What is the next number of the following sequence 6,120,504,1320,.....

Rajasekhar Reddy   11 years AGO

The sequence is follows as
2^3-2 = 6;
5^3-5 = 120;
8^3-8 = 504;
11^3-11 = 1320;
and the next number is
14^3-14 = 2730;

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chandana   11 years AGO

first number in series is 6=1*2*3
second number in the series is 120=4*5*6
third number in the series is 504=7*8*9
fourth number in the series is 1320=10*11*12
fifth number in the series=13*14*15=2730(option 2)

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Pallavi Chand   11 years AGO

1*2*3=6
4*5*6=120
7*8*9=504
10*11*12=1320
13*14*15=2730

Like? Yes (4) | No (2)  

saurabh anand   11 years AGO

Here, Every number is multiplication of next 3 consequetive starting from 1...
6 = 1*2*3
120 = 4*5*6
504 = 7*8*9
1320 = 10*11*12
so, next number will be... 13*14*15 = 2730..

Like? Yes (2) | No   

pavan   11 years AGO

finding the difference between the num still we get constant difference
6 120 504 1320
114 384 816
270 432
162
so then by adding 162+432+816+1320=2730

Like? Yes (3) | No (1)  

Gunaseelan   11 years AGO

Given Pattern is n*(n+1)*(n+2)
6= 1*2*3
120 = 4*5*6
504 = 7*8*9
1320 = 10*11*12
Answer is 13*14*15 = 2730

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Pratiksha Gupta   11 years AGO

6*1=6
12*10=120
18*28=504
24*55=1320
Similarly,
30*91=2730

Here, 6, 12, 18, 24 and 30 are multiple of 6
And the difference of
1 & 10
28 & 10
55 & 28
30 & 91
is the multiple of 9 i.e 9, 18, 27, 36....

Like? Yes (7) | No (5)  

Shubham Saxena   11 years AGO

6*1=6
12*10=120
18*28=504
24*55=1320
Similarly,
30*91=2730

Here, 6, 12, 18, 24 and 30 are multiple of 6
And the difference of
1 & 10
28 & 10
55 & 28
30 & 91
is the multiple of 9 i.e 9, 18, 27, 36....

Like? Yes (3) | No (1)  

Shubham Saxena   11 years AGO

6*1=6
12*10=120
18*28=504
24*55=1320
Similarly,
30*91=2730

Here, 6, 12, 18, 24 and 30 are multiple of 6
And the difference of
1 & 10
28 & 10
55 & 28
30 & 91
is the multiple of 9 i.e 9, 18, 27, 36....

Like? Yes (2) | No   

~Sandeep~   11 years AGO

nth term = 3n*(3n-1)*(3n-2)
5th Term = (3*5) * (3*5-1) * (3*5-2) = 2730

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Paranthamakannan   11 years AGO

6=6
6*5*4=120
7*8*9=504
10*11*12=1320
13*14*15=2730..........

Like? Yes (3) | No (2)  

Kuldeep yadav   11 years AGO

1*2*3=6
4*5*6=120
7*8*9=504
10*11*12=1320
13*14*15=2730

Like? Yes (2) | No (1)  

asam srinivasa kumar   11 years AGO

The sequence follows the pattern
3n*(3n-1)*(3n-2) where n=1,2,3....
n=1-->3*2*1=6
n=2-->6*5*4=120
n=3-->9*8*7=504
n=4-->12*11*10
the next number is for
n=5--->15*14*13

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Chandni Maurya   11 years AGO

ans=(2). 2730
series is 6,120,504,1320,?
(x^3-x, where x increased by x=>x+3, starting with 2)
2^3-2 = 8-2 =6
5^3-5 = 125-5 = 120
8^3-8 = 512-8 = 504
11^3-11 = 1331-11 = 1320
similarly,
14^3-14 = 2744-14 = 2730

Like? Yes (2) | No (1)  

MADHU KUMARI   11 years AGO

3n*(3n-1)*(3n-2)
n=5
15*14*13=2730

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siddagalla bhaskar   11 years AGO

3n(3n-1)(3n-2).
where n=1,2,3,4,5,....

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Darsana K   11 years AGO

pattern is as follows
1*2*3=6
4*5*6=120
7*8*9=504
.......
13*14*15=2730

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Deepak Padhy   11 years AGO

2^3-2,5^3-5,8^3-8,11^-11 so answer will be 14^3-14=2730(2)

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Udhaya kumar   11 years AGO

1*2*3=6
4*5*6=120
7*8*9=504
10*11*12=1320
13*14*15=2730.................

Like? Yes (2) | No (1)  

Ankit Goyal   11 years AGO

2^3 - 2 = 6
5^3 - 5 = 120
8^3 - 8 = 504
11^3 - 11 = 1320
14^3 - 14 = 2730

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ROHIT UPADHYAY   11 years AGO

using formula-- 3n*(3n-1)*(3n-2)
n=1, 3*2*1=6
n=2, 6*5*4=120
. .
. .
n=5, 15*14*13=2730

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Ankit Sharan   11 years AGO

3n*(3n-1)*(3n-2)
n=1,2,3,4,....

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Venkatesh KK   11 years AGO

3n*(3n-1)*(3n-2) where n=1,2,3,4,....

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R.RAVIKUMAR   11 years AGO

the number is increasing by 3 like 2,5,8,11,14
so given numbers are of their cubes-number
i.e (x^3)-x
so, in the order the required number is (14^3)-14=2730

Like? Yes (1) | No (1)  

Leelanand Kumar Yalla   11 years AGO

Here,
3*2*1=6;Every time 3 adds in each digit multiplication
6*5*4=120;
9*8*7=504;
12*11*10=1320;
15*14*13=2730;
So, this is the answer....
So let's get this in formula 3n*(3n-1)*(3n-2);

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rohan biswal   11 years AGO

all are products of 3 consecutive numbers;
1*2*3,4*5*6,..........13*14*15

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Dr.Dipin Singh   11 years AGO

13*14*15= 2730

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KRISHNAN   11 years AGO

The sequence is formed by the following
3n*(3n-1)*(3n-2). where n is number starting from 0
so if n = 0 then putting n in the equation we get 0
if n = 1 then putting n in the equation we get 6
if n = 2 then putting n in the equation we get 120
if n = 3 then putting n in the equation we get 504
if n = 4 then putting n in the equation we get
1320
if n = 5 then putting n in the equation we get 2730 so option 2 is correct

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A.Sivapriya   11 years AGO

the number is increasing by 3 like 2,5,8,11,14
so given numbers are of their cubes-number
i.e (x^3)-x
so, in the order the required number is (14^3)-14=2730

Like? Yes (1) | No (1)  

pranshu goyal   11 years AGO

because 1*2*3=6,4*5*6=120,7*8*9=504,10*11*12=1320,13*14*15=2730.

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Vinay Sipani    11 years AGO

nth term = (3n-1)^3 - (3n-1)

=> next term = 14^3 - 14 = 2730

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Abirudh reddy   11 years AGO

in above sequence
N^3-N
substitute the series like 2,5,8,11
with difference 3
the ans is 2730

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sharath   11 years AGO

sequence is N^3-N and N=N+3
so
2^3-2=6
5^3-5=120
8^3-8=504
11^3-11=1320
so
14^3-14=2730

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Balakumaran N.A   11 years AGO

use this formula: a(n)=3n*(3n-1)*(3n-2)
a(5) = 15*14*13 = 2730

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DHIRENDRA    11 years AGO

3n(3n-1)(3n-2).....
start from 1
for first element
3*1(3-1)(3-2)
3*2*1=6
same as
5th term
3*5(5-1)(5-2)
15*14*13=2730

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Satyendra Singh   11 years AGO

series is like this
2^3-2 , 5^3-5, 8^3-8, 11^3-11, 14^3-14
2730

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vaibhav kumar    11 years AGO

answer is 2730
reason
2^3-2=6
5^3-2=120
8^3-2=504
11^3-2=1320
14^3-2=2730

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Prabhat Yadav   11 years AGO

6=6*1
120=12*10
504=18*28
1320=24*55
2730=30*91

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