If a Delhi to Mumbai Rajdhani train running at the speed of 30 m/s and covers 4.2 km long chunk in 7 minutes, then the length of the train is:
OPtion
1) 8.2 km
2) 8.6 km
3) 8.4 km
4) 7.8 km
5) 7.4 km
6) 9.0 km
7) 9.2 km
8) 9.4 km
9) 8.8 km
10) None of the above
Solution
Let the length of the train be y meters.
Time taken by the train to cover (4200+ y) meters at 30m/s in 420 seconds
i.e., distance = speed x time
(4200+y) = 30 x 420
4200+y = 12600
y = 12600 - 4200 m
i.e., y = 8.4 km
Hence the length of the train is 8.4 km
Find the number of tiles, each measuring 20 cm x 14 cm x 6 cm, required to construct a wall 20 m long, 10 m high and 70cm thick. IF 10% of the wall is filled with mortar?
Volume of the wall to be constructed = (2000 x 1000 x 70) cm³
Volume of the tiles = 90% of the volume of the wall
= (90/100 x 2000 x 1000 x 70) cm³
Volume of 1 tile = (20 x 14 x 6) cm³
Hence the numbers of tiles are required
= [ 90/100 (2000x1000x70)/(20x14x6)]
=75000
The average age of a group of 15 players is 23 years. If the age of the coach be included, then the average increases by 6 months. Find the age of the coach.
Total age of 15 Players = 23 x 15 = 345 years
Average age of 15 players and their coach = 23 years and 6 months = 23.5 years
Total age of 15 players and their coach = 23.5 x 16 = 376 years
Hence age of the coach = 376 – 345 = 31 years
Let Namit’s age is X
Then Ankit’s age will be (X – 6)
As given- (X – 6) / X = 6/9
9X – 54 = 6X
3X = 54
X = 18
Hence Ankit’s Age will be = 18-6 = 12 years.
In a km race, Ashok beats Raman by 30 meters or 12 seconds. Find Ashok’s approximate time over the course?
OPtion
1) 10 min.
2) 7 min.
3) 5.5 min.
4) 4.3 min.
5) 6 min.
6) 8.5 min.
7) 7.7 min.
8) 6.46 min.
9) 5.22 min.
10) None of the above
Solution
As given, Raman covers 30 m in 12 seconds.
Raman’s time over the course = 12/30 x1000 = 400 seconds
Ashok’s time over the course = (400 – 12) = 388 seconds = 6.46 minutes
How many seconds will a 468 m long train take to cross a man driving his motor bike at a speed of 39 km/hr in a direction of the moving train if the speed of the is 120 Km/hr.
Let the new S.P. be ₹ x
Then, (100 – loss%) : (1st S.P.) = (100 + gain%) : (2nd S.P.)
(100 – 6) / 1269 = (100 + 6) / x
X = (106 x 1269)/94
X = 134514/94 = ₹1431