M4maths Previous Puzzles

01 Oct 2009 News channels (Level Hard)

Some TV channels and their codes are given below
TV channel Code
ZEE CINEMA 972
STAR PLUS 4779
DD NATIONAL 292
Then code for SAHARA ONE is

OPtion

1) 3502
2) 393
3) 3052
4) 1436
5) 786
6) 2330
7) 2033
8) 519
9) 617
10) 324

Solution

Code is obtained as follow
ZEE CINEMA becomes ACE EEIMNZ after taking the letters in increasing order
Sum of position of letters according to English alphabet is
(1+3+5)(5+5+9+13+14+26) = (9)(72) hence the code,
Similarly
SAHARA ONE is changed to AAAEHN ORS
after taking the letters in increasing order sum of position of letters according to English alphabet is
(1+1+1+5+8+14)(15+18+19) = (30)(52)

Correct Option: 3 Best Solution (0)

30 Sep 2009 E69 break the code

If R76 = D4
J68 = F8
V123 = E13
Then E69 is

OPtion

1) I21
2) N3
3) D3
4) F5
5) E18
6) K24
7) H23
8) M4
9) J9
10) G8

Solution

R76 = 76/18 (18 is the position of R in English alphabet)
On solving this division problem we get 4 as quotient (D is the fourth letter of English alphabet) and 4 as reminder hence code is D4
Similarly for others.

Correct Option: 8 Best Solution (1)

29 Sep 2009 who is your friend

In a coded language
If "WHAT IS YOUR NAME" - ABH
"HOW ARE YOU" - BG
"WHAT ARE YOUR SUBJECTS" - CHD
Then "WHO IS YOUR FRIEND" is coded as

OPtion

1) DD
2) BDA
3) AD
4) ADD
5) CDH
6) GHA
7) IDH
8) ADB
9) DAD
10) AEC

Solution

In this coded language
WHAT IS YOUR NAME
= 4244 (according to the number of letters used in the corresponding word)
On multiplying these numbers we get 4*2*4*4 = 128
In alphabetic order these are equivalent to A, B, H
Similarly for others

Correct Option: 4 Best Solution (2)

28 Sep 2009 Next Number?

Next number of the sequence 1, 4, 13, 40 ...... will be

OPtion

1) 94
2) 64
3) 49
4) 56
5) 121
6) 157
7) 164
8) 136
9) 78
10) 144

Solution

This sequence is 1, 1+3, 1+3+3^2, 1+3+3^2+3^3, 1+3+3^2+3^3+3^4

Correct Option: 5 Best Solution (0)

25 Sep 2009 coded Language Friday

Code for some names are given below
Name Code
ABHISHEK 38
AKSHAY 35
ARJUN 31
Then code for AMITABH is

OPtion

1) 36
2) 33
3) 35
4) 30
5) 29
6) 32
7) 38
8) 39
9) 40
10) 41

Solution

Position of all the letters used in ABHISHEK are
ONE TWO EIGHT NINE NINETEEN EIGHT FIVE ELEVEN
Total letters used in this expression are 38
In AKSHAY position of all the letters used are
ONE ELEVEN NINETEEN EIGHT ONE TWENTY-FIVE
Total letters used in this expression are 35
In ARJUN position of all the letters used are
ONE EIGHTEEN TEN TWENTY-ONE FOURTEEN
Total letters used in this expression are 31
similarly for AMITABH position of all the letters used are
ONE THIRTEEN NINE TWENTY ONE TWO EIGHT
Total letters used in this expression are 32, hence the code

Correct Option: 6 Best Solution (0)

24 Sep 2009 apply mathematical operation

(16, 8, 36), (28, 11, 48), (12, 7 ,32) are 3 set of integers according to some mathematical operations,
a similar set based on the similar operations are

OPtion

1) (12, 6, 30)
2) (28, 7, 40)
3) (20, 10, 44)
4) (24, 8, 36)
5) (36, 13, 58)
6) (40, 14, 48)
7) (32, 10, 44)
8) (4, 5, 24)
9) (44, 16, 68)
10) (8, 6, 30)

Solution

Formula used to solve a set (a, b, c) is b = [(a/4) + 4] and c = [b*4 + 4]

Correct Option: 8 Best Solution (2)

23 Sep 2009 coded word

If in a coded language 92835 = 6.2
64324 = 8.5
47824 = 7.0
Then 68552 =

OPtion

1. 2.2
2. 1.8
3. 2.3
4. 2.9
5. 1.5
6. 0.8
7. 3.5
8. 4.3
9. 3.7
10. 4.8

Solution

Here 92835 = 9 + 2 – 8 × 3 ÷ 5
= 9 + 2 - 8 ×.6 (according to BODMAS rule)
= 9 + 2 – 4.8
= 11 – 4.8 = 6.2
Similarly for others

Correct Option: 5 Best Solution (0)

22 Sep 2009 new category of English alphabet

All 26 letters A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
in English alphabet are divided into 2 category
If one of the category contains A H M V Z ......etc
And other contains C G J O U ..........
Then which one of the following set contains all the letters of the same category

OPtion

1) E F G T
2) B C I Y
3) C G L T
4) D H M R
5) A K R X
6) A E I N
7) O P U Y
8) I L N R
9) B K W X
10) C F L Y

Solution

In this distribution all the letters having any curved part in it are taken in a category whereas letters
having no curved part are taken in other category
First category contains B C D G J O P Q R S U
Second category contains A E F H I K L M N T V W X Y Z

Correct Option: 6 Best Solution (1)

21 Sep 2009 percent rule

If Suraj obtains 10% marks more then Amit then how many % less marks are obtained by Amit than Suraj.

OPtion

1) 9
2) 9.08
3) 10
4) 9.09
5) 10.01
6) 10.1
7) 9.9
8) 9.8
9) 11
10) 10.9

Solution

Let marks of Amit is x
Then according to given condition marks of Suraj is 1.1x
Difference of marks is 1.1x – x = 0.1x
Hence marks of Amit are (0.1x/1.1x)*100 = 100/11 = 9.09 % less than marks of Suraj.

Correct Option: 4 Best Solution (0)

18 Sep 2009 Break the code

If in a coded language
32+57+48=11/23
27+62+51=26/3
And 19+72+53=33/8
Then 45+99+34=

OPtion

1) 25/13
2) 34/5
3) 18/19
4) 16/9
5) 23/7
6) 34/15
7) 48/23
8) 21/31
9) 21/13
10) 28/13

Solution

Here (32+57+48) is solved in the following manner
First divide 57 by 32, we get 1 and 25 as reminder then divide 48 by reminder we obtain 1 and 23 as
reminder hence the result code is 11/23. Similarly in second case (27+62+51), first divide 62 by 27
we get 2 and 8 as reminder then divide 51 by reminder we obtain 6 and 3 as reminder hence the result code is 26/3, similarly for others.

Correct Option: 5 Best Solution (0)