Find a fraction which become 1/2 when 1 is subtracted from the numerator and 2 is added to the denom

Ann Theressa   11 years AGO

Let the fraction be x/y

(x-1)/(y+2) = 1/2
2x - 2 = y + 2
2x - y = 4 ----(1)

(x-7)/(y-2) = 1/3
3x - 21 = y - 2
3x - y =19 -----(2)

(2) - (1)

x = 15
and y = 26

Like? Yes (22) | No (6)  

Roopa kamale   11 years AGO

(x-1)/(y+2)=1/2
(x-7)/(y-2))=1/3
solve
x=15 & y=26
hence x/y=15/26

Like? Yes (5) | No   

Sonal Singh   11 years AGO

Let x be the numerator and y be the denominator. From statement 1:
(x-1)/(y+2)=1/2
From statement 2:
(x-7)/(y-2)=1/3

Solving both, we get.
x=15 ; y=26
Therefore, fraction = 15/26

Like? Yes (4) | No   

Grishma Shah   11 years AGO

Let numerator be x and denominator be y

From given
2x-y = 4....(1)
3x-y = 19...(2)

Subtracting (2) from (1)

x=15, putting x in (1)
y=26

Like? Yes (4) | No (1)  

indrajeet yadav   11 years AGO

let fraction=x/y
x-1/y+2=1/2
x-7/y-2=1/3
on solving both equation
x=15
y=26
so fraction=15/26

Like? Yes (3) | No   

shubham raghuvanshi   11 years AGO

supposing the fraction is x/y so by the first statement (x-1)/(y+2)=1/2 and by the second statement (x-7)/(y-2)=1/3 which forms two equations with two unknowns and gives x=15,y=26

Like? Yes (2) | No   

Shamik Maity   11 years AGO

x=(5*y-23)/2
x=denominator y=numerator
y given 1,7,15,19 only
1,7 are are too small to produce a denominator of 15(given minimum denominator)
y=15 gives x=26

Like? Yes (2) | No   

harshal agrawal   11 years AGO

let fraction be x/y
then, a/q
(x-1)/(y+2)=1/2
=> 2x-2=y+2
=> 2x-y=4 .... (1)
and (x-7)/(y-2)=1/3
=>3x-21=y-2
=>3x-y=19 .... (2)
solving (1) and (2)
x=15 y=26
hence fraction is 15/26

Like? Yes (4) | No (3)  

nirmal kumar saini   11 years AGO

let numerator is x and denominator is y
so according to first statement:-
x-1/y+2=1/2
and according to second statement:-
x-7/y-2=1/3
and by calculating both equations we get-
x=15 and y=26
so the fraction is 15/26

Like? Yes (2) | No (1)  

Aman   11 years AGO

if x/y is desired fraction, then
(x-2)/(y+2)=1/2
(x-7)/(y-2)= 1/3
solving, x/y = 15/26

Like? Yes (4) | No (3)  

Yekollu Muneeswar   11 years AGO

let the fraction be x/y
then(x-1)/(y+2)=1/2 --(1)
and (x-7)/(y-2)=1/3 --(2)

equation(1)implies, 2x-y=04
eq.(2) implies , 3x-y=19

therefore x=15 y=26.
Ans is 15/26

Like? Yes (3) | No (2)  

ABHOY KUMAR   11 years AGO

let the fraction be: n/d. acc. to ques,
(n-1)/(d+2)=12
=>2n-d=4 .............(i)
and (n-7)/(d-2)=1/3
=> 3n-d=19 .............(ii)
solving (i) & (ii) , we get-
n=15 and d=26
so, (n/d)=15/26

Like? Yes (2) | No (1)  

Abhishek Jha   11 years AGO

We suppose the fraction is x/y.
Now, as per the 1st condition, (x-1)/(y+2) = 1/2
=> 2x-2 = y+2 => 2x-y = 4 ......(1)
From the 2nd condition, (x-7)/(y-2) = 1/3
=>3x-21 = y-2 => 3x-y = 19 .......(2)

From (2)-(1), x = 15; From (1), y = 26.
Hence, x/y = 15/26. Option (5).

Like? Yes (2) | No (1)  

AMIT KUMAR   11 years AGO

let numerator = n
denominator = d
q/c,
(n - 1) / (d + 2) = 1/2
2*n - d = 4 ....................(1)
&, (n - 7) / (d - 2) = 1/3
=> 3*n - d = 19 ...................(2)
eq (1) - eq (2)
2*n - d = 4
3*n - d = 19
- + -
-----------------
-n = -15
n = 15
putting the value of n in eq.(1)
d = 26
fraction = n/d = 15/26
ans>>>>>>>>>>5)15/26

Like? Yes (2) | No (1)  

Ayesha khatoon   11 years AGO

x-1/y+2=1/2
x-7/y-2=1/3
by solving these two equation we get x=15 n y=26
so our required fraction will be 15/26

Like? Yes (2) | No (1)  

TUSHAR    11 years AGO

let x/y is fraction then (x-1)/(y+2)=0.5, (x-7)/(y-2)=1/3 then x=15, y=26

Like? Yes (2) | No (1)  

Sudipta Mukherjee   11 years AGO

Eq 1. let denominator= y and numerator=x
x-1/y+2=1/2
Eq. 2 . x-7/y-2=1/3.
solving this we get
x=15,y=26.
15/26

Like? Yes (2) | No (1)  

shree   11 years AGO

let numerator=x and denominator=y
if we will put given input we get two equation
2x-y=4-------------(1)
3x-y=19------------(2)
after solving these equation
we get x=15 and y=26
so the fraction is 15/26

Like? Yes (2) | No (1)  

Keshav Kishlay   11 years AGO

let us assume fraction is x/y
(x-1)/(y+2)=1/2;2x-y=4....(1)
(x-7)/(y-2)=1/3;3x-y=19.....(2)
so, after subtracting from 2 to 1 then
x=15;y=26
so, fraction will be 15/26

Like? Yes (2) | No (1)  

Varunraj Reddy   11 years AGO

By verification only option 5) satisfies both conditions.

Like? Yes (2) | No (1)  

Pankaj Kumar Verma   11 years AGO

Let the fraction is x/y.
by the equation(1)
2(x-1)=y+2 ..........(1)
and by second equation
3(x-7)=y-2 ........(2)
after solving both equts
x=15
and y=26
so, fraction is 15/26.

Like? Yes (2) | No (1)  

Y.Rony Singh   11 years AGO

Taking numerator as x n denominator as y we have given equation as
2x-2=y+2
3x-21=y-2
Solving we have x= 15 and y= 26

Like? Yes (2) | No (1)  

RAVI KANT   11 years AGO

x-1/y+2=1/2 and
x-7/y-2=1/3

Like? Yes (2) | No (1)  

sahithya   11 years AGO

Let nunerator be x and denominator be y
so (x-1)/(y+2)=1/2 by simplifying we get 2x-1=4
and (x-7)/(y-2)=1/3 by simplifying we get 3x-y=19
on solving above equations x=15 and y=26
so ans is 15/26

Like? Yes (2) | No (1)  

gaurav arora   11 years AGO

(15-1)/(26+2)=1/2 and (15-7)/(26-2)=1/3
so answer is 15/26

Like? Yes (2) | No (1)  

Leelanand Kumar Yalla   11 years AGO

3x-y-19=0---->(1);
2x-y-4=0------>(2);

By solving 1 and 2 we will get 15/26...

Like? Yes (2) | No (2)  

SriS   11 years AGO

Let the fraction be x/y
given x-1/y+2=1/2
x-7/y-2=1/3
by solving the equation we will get x=15 and y=26

Like? Yes (2) | No (2)  

sruthi   11 years AGO

let x/y be the fraction
so
x-1/y+2=1/2 equation 1
x-7/y-2=1/3 equation 2
from equation 1
2(x-1)=y+2
2x-2=y+2
2x-y=4
take equation 2
3(x-7)=y-2
3x-21=y-2
3x-y=19
fom these two equation find x and y
x=15 and y=26
so answer is 15/26
15-1/26+2=1/2
15-7/26-2=1/3

Like? Yes (2) | No (2)  

saikiran   11 years AGO

(x-1)/(y+2)=1/2 ---> 2x-y=4 -->eq1
(x-7)/(y-2)=1/3 ---> 3x-y=19 -->eq2
by solving eq1 and eq2
x/y=15/26

Like? Yes (3) | No (3)  

Gitanjali K   11 years AGO

let fraction be a/b
given, if 1 is subtracted from the numerator and 2 is added to the denominator fraction become 1/2
so, a-1/b+2=1/2
b+2=2a-2
2a-b=4 ...eq (1)

given, when 7 is subtracted from the numerator and 2 from denominator fraction become 1/3
so, a-7/b-2=1/3
b-2=3a-21
3a-b=19 ...eq(2)

therefore solving eq (1) and (2)
we get a=15 & b=26
therefore the fraction is 15/26

Like? Yes (2) | No (2)  

BHAVNISH BHUTANI   11 years AGO

from statement we can conclude
2x-y=4--(1)
3x-y=19--(2)
on solving 1 and 2 we get x=15 and y =26
so the fraction becomes 15/26

Like? Yes (2) | No (2)  

Tanvir Rahman   11 years AGO

Let the fraction is x/y.
Now from question
(x-1)/(y+2)=1/2 ---- 1
(x-7)/(y-2)=1/3 ---- 2

again,

2x-y=4 ---- 3
3x-y=19 ---- 4

by solving equation 3 and 4
x=15
y=26

So, the fraction is 15/26
ANS=option -- 5

Like? Yes (2) | No (2)  

Rashmi bharti   11 years AGO

let the fraction is x/y.
(x-1/y+2)=1/2----(i)
(x-7/y-2)=1/3-----(ii)
on solving,we get x=15,y=26.

Like? Yes (2) | No (2)  

shree   11 years AGO

5) 15/26 is answer

Like? Yes (2) | No (2)  

muni   11 years AGO

x-1/y+2=1/2----1
x-7/y-2=1/3-----2
solve 1 and 2
x/y=15/26

Like? Yes (2) | No (2)  

jagruti bhagwan salvi   11 years AGO

15/26=15-1/26+2=14/28=1/2
15/26=15-7/26-2=8/24=1/3

Like? Yes (2) | No (2)  

raj miglani   11 years AGO

X-1/y+2=1/2
2x-2=y+2
also,
x-7/y-2=1/3
3x-21=y-2
solving
x=15
y=26

Like? Yes (2) | No (2)  

Satish Zod   11 years AGO

Let the fraction is x/y
(x-1)/(y+2) = 1/2
(x-7)/(y-2) = 1/3

Solving this,
x/y = 15/26

Like? Yes (2) | No (2)  

Sundar Kumar   11 years AGO

take 15/26 in dat sub 1 from num nd add 2 to den then u vil get 1/2 as fraction dis s stated n d ques... similarly sub 7 from num nd 2 from dem u vil get 1/3 is also stated n ques... so 15/26 s d ans

Like? Yes (2) | No (2)  

RAKESH   11 years AGO

x-1/y+2 = 1/2

x-7/y-2 = 1/3

x=15, y=26

Like? Yes (1) | No (2)  

Udhaya kumar   11 years AGO

(x-1)/(y+2)=1/2
(x-7)/(y-2)=1/3
by solving this we get
x=15
y=26

Like? Yes (2) | No (3)  

llamar   11 years AGO

assume that fraction is x/y111
(x-1)/(y+2)=(1/2)......(1)
(x-7)/(y-2)=(1/3).............(2)
solve above two equation
we get x=15,y=26

Like? Yes (1) | No (2)  

Purosotam Gupta   11 years AGO

Let, the fraction is x/y
then
by the question
1/2=(x-1)/(y+2)
y+2=2x-2
2x-y=4........equ(1)
again
by the question
1/3=(x-7)/(y-2)
y-2=3x-21
3x-y=19........equ(2)
from 1 and 2

x=15
y=26

Like? Yes (1) | No (2)  

goral   11 years AGO

x-1/y+2=1/2
so,2x-y=4........(1)
x-7/y-1=1/3
so,3x-y=19.......(2)
solving (1)-(2)
x=15
put value of x in (1) or(2)
get y=26
it means x/y=15/26

Like? Yes (2) | No (3)  

DILEEP KUMAR   11 years AGO

x-1/y+2 = 1/2
x-7/x-2 = 1/3
solving thesetwo.......
sol x/y=15/26

Like? Yes (2) | No (3)  

steffy edmond   11 years AGO

Ans:Option 5) 15/26
Let the numerator be 'x' and the denominator be'y'.
let the first equation be (x-1)/(y+2)=1/2
Solving,
2x-2=y+2
2x-4=y -->(1)
let the second equation be (x-7)/(y-2)=1/3
Solving,
3x-21=y-2
3x-19=y -->(2)
Equating (1) and (2),
2x-4=3x-19
x= 15
substituting value of x in equation (1),
2*15-4=y
30-4=y
y=26
therefore the fraction x/y =15/26

Like? Yes (1) | No (2)  

vishal gupta   11 years AGO

x-1/y+2=1/2
x-7/y-2=1/3
on solving both equation
x=15
y=26
so x/y=15/26

Like? Yes (1) | No (2)  

AJAY KUMAR   11 years AGO

(x-1)/(y+2)=1/2
(x-7)/(y-2)=1/3
x=15,y=26
x/y=15/26

Like? Yes (1) | No (2)  

KALAIYARASI PADHMANABAN   11 years AGO

x-1/y+2=1/2 x-7/y-2=1/3
2x-2=y+2; 3x-21=y-2
2x-y=4 --->1 3x-y=19 --->2

solve (1)&(2)
x=15; y=26;

X/Y=15/26

Like? Yes (1) | No (2)  

Santosh Vishwakarma   11 years AGO

(x-1)/(y+2)=1/2 -------------(1)

(x-7)/(y-2)=1/3 --------------(2)

solve these.
x/y=15/26

Like? Yes (1) | No (2)  

Deepak Baran   11 years AGO

let required fraction be x/y
a/q
(x-1)/(y+2)=1/2
(x-7)/(y-2)=1/3
after solving above equ..we get
x=15 and y=26
required fraction be 15/26

Like? Yes (1) | No (2)  

Devendra Marghade   11 years AGO

If 'x/y' is the fraction then
Ist case:(x-1)/(y+2)=1/2 ,2x-y=4 ---(i) &
2nd case:(x-7)/(y-2)=1/3,3x-y=19 ---(ii)
Solving (i)&(ii),we get x=15,y=26

Like? Yes (1) | No (3)  

KAUSTUBH BHARDWAJ   11 years AGO

let x=numerator and y=denominator
now from 1st condition
x-1/y+2=1/2;
from 2nd condition
x-7/y-2=1/3;
on solving by putting value of x from 1st eqn. to 2nd we can get,
x=15
and
y=26
s0 the fraction is x/y=15/26

Like? Yes (1) | No (3)  

Ghanshyam Gulati   11 years AGO

(x-1)/(y+2)=1/2
and
(x-7)/(y-2)=1/3

Like? Yes (1) | No (3)  

RANA MONDAL   11 years AGO

1st,
(x-1)/(y+2)=1/2
2nd,
(x-7)/(y-2)=1/3

x=15, y=26
Ans: 15/26

Like? Yes (1) | No (3)  

saisudha sarva   11 years AGO

(15-1)/(26-2)=1/2

Like? Yes (1) | No (3)  

NIRUPOM GHOSH   11 years AGO

1st eqn and 2nd eqn solve we get x/y=15/26.

Like? Yes (1) | No (3)  

ashish kumar   11 years AGO

jst by looking options....we can get it i.e: 15/26

Like? Yes (1) | No (3)  

ASHISH MITTAL   11 years AGO

(x-1)/(y+2)=1/2
(x-7)/(y-2)=1/3
after solving we get
x/y=15/26

Like? Yes (1) | No (3)  

SIBNATH HALDER   11 years AGO

by solved get 2 eqn
2X-Y=4 & 3X-Y=19
X/Y=15/26

Like? Yes (1) | No (3)  

abirami   11 years AGO

num is x/y
x-1=a and y+2=2a
become y+2=2(x-1)
eq 1: 2x-y=4
x-7=b and y-2=3b
become y-2=3(x-7)
eq 2:
3x-y=19

solve:

ans: x=15 and y=26
num is 15/26

Like? Yes (1) | No (3)