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Genpact Placement Papers with Solution : Solved Question

(#M40041191) GENPACT QUESTION Number Series Keep an EYE

9,19,40, ? ,146

Asked In Genpact Kasthuri Monika (11 years ago)

Solved MANISH KUMAR SINGH Read Solution (4)

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(#M40005418) GENPACT QUESTION Problem on ages Keep an EYE

Tina is 3 years younger than Tom. The ages are in the ratio 2:3. Find their ages.

Asked In GENPACT (13 years ago)

Solved Vignesh Read Solution (6)

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(#M40005417) GENPACT QUESTION Problem on ages Keep an EYE

Ana is 5 years more than Jack. The sum of their ages is 29. Find the ages of Ana and Jack.

Asked In GENPACT (13 years ago)

Solved Vignesh Read Solution (4)

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(#M40005404) GENPACT QUESTION Problem on ages Keep an EYE

The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A. 8, 20, 28 B. 16, 28, 36

C. 20, 35, 45 D. None of these

Solution

Let present ages are x,y and z so according to the given condition x+y+z-3*8 = 56 so x+y+z = 80, only B satisfies the condition

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Asked In GENPACT (13 years ago)

Solved Read Solution (2)

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(#M40005239) GENPACT QUESTION Series Keep an EYE

Look at this series: XXIV, XX, __, XII, VIII, ... What number should fill the blank?

A. XXII B. XIII
C. XVI D. IV

Solution

these numbers are 24,20,16,12,8 so blank number = 16 = XVI

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Asked In GENPACT (13 years ago)

Solved Read Solution (1)

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(#M40005230) GENPACT QUESTION Series Keep an EYE

Look at this series: 70, 71, 76, __, 81, 86, 90, 91, ... What number should fill the blank?

A. 70 B. 71
C. 80 D. 96

Asked In GENPACT (13 years ago)

Solved romi Read Solution (4)

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(#M40005228) GENPACT QUESTION Series Keep an EYE

Look at this series: 664, 332, 340, 170, ____, 89, ... What number should fill the blank?

A. 85 B. 97
C. 109 D. 178

Asked In GENPACT (13 years ago)

Solved romi Read Solution (8)

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(#M40004941) GENPACT QUESTION Problem on numbers Keep an EYE

If the sum of two numbers is 22 and the sum of their squares is 404, then the product of the numbers is
A. 40
B. 44
C. 80
D. 88

Solution

according to the given conditions x+y = 22
and x^2+y^2 = 404
now (x+y)^2 = x^2+y^2+2xy
so 22^2 = 404 + 2xy
so xy = 80/2 = 40

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Asked In GENPACT (13 years ago)

Solved Read Solution (2)

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(#M40004818) GENPACT QUESTION Rectangle Keep an EYE

If a rectengale length and width are both doubled,by what percent is the rectangle area increase?

Solution

let length and width are l and b
so area = lb
now after doubling both we will get area = 2l*2b = 4lb
so % increase = 400-100 =300

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Asked In GENPACT (13 years ago)

Solved Read Solution (1)

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