If (+,-,*,/) denoted by (*,/,+,-) then find the value of (27*5+69/9-3+5)-(2+3-6*5/3)

Vaibhav Mishra   11 years AGO

(27+(5*69)-((9/3) *5))/((2*3/6) +5-3)
now apply the BODMAS rule
we will get
(27+345-15)/3
119 Ans

Like? Yes (9) | No   

sonali randave   11 years AGO

From condition,
e.g will be
(27+5*69-9/3*5)/(2*3/6+5-3)
= (27+5*69-3*5)/(2*1/2+2)
= (27+345-15)/(3)
= 119

Like? Yes (6) | No (2)  

utkarsh bisht   11 years AGO

simply replace all the values followed by the bodmas rule
hence new equation will seem like it
(27+5*69-9/3*5)/(2*3/6+5-3)
(27+345-15)/(3)=357/3=119

Like? Yes (4) | No (1)  

SOMASHEKAR MACHANI   11 years AGO

acc to given rules,
the given expression can b written as follows
(27+5*69-9/3*5)/(2*3/6+5-3)
= 357/3 (using bodmas rule)
= 119
hence option 3 is the answer

Like? Yes (5) | No (2)  

nishant kumar   11 years AGO

after applying the given condition the equation becomes
(27+5*69-9/3*5)/(2*3/6+5-3)
(27+345-15)/(1+5-3)
357/3
=119
hence the answer is 119

Like? Yes (3) | No (1)  

Mariappan   11 years AGO

By given Condition, the equation will become

(27+5*69-9/3*5)/(2*3/6+5-3)=119

Like? Yes (3) | No (1)  

devendra kumar gond   11 years AGO

equivalent of(27*5+69/9-3+5)-(2+3-6*5/3) is(27+5*69-9/3*5)/(2*3/6+5-3)=357/3=119

Like? Yes (3) | No (1)  

richa ahuja   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
solve by applying BODMAS rule
ans=119

Like? Yes (2) | No   

Jasmine Khan   11 years AGO

after replacing the signs we get
(27+5*69-9/3*5)/(2*3/6+5-3)
=(27+345-15)/(1+5-3)
=357/3
=119

Like? Yes (2) | No   

Chandni Maurya   11 years AGO

ans=(3). 119
after replacing (+,-,*,/) by(*,/,+,-)
(27+5*69-9/3*5)/(2*3/6+5-3)
=(27+345-15)/(6/6+2)
=357/3
=119

Like? Yes (2) | No   

ashiwani kumar singh   11 years AGO

ans=119;

Like? Yes (2) | No   

Raju Sharma   11 years AGO

+=*
-=/
*=+
/=-
(27*5+69/9-3+5)-(2*3-6*5/3) then expression
(27+5*69-9/3*5)/(2*3/6+5-3)
then solve ans =119

Like? Yes (2) | No   

AISHWARYA   11 years AGO

(27+(5*69)-9/3*5)/((2*3)/6+5-3)=119

Like? Yes (2) | No   

Vaibhav Deshmukh   11 years AGO

(27*5+69/9-3+5)-(2+3-6*5/3)
According to new system
= (27+5*69-9/3*5)/(2*3/6+5-3)
= (27+345-15)/(1+5-3)
= 357/3
= 119

Like? Yes (2) | No   

sridevi   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
Solving by BODMAS,
we will get 119.

Like? Yes (2) | No   

Ankit Shukla   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
(27+345-3*5)/(1+5-3)
357/3=119
so ans =119

Like? Yes (2) | No   

komal   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)

357/3 => 119

Like? Yes (2) | No   

sintu jain   11 years AGO

bodmas rule

Like? Yes (2) | No   

sivaraman   11 years AGO

If (+,-,*,/) denoted by (*,/,+,-)
after the change sum you get

(27+5*69-9/3*5)/(2*3/6+5-3)
(27+345-3*5)/(6/6+5-3)
(27+345-15)/(1+5-3)
(27+330)/(1+2)
(357)/(3)
119

Like? Yes (2) | No   

Sagar Jinachandran   11 years AGO

(+-*/)=(*/+-)
(27*5+69/9-3+5)-(2+3-6*5/3)
=(27+5*69-9/3*5)/(2*3/6+5-3)
=(27+345-15)/3
=(372-15)/3
=(357)/3
=119
option 3

Like? Yes (2) | No   

KALIDASS   11 years AGO

The changed expresion is:
(27+(5*69)-((9/3)*5))/((2*(3/6))+5-3)
(27+345-15)/3=119

Like? Yes (2) | No   

k.ushanandhini   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
(27+5*69-3*5)/(2*1/2+5-3)
357/3=119

Like? Yes (2) | No   

Soumya Sharma   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
= 119
apply BODMAS

Like? Yes (2) | No   

saranya   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
Evaluate according to the precedence /,*,_ & +
so the answer is 119

Like? Yes (2) | No   

Yallapu Uday tarun kumar   11 years AGO

in the resultant place
* at + and / at - and + at * and - at /
and apply "bodmas" rule.
(27+5*69-3*5)/(2*3/6+5-3)=119

Like? Yes (2) | No   

Gokul Krishnan   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)=119

Like? Yes (2) | No   

Devendra Marghade   11 years AGO

(27*5+69/9-3+5)-(2+3-6*5/3)
=(27+5*69-9/3 *5)/(2*3/6 +5-3)
=357/3
=119

Like? Yes (2) | No (1)  

Mayuresh Srivastava   11 years AGO

(27+5*69-(9/3)*5)/(2*(3/6)+5-3)
=357/3=119

Like? Yes (2) | No (1)  

sudipta sadhukhan   11 years AGO

(27*5+69/9-3+5)-(2+3-6*5/3)
will be replaced by (27+5*69-9/3*5)/(2*3/6+5-3)
using bodmas rule we get 119

Like? Yes (2) | No (1)  

Bingumalla Abinay   11 years AGO

change symbols and do calculation according to BODMAS rule

(27+66*5)/3=9+22*5=9+110=119

Like? Yes (2) | No (1)  

sanjay kumar saha   11 years AGO

357/3=119

Like? Yes (2) | No (1)  

gowthaman   11 years AGO

we have the problem
(27*5+69/9-3+5)-(2+3-6*5/3)
now the conditions are we have to inter change the operations like (+,-,*,/)as (*,/,+,-)
now we get the problem in the form of
(27+5*69-9/3*5)/(2*3/6+5-3)
= 357/3
=119

Like? Yes (2) | No (1)  

ShAg   11 years AGO

replacing the signs, our eqn comes out to be:
(27+5*69-9/3*5)/(2*3/6+5-3) = 119

Like? Yes (1) | No   

abhishek ranjan   11 years AGO

(27*5+69/9-3+5)-(2+3-6*5/3)
putting all assumption
=> (27*5+69/9-3+5)-(2+3-6*5/3) =(27+5*69-9/3*5)/(2*3/6+5-3)
applying BODMAS rule RHS equals to----
=> (27+5*69-3*5)/(2*0.5+5-3)
=>(27+345-15)/(1+5-3)
=>(372-15)/(6-3)
=> (357/3)
=> 119
answer is option (3).119

Like? Yes (1) | No   

ravi singh   11 years AGO

answer is 119

the actual form of queation is

(27+5*69-9/3*5)/(2*3/6+5-3)

by solving we get 357/3=119

hence option 3 is right answer

Like? Yes (1) | No   

TEJ PRAKASH TEWARI   11 years AGO

We can write it
(27+5*69-9/3*5)/(2*3/6+5-3)
=357/3
=119

Like? Yes (2) | No (1)  

Madhu pericherla   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
(27+345-15)/(1+5-3)
357/3
119

Like? Yes (1) | No   

manasa epuru   11 years AGO

given exp becomes (27+5*69-9/3*5)-(2*3/6+5-3)
on solving we get 119

Like? Yes (1) | No   

vaibhav rajhns   11 years AGO

changed signs
(27+5*69-9/3*5)/(2*3/6+5-3)
=(27+345-15)/(1+5-3)
=119

Like? Yes (1) | No   

FAISAL RIZWAN   11 years AGO

The solution is like that
+ -> *
- -> /
* -> +
/ -> -

Now after changing the sign (27+5*69-9/3*5)/(2*3/6+5-3)
=>357/3=119
so option 3 is correct i.e 119

Like? Yes (2) | No (1)  

Undapalli Soujanya   11 years AGO

simple mathematical calculation

Like? Yes (1) | No   

malarvezhi.m   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
Solving by BODMAS,
we will get 119.

Like? Yes (1) | No   

shamily.k   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
Solving by BODMAS,
we will get 119.

Like? Yes (1) | No   

Anuja Subramanian   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
Solving by BODMAS,
we will get 119.

Like? Yes (1) | No   

Monisha   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)
Solving by BODMAS,
we will get 119.

Like? Yes (1) | No   

LOGAN WOLVERINE   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3);
354/3;
119;
option 3.

Like? Yes (1) | No   

Kumar Ankit   11 years AGO

After changing the operator as per in the question
we get the equation
(27+5*69-9/3*5)/(2*3/6+5-3)
By using BODMAS rule we get
357/3= 119

Like? Yes (1) | No   

praneeth   11 years AGO

as per the given conditions the given prblm becomes (27+5*69-9/3*5)/(2*3/6+5-3)=357/3=119

Like? Yes (1) | No   

Abhishek   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)=119

Like? Yes (1) | No   

galibpasha   11 years AGO

just simply followed the prosidure in order but actually i got the answer as 129.6

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GOKULVASANTH   11 years AGO

=(27+(5*69)-((9/3)*5))/((2*(3/6))+5-3)

Like? Yes (1) | No   

Ananya Gupta   11 years AGO

its simple calculation...now the expression will turn as
(27+5*69-9/3*5)/(2*3/6+5-3)
=119

Like? Yes (1) | No   

patil hareesh   11 years AGO

(27+5*69-9/3*5)/(2*3/6+5-3)

using bodmas simplify it will get 357/3=119

Like? Yes (1) | No   

saurabh saraff   11 years AGO

by BODMAS rule we solve.

Like? Yes (1) | No (1)  

Manuj Vishnoi   11 years AGO

change the sign than calculate by bodmas rule

Like? Yes (1) | No (1)  

Shubham Kumar   11 years AGO

simply change the symbols as prescribed and solve by using BODMAS

Like? Yes (1) | No (1)