Krsihna Prasad   10 years AGO

add the odd
M=13
A=1
N=14
O=15
J=10
by adding odd numbers we get,
13+1+15=29

Like? Yes (25) | No (15)  

ROHIT KUMAR YADAV   10 years AGO

add place value of each position position 1+2+4

eg:- for MOHAN=13+15+1=29
same for MANOJ=13+1+15=29

Like? Yes (1) | No   

Venkat   10 years AGO

mohan=m+o+a=29(odd alphabet sum)
manoj=m+a+o=29

Like? Yes (1) | No   

satyanarayana   10 years AGO

m+a+0=29

Like? Yes (1) | No   

Rajapraveen.P   10 years AGO

Mohan=13+15+8+1+14(this is by a=1,b=2,c=3,d=4....)
by adding odd numbers we get 29
similarly
for manoj m=13 a=1 n=14 0=15 j=10
ans is 29

Like? Yes (1) | No   

ekta rani   10 years AGO

MOHAN=13,15,8,1,14
SUM OF 1,2&5 TERMS ARE 13+15+1=29
MANAN=13,1,14,1,14
SUM OF 1,2&5 TERMS ARE 13+1+1=15
MANOJ=13,1,14,15,10
SUM OF 1,2&5 TERMS ARE 13+1+15=29

Like? Yes (1) | No   

aparna lakshmi    10 years AGO

mohan-29 m-13,o-15,h-8,a-1,-14 where 13+15+1=29.
suresh-64 s-19,u-21,r-18,e-5,s-19,h-8 19+21+5+19=64
manan-15 m-13,a-1,n-14,a-1,n-14 13+1+1=15
manoj m-13,a-1,n-14,o-15,j-10 13+1+15=29
letter are assigned values according to their alphabetical order

Like? Yes (1) | No   

NATHIYA   10 years AGO

mohan=13+15+8+1+14(add all odd numbers)=29
similarly manoj=13+1+14+15+10
add odd numbers
manoj=13+1+15=29.

Like? Yes (1) | No   

nabarun guha   10 years AGO

find it out

Like? Yes (1) | No   

Hari Sankhar   10 years AGO

add 1st 2 no and add the 4th of each name

Like? Yes (1) | No (1)  

mohd zakir   10 years AGO

write abcd... as 1234...
add odd values of name

Like? Yes (1) | No (1)  

AMIT KUMAR   10 years AGO

ADD ONLY THESE ALPHABET WHOSE NUMERICAL VALUE FROM A(1)....TO Z(26) IS ODD NUMBER.
M=13,O=15,H=8,A=1,N=14 ==13+15+1=29
S=19,U=21,R=18,E=5,S=19,H=8 ==19+21+5+19=64
M=13,A=1,N=14,A=1,N=14==13+1+1=15
M=13,A=1,N=14,O=15,J=10==13+1+15=29
ANS>>>>>>>4) 29

Like? Yes (1) | No (1)  

sruthi   10 years AGO

take mohan ....m=13,o=15,h=8,a=1,n=14 so ...adding odd values 13+15+1=29
hence
manoj considering its postion value m=13 a=1 n=14 o=15 j=10 ...add the odd values ie 13+1+15=29 so ans is 29

Like? Yes (1) | No (1)  

Ghanshyam Gulati   10 years AGO

A(1),B(2),C(3),D(4),E(5),F(6),G(7),H(8),I(9),J(10),k(11),L(12),M(13),N(14),0(15),P(16),Q(17),R(18), S(19),T(20),U(21),V(22),W(23),X(24),Y(25),Z(26).

NOW
M O H A N = 29
13 15 8 1 14 =13+15+1(SUM OF ODD NUMBERS)

AND

S U R E S H =64
19 21 18 5 19 8 =19+21+5+19(SUM OF ODD NUMBERS)

AND

M A N A N = 15
13 1 14 1 14 = 13+1+1

HENCE
M A N O J
13 1 14 15 10=13+1+15=29

THUS ANS IS 29

Like? Yes (1) | No (1)  

mohini gupta   10 years AGO

sum of odd numbers
mohan, m=13, o=15, a=1, total=29
suresh, s=19, u=21, e=5, s=19, total=64
manoj, m=13, a=1, o=15, total=29

Like? Yes (1) | No (1)  

Varunraj Reddy   10 years AGO

Given that MOHAN=29
We know that M=13 0=15 H=8 A=1 N=14
Consider only odd number alphabets sum
i.e.,M+O+A=13+15+1=29

Now SURESH=S+U+E+S=19+21+5+19=64

MANAN=M+A+A=13+1+1=15

Similarly,
MANOJ=M+A+O=13+1+15=29
Answer is option 4)

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

sum of odds

Like? Yes (1) | No (1)  

Dr.Dipin Singh   10 years AGO

sum of place value of letters having odd place value.
like A=1,
C=3
E=5

MOHAN .... 13 15 08 01 14.... 13+15+1=29
Similarly
SURESH = 64
MANAN = 15
Hence MANOJ... 13 01 14 15 10... 13+1+15=29

Like? Yes (9) | No (15)  

azharshahid01@gmail.com   10 years AGO

In code Language,
A=1,
B=2,
C=3,
...
...
z=26
In each word add only odd numbers.
MOHAN 13,15,8,1,14 => 13+15+1=29
SURESH 19,21,18,5,19,8 => 19+21+5+19=64
MANAN 13,1,14,1,14 => 13+1+1 = 15
In the same way,
MANOJ 13,1,14,15,10 => 13+1+15 = 29
Thus answer is option 4)29

Like? Yes (4) | No (11)  

Akanksha Mishra   10 years AGO

Given

MOHAN = 29
SURESH = 64
MANAN = 15
Then
MANOJ = ?

A(1),B(2)..............................Y(25),Z(26)

MOHAN = M(13), O(15),H(8), A(1) ,N(14)

ADD odd place alphabets
M(13) + O(15) + A(1) = 29

Similarly
MANOJ = M(13),A(1),N(14),O(15),J(10)
ADD odd place alphabets
M(13) + A(1) + O(15) = 29

So answer will be 29(option 4)

Like? Yes (5) | No (14)  

MD SOHAIL AKHTER   10 years AGO

A=1, B=2,.........Z=26
NOW ADD THE ODD NO. CORRESPONDING TO THE DIGIT
MOHAN=13+15+1=29
MANOJ=13+1+15=29

Correct option.is 4

Like? Yes (2) | No (11)  

Pulkit Dureja   10 years AGO

Add all the odd terms i.e. M+A+O=13+1+15

Like? Yes (1) | No (10)  

Ann Theressa   10 years AGO

put
M=13, O=15, H=08, A=01, N=14

S=19, U=21, R=18, E=05, S=19, H=08

M=13, A=01, N=14, A=01, N=14

M=13, A=01, N=14, O=15, J=10

adding all alphabets except 3rd and last one we get
MOHAN = M+O+A = 13+15+01 = 29
SURESH = S+U+E+S = 19+21+05+19 = 64
MANAN = M+A+A = 13+01+01 = 15
and
MANOJ = M+A+O = 13+01+15 = 29

Like? Yes (1) | No (10)  

Saraswathy   10 years AGO

for odd no. of alphabets, do total-(3rd alphabet - 5th alphabet)

mohan -----> 13+15+8+1+14 =51
51 - (8+14) = 29
manan -----> 13+1+14+1+14 = 43
43 - (14+14) = 15

for even no. of alphabets, do total-(2nd alphabet - 4th alphabet)

suresh ----> 19+21+18+5+19+8=90
90 - (21+5) = 64

so "manoj" contains odd no. of alphabets
manoj ----> 13+1+14+15+10 = 53
53 - (14+10) = 29

Ans : option (4)

Like? Yes (2) | No (11)  

VEERENDRA KUMAR K G   10 years AGO

MOHAN= M+O+A=29
SURESH=S+U+E+S=64
MANAN=M+A+A=15

MANOJ=M+A+O=29

Like? Yes (1) | No (10)  

J.DHANDAPANI   10 years AGO

odd numbers are added.so,ans=29

Like? Yes (1) | No (11)  

Pallekonda Rajesh   10 years AGO

given number is the sum of the odd numbers of all
alphabets
mohan=13,15,8,1,14=13+15+1=29
suresh=19,21,18,5,19,8=19+21+5+19=64
similarly manoj=13,1,14,15,20=13+1+15=29 so
ans:29

Like? Yes (1) | No (11)  

SHEREENA NISHAD   10 years AGO

M=13
A=1
N=14
O=15
J=10
SUM OF ODD NUMBERS= 13+15+1 =29

Like? Yes (1) | No (11)  

R.RAVIKUMAR   10 years AGO

A-1,B-2,....Z-26.

The coding follow that first two letters and the letters between third letter and last letter...

MOHAN = M+O+A = 13+15+1 = 29
SURESH = S+U+E+S = 19+21+5+19 = 64
MANAN = M+A+A = 13+1+1 = 15

similarly,
MANOJ = M+A+O = 13+1+15 = 29

Like? Yes (2) | No (12)  

ashish kumar   10 years AGO

its sum of value of alphabets on odd position.
m=13,a=1,n=14,0=15,j=10
add 13+1+15=29

Like? Yes (2) | No (12)  

B karthik   10 years AGO

Conditions For Summation:
For Odd numbers..
we have remove 3,5 charecters...
For Even Numbers..
2,4 charecters...
MOHAN count is odd no. so M+O+A=13+15+1=29(3,5 not adding to summation)
SURESH Count is even no. so S+R+S+H=19+18+19+8=64(2,4 not adding to summation)
MANAN count is odd no. so M+A+A=13+1+1=15(3,5 not adding to summation)
MANOJ count is odd no. so M+A+O=13+1+15=29(3,5 not adding to summation)..
MANOJ=29..(Ans.)

Like? Yes (3) | No (13)  

TRIMURTULU   10 years AGO

sum of the odd numerals of the corresponding alphabets.

Like? Yes (1) | No (11)  

Rohit Agarwal   10 years AGO

here if number of letters in the word is odd then add 1st,2nd and 4th letter.

if number of letters in the word is even then add 1st,2nd,4th,5th letter.

so MOHAN(odd)==13+15+1=29
SURESH(even)=19+21+5+19=64
MANAN(odd)=13+1+1=15
MANOJ(odd)=13+1+15=29

Like? Yes (1) | No (11)  

saikiran   10 years AGO

for even number letter words we remove 2 and 4 letters
in suresh
s+r+s+h=19+18+19+8=64
for odd number letter words we remove 3 and 5 letters
in manan
m+a+a=13+1+1=15
like in manoj
m+a+o=13+1+15=29

Like? Yes (3) | No (13)  

ASHISH MITTAL   10 years AGO

if a=1,b=2,c=3 and so on..
in all words add only odd no to get answer so for manoj,answer will be 13+1+15=29
option no(4)

Like? Yes (1) | No (11)  

Surya Narayana K   10 years AGO

Answer : 29 (Option 4).

Coding : Sum of letters with odd value when they are arranged in alphabetical order.

MOHAN=13+15+8+1+14= 29 (13+15+1)
SURESH=19+21+18+5+19+8=64 (19+21+5+19)
MANAN=13+1+14+1+14=15 (13+1+1)

Similarly
MANOJ=13+1+14+15+10=29 (13+1+15)

So answer is 29.

Like? Yes (1) | No (11)  

NavyaBharathi   10 years AGO

First we can add corresponding 2 numbers of alphabets leave one letter then add one number corresponding to alphabet

Like? Yes (1) | No (11)  

Rajasekhar Reddy   10 years AGO

adding of odd numbers of alphabets
MANOJ = 13 1 14 15 10
by adding odd numbers
13+1+15 = 29

Like? Yes (1) | No (11)  

Satish Zod   10 years AGO

If A=1, B=2,..................Y=25, Z=26.
Add only odd numbers of alphabets used in name.
M=13, A=1, N=14, O=15, J=10.
Add 13+1+15 (Only odd numbers) = 29
i.e. sr. no. 4.

Like? Yes (1) | No (11)  

rajesh   10 years AGO

mohan=m+o+a=29(odd number alphabet)
manoj=m+a+o=29

Like? Yes (1) | No (11)  

Soumya   10 years AGO

MOHAN=13+15+8+1+14 IN THAT ADD ONLY ADD NUMBERS THEN ANS IS 29
LIKEWISE
SURESH=19+21+18+5+19+8=64
MANAN=13+1+14+1+14=15
THEN
MANOJ=13+1+14+15+10=29 SO ANS IS 29.

Like? Yes (3) | No (13)  

ch rajesh   10 years AGO

mohan=m+o+a=29(odd alphabet sum)
manoj=m+a+o=29

Like? Yes (1) | No (11)  

Soham Dalwadi   10 years AGO

ACCORDING TO A-1 TO Z-26
SUM OF ODD EQUIVALENT NUMBER TO ALPHABET

M A N O J=?
13 1 14 15 10

ODD SUM = 13 + 1 + 15 = 29
ANSWER 29

Like? Yes (1) | No (11)  

champavat jaydipsinh padamsinh   10 years AGO

ACCORDING TO A-1 TO Z-26
SUM OF ODD EQUIVALENT NUMBER TO ALPHABET

M A N O J=?
13 1 14 15 10

ODD SUM = 13 + 1 + 15 = 29
ANSWER 29

Like? Yes (1) | No (11)  

AKANKSHA NAYAK   10 years AGO

in five digit number
total is sybtracted by 3rd and 5th place
like
total is-53
sum of 3rd and 5th place is-24
subtract:-(53-24=29)

Like? Yes (3) | No (13)  

Bupathikavya   10 years AGO

sum of odd alphabet in the given question.
manoj==>m(13)+a(1)+o(15)=29

Like? Yes (1) | No (11)  

deepak kumar   10 years AGO

sum of odd numbers.

Like? Yes (1) | No (11)  

m b naga lakshmi   10 years AGO

sum of odd numbering of the alphabatics

Like? Yes (2) | No (12)  

SIBNATH HALDER   10 years AGO

ANS OPTIONS IS 4
MOHAN=13+15+8+1+14=51
TOTAL SUM-(3RD PLACE+5TH PLACE VALUE)
=51-(8+14)=29
SO, MOHAN=29
SURESH=19+21+18+5+19+8=90
TOTAL SUM-(3RD PLACE+5TH PLACE VALUE)
=90-(18+8)=64
SO, SURESH=64
MAHAN=13+1+8+1+14=37
TOTAL SUM=(3RD PLACE+5TH PLACE VALUE)=
37-(8+14)=15
SO,MAHAN=15
MANOJ=13+1+14+15+10=53
TOTAL SUM-(3RD PLACE+5TH PLACE VALUE)
=53-(14+10)=29
SO,MANOJ=29

Like? Yes (1) | No (11)  

roshani munde   10 years AGO

count odd no variables only

Like? Yes (1) | No (11)