This question can be solved by equidistribution of words from every letter symmetrically.
on arranging these 6 letters in english alphabetic order we get
C(1 to 60) E(61 to 120) E(121 to 180) similarly .........
so 146th word would be start from E
next step for next letter
C(61 to 84) E(85 to 108) R(109 to 132) S(133 to 156)similarly .......
so next letter would be S
next step
C(133 to 138) E(139 to 144) R(145 to 150) similarly ...........
so next letter would be R
next step
C(145-146) E(147-148) T(149-150)
so next letter would be C
next step
E(145) T(146)
so next letter would be T
and last letter is E
since 1 mango would be provided to every child necessarily, so we have to distribute remaining 2 mangos to the 4 children. Methods are
1) give both the mango to any 1 child for which there are 4 methods
2) give 1-1 to any 2 children for which there are 6 methods
50 % of 80 % of 100 - 20 % of 60 % of 100 - 32 % of 25 % of 100 - 1/6 of 36 % of 100 = 12
What should be added in the right hand size to make the equation correct
On solving
50 % of 80 % of 100 - 20 % of 60 % of 100 - 32 % of 25 % of 100 - 1/6 of 36 % of 100 = 40 - 12 - 8 - 6 = 14
but RHS is given as 12 so 2 should be added in RHS
The cost of 3 kg potato and 2 kg onion is 72 rupee and that of 4 kg potato and 3 kg onion is 104 rupee.H.C.F. of the cost of 1 kg potato and 1 kg onion is
Total number of the words by the letters of the word
KUNDAN = 6*5*4*3*2*1/2*1=360
Denominator is due to the revision of N twice.
The correct order of these letters in English alphabets is A, D, K, N, N, and U
So rank of KUNDAN = (360/6)*2 + (60/5)*4 + (12/4)*2 + (6/3)*1 + (2/2)*0 + 1
= 120 + 48 + 6 + 2 + 0 +1
= 177
How many words can be formed by the letters of the word "TUESDAY"?
If all the vowels used in the word have to be taken in the order as these letters come in English alphabets.
TUESDAY, total numbers of letters in the word TUESDAY are 7
So numbers of methods to form word are 7*6*5*4*3*2*1/3*2*1 = 840
The denominator is due to the restriction given in the question
Methods for the arrangement of 5 boys = 1*4*3*2*1 = 24, between the boys there are 5 places so methods for the arrangement of 4 girls = 5*4*3*2 = 120
Hence total number of methods = 24 * 120 = 2880