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Genpact Placement Papers with Solution Page 7

(#M40005412) GENPACT QUESTION Problem on ages Keep an EYE

Nona is one-third as old as her mother. Five years ago, she was only one-fifth of the age of her mother. How old is Nona now?

Asked In GENPACT (13 years ago)

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(#M40005411) GENPACT QUESTION Problem on ages Keep an EYE

A man is 4 years older than his wife and 5 times as old as his son. When the son was born, the age of the wife was six-sevenths that of her husband's age. Find the age of each.

Asked In GENPACT (13 years ago)

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(#M40005410) GENPACT QUESTION Problem on ages Keep an EYE

Bob is one third the age of his father. In 12 years he will be half the age of his father. How old is each now?

Asked In GENPACT (13 years ago)

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(#M40005409) GENPACT QUESTION Problem on ages Keep an EYE

Pol is 10 years younger than Greg. In 7 years, he will be 10 years more than one half as old as Greg. Find their age at present.

Asked In GENPACT (13 years ago)

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(#M40005408) GENPACT QUESTION Problem on ages Keep an EYE

In this algebra age word problem we have "A man is 27 years older than his son and 10 years from now, he will be twice as old as his son. how old is each now?"

Asked In GENPACT (13 years ago)

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(#M40005407) GENPACT QUESTION Problem on ages Keep an EYE

Jason is 4 times older than Bob at present. 8 years ago Jason was 12 times older. How old are Jason & Bob?

Asked In GENPACT (13 years ago)

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(#M40005406) GENPACT QUESTION Problem on ages Keep an EYE

Bob is currently twice as old as Steve. Twenty years ago Bob was 6 times as old as Steve. What are their current ages?

Asked In GENPACT (13 years ago)

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(#M40005405) GENPACT QUESTION Problem on ages Keep an EYE

A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

A. 32 years B. 36 years

C. 40 years D. 48 years

Asked In GENPACT (13 years ago)

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(#M40005404) GENPACT QUESTION Problem on ages Keep an EYE

The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A. 8, 20, 28 B. 16, 28, 36

C. 20, 35, 45 D. None of these

Solution

Let present ages are x,y and z so according to the given condition x+y+z-3*8 = 56 so x+y+z = 80, only B satisfies the condition

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Asked In GENPACT (13 years ago)

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(#M40005403) GENPACT QUESTION Problem on ages Keep an EYE

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

A. 5 : 2 B. 7 : 3

C. 9 : 2 D. 13 : 4

Asked In GENPACT (13 years ago)

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