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M4maths Previous Puzzles

02 Sep 2022 Mensuration

A cuboidal block of 8 cm x 12 cm x 20 cm is cut into an exact number of equal cubes.The least possible number of equal cubes will be

OPtion

1) 24
2) 18
3) 16
4) 33
5) 32
6) 20
7) 36
8) 30
9) 27
10) None of these
Solution
Volume of block=(8 x 12 x 20) cu.cm = 1920 cu.cm
Side of largest cube = H.C.F of 8,12,20 = 4 cm
Volume of a cube=(4 x 4 x 4)=64 cu.cm
Number of cubes=(1920/64)=30
Correct Option 8)
Correct Option: 8 Best Solution (2)
Dr.Dipin Singh   6 Months AGO
For minimum number of Same size cubes, each side should have maximum possible size.
HCF of 8,12,20 is 4.
So each cube will be 4x4x4.
Number of cubes = (8x12x20) /(4x4x4) = 2x3x5 = 30
Like? Yes (3) | No   
G.S.Kantharao   6 Months AGO
Dimensions 8cm×12cm×20cm
HCF of 8,12,20=4
So number of cubes =2*3*5=30
My option is 8👈
Like? Yes (2) | No   
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01 Sep 2022 Sequence & Series

Find next number of the following series.
4, 9, 12, 16, 20, 23, 28, ?

OPtion

1) 30
2) 32
3) 35
4) 31
5) 37
6) 36
7) 33
8) 29
9) 34
10) None of these
Solution
There are two alternate series: 4, 12, 20, 28, .. (Increase by 8)
And 9, 16, 23, ? (Increase by 7)
Hence next term is 23+7=30
Correct Option 1)
Correct Option: 1 Best Solution (2)
Dr.Dipin Singh   6 Months AGO
Two series are mixed
4,12,20,28
9,16,23,30

So next number is 30
Like? Yes (1) | No   
M J SHIVAYOGI   6 Months AGO
difference of 7 between 2nd 4th 6 th and adding 7 to 8th gives 30.
Like? Yes | No   

31 Aug 2022 Time and Work

If Anil does 40% of certain work and Sunil the remaining, it takes 41 days to complete the work but when Sunil does 65% of the same work and Anil the remaining, it takes 41½ days to finish the work. Anil is more efficient than Sunil by

OPtion

1) 14.28%
2) 44.44%
3) 57.14%
4) 66.66%
5) 33.33%
6) 22.22%
7) 71.43%
8) 28.57%
9) 38.89%
10) None of these
Solution
Working individually, let Anil and Sunil takes x and y days respectively.
Then Anil's 1 day work=1/x and Sunil's 1 day work=1/y
As per given conditions: (40/100) / (1/x) + (60/100) / (1/y) = 41
⇒ 2x + 3y = 205 ---(i)
And (65/100) / (1/y) + (35/100) / (1/x) = 83/2
⇒ 7x + 13y = 830 ---(ii)
Solving Eqn (i) & (ii), we get x=35, y=45
Efficiency of work of Anil and Sunil = 1/35 : 1/45 = 9 : 7
.'. % Anil is more efficient than Sunil = [(9-7)/7]*100 = 28.57%
Correct Option 8)
Correct Option: 8 Best Solution (2)
Dr.Dipin Singh   7 Months AGO
If their per day work is x and y respectively, then
0.4/x +0.6/y=41
0.35/x+ 0.65/y =41.5
Solving these equations, we get
x/y = 1.2857
Which means
x is 28.57 % more than y.
Like? Yes (2) | No   
RAMADURAI NATESAN   7 Months AGO
let A take a days to complere work alone and
S.. b days ............................................. Given:
0.4a + 0.6b=41 AND 0.35a + 0.65b = 41.5 .Solving ,
a = 35 and b = 45.Anil can do 1/35 0f work in 1 day and
Sunil 1/45. 45/35 = 1.2857. Anil is 28.57 % more efficient
Like? Yes (1) | No   

30 Aug 2022 Profit & Loss

A shopkeeper list a product at 25% above the cost price. If he offers two successive discounts of 16% and 8%, he loose Rs. 51 in this transaction. When he sells the same product at a straight discount of 24%, there is

OPtion

1) 7.5% Loss
2) 10% Gain
3) 5% Gain
4) 12% Loss
5) 7.5% Gain
6) 6.25% Loss
7) 2.5% Gain
8) 5% loss
9) 10% Loss
10) None of these
Solution
Let CP=Rs. x, then list price=Rs. 1.25x
SP after successive discounts of 16% and 8% = 1.25x*0.84*0.92 = 0.966x
Loss = CP - SP = x - 0.966x = 44
0.034x = 51
x = 1500
.'. List Price=1.25*1500=1830
SP after single discount of 24% = 1830*0.76 = 1425
Loss = 1500 - 1425 = 75
Percentage Loss = (75/1500)*100 = 5%
Correct Option: 8 Best Solution (0)

29 Aug 2022 Boat and Streams

A boatman rows upstream from point X after 28 seconds he rows back towards point X and in 28 seconds he reaches at point Y. If distance between X and Y is 784 meters, find speed of current?

OPtion

1) 10 m/s
2) 14 m/s
3) 12 m/s
4) 18 m/s
5) 21 m/s
6) 8 m/s
7) 6 m/s
8) 9 m/s
9) 7 m/s
10) None of these
Solution
X -------- (28 sec) Upstream ----------
Y -----------(784 m)----------- X
-------------------------------(28 sec) Downstream --------------------
Let speed of the boat in still water=a m/s and speed of stream=b m/s
Distance covered in downstream in 28 sec - Distance covered in upstream in 28 sec = 784 meters
⇒ (a+b)*28 - (a-b)*28 = 784
28a + 28b - 28a + 28b = 784
56b = 784
b = 14 m/s
Correct Option 2)
Correct Option: 2 Best Solution (1)
Dr.Dipin Singh   7 Months AGO
(b+s)*28 -(b-s) *28 =784
56s=784
s=14m/sec
Like? Yes (2) | No   

26 Aug 2022 Ratio & Proportion

If a:b=9:7, b:c=5:8 and 5a –3b + 4c = 344, then the value of c is

OPtion

1) 45
2) 35
3) 65
4) 28
5) 56
6) 70
7) 54
8) 42
9) 63
10) None of these
Solution
5a - 3b + 4c = 344
As we require value of c, therefore expressing a and b in terms of c in above equation.
Given, a/b=9/7, b/c=5/8 ⇒ a : b : c = (9x5) : (7x5) : (8x7) = 45 : 35 : 56
.'. a/c=45/56 ⇒ a=45c/56 and b=5c/8
5a –3b + 4c = 5x(45c/56) - 3x(5c/8) + 4c = 344
Solving, we get c=56
Correct Option 5)
Correct Option: 5 Best Solution (2)
Dr.Dipin Singh   7 Months AGO
As per given statement,
a:b:c =45:35:56
Hence
5*45x -3*35x +4*56x=344
x=1
Hence c=56
Like? Yes (4) | No   
RAMADURAI NATESAN   7 Months AGO
Given :7a = 9b 0r 56a = 72b. 8b = 5c or 72b = 45c.
a = 45c/56 and b = 45c/72c = 5c/8.
Substituting a and b in terms of c in given equation,
c( 225/56 + 4 - 15/8 ) = 344. Solving c = 56.
Like? Yes (1) | No   

25 Aug 2022 Simple & Compound Interest

A sum increases by 48% in 6 years at certain rate of simple interest per annum, then how much years are required to approximately double the amount at the same annual rate of compound interest ?

OPtion

1) 6
2) 5
3) 6.5
4) 7.5
5) 10
6) 9
7) 12
8) 8
9) 15
10) None of these
Solution
Let rate=R% and principal amount=P, then with simple interest amount after 6 years = P + (PxRx6/100) = 1.48P
⇒ R=8%
With coumpound interest sum after 'n' years = P[1 + 8/100]^n = 2P
(27/25)^n = 2
⇒ n=9
Correct Option 6)
Correct Option: 6 Best Solution (1)
RAMADURAI NATESAN   7 Months AGO
S.I. = PNR/100. Given : S = P+i = p+6PR/100 = 1.48P.
Solving , R = 8
A = P(1+R/100)^N. P(1+8/100)^N =2P. (1.08)^N=2.
N = 9
Like? Yes | No   

24 Aug 2022 Geometry

If PQR is a triangle such that PQ=15 cm, PR=15 cm, QR=18 cm, then altitude to side PR will be

OPtion

1) 29 cm
2) 15 cm
3) 14.5 cm
4) 25.4 cm
5) 21.6 cm
6) 20.4 cm
7) 14.4 cm
8) 12.5 cm
9) Cann't be determined
10) None of these
Solution
As two sides PQ, PR are same, it is an isosceles triangle, so altitude to QR will also be perpendicular bisector of QR.
Let PS be the bisector of QR, then QS=SR=9 cm.
By Pythagoras theorem, PS² + SR² = PR²
PS² = 15² - 9² = 144
PS = 12
Now, Area of the triangle = (1/2)* base*height = (1/2)*QR*PS = (1/2)*18*12 = 108 cm²
As we have to find the altitude to PR, Area=(1/2)*PR*(Altitude to PR, say h)
108 = (1/2)*15*h
h = 14.4 cm
Correct Option 7)
Correct Option: 7 Best Solution (1)
RAMADURAI NATESAN   7 Months AGO
let altitude to side PR meet PR at S , forming 2 rt.angled Triangles PQS and. RQS.
RS^2 +QS^2 = 324 AND PS^2 + QS^2 = 225.
RS^2 - PS^2 = 99= (RS + PS )(RS - PS) = 15 ( RS - PS).
RS - PS = 6.6. RS = 10.8 QS^2 = 324 - (10.8)^2 = 207.36.
Q = 14.4
Like? Yes | No   

23 Aug 2022 Profit & Loss

A man bought a chair and a table. If he sold the chair at 10 % loss and the table at 7.5 % gain, he would not lose anything; but if he sold the table at 5% loss and the chair at 5% gain, he would lose Rs. 15 in the bargain. The total cost price of a chair and a table is

OPtion

1) Rs. 1200
2) Rs. 4200
3) Rs. 2400
4) Rs. 2100
5) Rs. 1800
6) Rs. 1500
7) Rs. 3000
8) Rs. 2700
9) Rs. 900
10) None of these
Solution
Let CP of a chair=C and a table=T
0.9C + 1.075T = T+C ⇒ 3T - 4C = 0 ---(i)
0.95T + 1.05C = T+C-15 ⇒ T - C = 300 ---(ii)
Solving eqn. (i) & (ii), we get T=1200, C=900
CP of a table and a chair = 1200+900 = 2100 Rs.
Correct Option 4)
Correct Option: 4 Best Solution (3)
Dr.Dipin Singh   7 Months AGO
.075t=0.1 c
c=0.75t .... (1)

0.05t-0.05c=15
t-c=300
t-0. 75t=300
t=1200, c=900
t+c=2100
Like? Yes (4) | No   
G.S.Kantharao   7 Months AGO
Let C.P of Chair and Table are =C,T
Now 0.9C+1.075T=C+T
0.1C=0.075T=>C=0.75T
Now 0.95T+1.05C=C+T-15
0.05T-0.05C=15
0.05T-(0.05*0.75)T=15
0.05T-0.0375T=15=>T=15/0.0125=150000/125=₹1200
Chair=1200*0.75=900
So total price=₹1200+₹900=₹2100
So my option is 4👈
Like? Yes | No   
RAMADURAI NATESAN   7 Months AGO
Given: 0.9c + 1.075t = c + t and 1.05c + 0.95t = c + t - 15.
Solving, c = 900 and t = 1200. c + t = 2100
Like? Yes | No   

22 Aug 2022 Time and Work

B alone can complete the work in 45 days. A is 35% more efficient than B. If A and B together started the work but after 18 days A and B left. Then C alone completed the remaining work in 3 days. If they get Rs. 9750 as wages for the whole work, then share of C in wages is

OPtion

1) Rs. 7200
2) Rs. 5400
3) Rs. 3000
4) Rs. 4050
5) Rs. 4500
6) Rs. 2700
7) Rs. 2025
8) Rs. 2350
9) Rs. 3600
10) None of these
Solution
B's 1 day work = 1/45
A's 1 day work = (135/100)*(1/45) = 3/100
18 days work of A & B = 18*(1/45 + 3/100) = 47/50
Remaining work = 1 - 47/50 = 3/50
As C takes 3 days to complete the remaining work .'. C's 1 day work = (3/50)/3 = 1/50
Ratio of efficiencies of A, B & C respectively = 3/100 : 1/45 : 1/50 = 27 : 20 : 18
Ratio of share of A, B & C respectively = 27*18 : 20*18 : 18*3 = 162 : 120 : 18
C's share in total wages of Rs. 9750 = [18/(162+120+18)]*9750 = 585 Rs.
Correct Option 10) None of these
Correct Option: 6 Best Solution (0)
Page: 349
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