Ann Theressa   10 years AGO

second number = first number/4 + 4
third number = first number + 20
or
third number = (second number+1)*4

(16,8,36)
===>16/4 + 4 = 8
===> 16+20 = 36
===>(8+1)*4 = 36

(28,11,48)
===>28/4 + 4 = 11
===> 28+20 = 48
===> (11+1)*4 = 48

(12,7,32)
===>12/4 + 4 = 7
===> 12+20 = 32
===> (7+1)*4 = 32

(4,5,24)
===>4/4 + 4 = 5
===> 4+20 = 24
===> (5+1)*4 = 24

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sruthi   10 years AGO

(16,8,36) ,(28,11,48) , (12,7,32)
here
36-16=20
48-28=20
32-12=20
so (4,5,24) 24-4=20

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PAWAN KUMAR   10 years AGO

16=4*4
8=4+4
36=4*(4+4+1)=4*8+1
Similarly others

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Udhaya kumar   10 years AGO

diff bw fst & last numbers is 20.......

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Pradeep   10 years AGO

Jst tak the 1st and 3rd numbers of each set.the dfrnc is 20.and also nw cnsider the middle one in each set multiply that number by 4 and add 4 to the resultant value which givs the third nmbr

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NAGENDRA P   10 years AGO

4*4,4+4,4*(8+1)=(16,8,36)
4*7,4+7,4*(11+1)=(28,11,48)
4*3,4+3,4*(7+1)=(12,7,32)
Similarly..
4*1,4+1,4*(5+1)=(4,5,24)..
so option (3)

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paulprashanth   10 years AGO

(12-4,7-1,32-4)=(8,6,28)=(8-4,6-1,28-4)=(4,5,24)

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manish chauhan   10 years AGO

6 are same as 36 right side=6
8 are also same right of 48
similary in 12, 2 are also 32 rihght side and
8*4+4=36
11*4+4=48
7*4+4=32
similary 5*4+4=24 also 4 r both left and right of 24

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Dhananjay singh   10 years AGO

36-16=20
48-28=20
32-12=20
ans:3) 24-4=20

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Dr.Dipin Singh   10 years AGO

(16, 8, 36), (28, 11, 48), (12, 7, 32) are 3 set of integers according to some mathematical operations.
operation is given by
(4x 4+x 4((4+x+1))
(16, 8, 36)....... when x=4
(28, 11, 48)... when x=7
(12, 7, 32) ... when x=3
and
(4, 5, 24).. when x=1

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Karan   10 years AGO

when difference of first and last term is 20.
only (4, 5, 24) satisfies this condition.

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SHEREENA NISHAD   10 years AGO

(16 8 36) - 4*4 4+4 (8+1)*4
(28 11 48)- 7*4 7+4 (11+1)*4
(12 7 32) - 3*4 3+4 (7+1)*4
(4 5 24) - 1*4 1+4 (5+1)*4

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sanghavi    10 years AGO

(4*4,4+4,4*9)=(16,8,36)
(4*7,4+7,4*12)=(28,11,48)
(4*3,4+3,4*8)=(12,7,32)
(4*1,4+1,4*6)=(4,5,24)

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SHUBHAM KUMAR   10 years AGO

16,8,24=4*4,4+4*1,4*9
28,11,48=4*7,4+7*1,4*12
12,7,32=4*3,4+3*1,4*8
4,5,24=4*1,4+1*1,4*6

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Varunraj Reddy   10 years AGO

Given sets are
(16,8,36),(28,11,48),(12,7,32)

These sets follows the operation
(4n-16, n ,4n+4)

So only option 3) satisfies this operation
ie.,(4,5,24)

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Sundar Kumar   10 years AGO

answer : (4,5, 24)
because
(16,8,36)=> 30-12= 20
(28, 11, 48)=> 48-28=20
(12, 7, 32)=>32-12=20
similarly (4,5, 24)=>24-4 =20

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Ankush Kumar   10 years AGO

Here i only found similarity :
Diff(16,36)=20
Diff(28,48)=20
Diff(12,32)=20
And from option only this one is fit-
Diff(4,24)=20

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SREEVIDHYA P P   10 years AGO

consider first (16,8,36)
36-16=20
8*4=32+4=36
ie.,last no-first=20& (middle *4)+4 = last
similarly,second
48-28=20 & (11*4)+4=48
32-12=20 & (7*4)+4=32
24-4 =20 & (5*4)+4=24
therefore the answer is (4,5,24).
So option (3) is the answer

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gaurav arora   10 years AGO

(8*4-16, 8, 8*4+4)
(11*4-16, 11, 11*4+4)
(7*4-16, 7, 7*4+4)

so option 3) is correct

(5*4-16, 5, 5*4+4)

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Akhilesh   10 years AGO

series goes on as (4,5,24),(8,6,28),(12,7,32)i.e.(4+4x,5+x,24+4x)

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Clair Christ D   10 years AGO

16,16/4+4=8,8*4+4=36
28,28/4+4=11,11*4+4=48
12,12/4+4=7,7*4+4=32
4,4/4+4=5,5*4+4=24(4,5,24)

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Ranjan Kumar   10 years AGO

16+20=36,
28+20=48,
12+20=32,

in the same way only 4+20=24 means options no 3 only satisfying this conditions and this is the options.

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subasini matheswaran   10 years AGO

28-16=12
11-8=3
48-36=12
28-12=12
11-7=4
48-32=12
so option 3

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indrajeet yadav   10 years AGO

(16,8,36)->third term=8*4+4=36 and First term=36-20=16
(28,11,48)->third term=11*4+4=48 and First term=48-20=28
(12,7,32)->third term=7*4+4=32 and First term=32-20=12
similarly
(4,5,24)->third term=5*4+4=24 and first term=24-20=4

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Anupam Banerjee   10 years AGO

The elements in each set are in a increment series.

Every next set is defined as,
1st element = 1st element of previous set + 4;
2nd element = 2nd element of previous set + 1;
3rd element = 3rd element of previous set + 4;

So, calculating back, the only option that satisfy the condition is the set (4,5,24);

The list can be,
(4,5,24)
(8,6,28)
(12,7,32)
(16,8,36)
(20,9,40)
(24,10,44)
(28,11,48)
(32,12,52) and so on..........

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vishesh saxena   10 years AGO

4,5,(2+4=6)

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Devendra Marghade   10 years AGO

If set contains integers(a,b,c) then,there is a difference of 20 in the sum of (a+b) & (b+c)
16+8=24 , 8+36=44,& 44-24=20
28+11=39 , 11+48=59, & 59-39=20
12+7=19, 7+32=39, & 39-19=20 similarly
4+5=9 , 5+24=29 & 29-9=20 ,
So option(3)

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T.Aravinth kumar   10 years AGO

4+20=24.
(4,5,24)

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DILEEP KUMAR   10 years AGO

the difference between The first number and third number in the set is 20.

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AMRIT SHANKAR   10 years AGO

difference between 1st and 3rd integer is 20 so answer is option 3

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Gitanjali K   10 years AGO

3rd number = 1st number + 20
so option (3) is the answer

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vemula mounika   10 years AGO

the difference between first and last number is 20

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Gokul Krishnan   10 years AGO

(4,5,24)=24-4=20

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Mahalakshmi   10 years AGO

(4,5,24)=>4+20=24
(5+1)*4=24
so ans is option 3

Like? Yes (2) | No (4)