5 schemes of a shopkeeper, which 1 is relatively most profitable.
n. Potato Onion Tomato Garlic Ginger
1 2 kg 1 kg 1 kg 1/2 kg 100 gm free
2 4 kg 2 kg 1/2 kg 200 gm free 1/2 kg
3 1 kg free 4 kg 1 kg 1/2 kg 1/2 kg
4 4 kg 1 kg free 2 kg 1 kg 1/2 kg
5 6 kg 4 kg 1 kg free 1 kg 1/2 kg
OPtion
1) 1
2) 2
3) 3
4) 4
5) 5
Solution
Bill 1 total purchasing = 71.5 and discount = 3.5 so 3.5/71.5 = 0.048951
Bill 2 total purchasing = 90.5 and discount = 8.6 so 8.6/90.5 = 0.095028
Bill 3 total purchasing = 113 and discount = 9.0 so 9.0/113.0 = 0.079646
Bill 4 total purchasing = 132.5 and discount = 14 so 14/132.5 = 0.105660
Bill 5 total purchasing = 170.5 and discount = 18 so 18/170.5 = 0.105572
What will be the rank of VODAFONE in the dictionary formed by the letters of the word VODAFONE
OPtion
1) 19568
2) 20423
3) 17934
4) 20134
5) 19572
6) 16547
7) 12346
8) 18459
9) data are insufficient
10) none of these
Solution
On arranging letters in order we get
A, D, E, F, N, O, O, V
now make attention on the trick
total possible words = 8*7*6*5*4*3*2*1/2*1 = 20160
so rank = 2520*7 + 360*5 + 120*1 + 24*0 + 6*1 + 2*2 + 1*1 + 1 = 19572
here 2520 is 20160/8 and 7 is the no. of letters before V
360 is 2520/7 and 5 is the no. of letters before O
now O comes twice in the word so
total words for the next step = 360*2
120 is 720/6 and 1 is the no. of letters before D
24 is 120/5 and 0 is the no. of letters before A
6 is 24/4 and 1 is the no. of letters before F
2 is 6/3 and 2 is the no. of letters before O
1 is 2/2 and 1 is the no. of letter before N
Last 1 is necessary to add
the power sequence of 7 is 7, 49, 343, 2401, 16807, 117649
on adding the digits of the numbers we get a sequence
7, 13, 10, 7, 22, 28
so 28 will be the answer.
Marks of Ram = 98 %
so that of Shyam will be 98-1 = 97%
now we have to find the % of difference of marks w. r. t. marks of Shyam it will be 1*100/97 = 100/97 = 1.031
According to formula we know that
a^3+b^3+c^3-3*a*b*c = (a+b+c)(a^2+b^2+c^2-a*b-b*c-c*a)
Here a=99, b=-56, c=-43
so a+b+c = 99-56-43 = 0
hence answer will be 0
so option 10th is correct