Two pipes running together can fill a cistern in 6 minute. If one pipe takes 5 minutes more than the

Krupa Pareshkumar Shah   10 years AGO

let total work done by two pipes in one minute is
1/6.
one of them done in one minute is 1/x & another one done it in one minute is 1/(x+5).
so that
1/x +1/(x+5)=1/6
After solving this...
x=10...
x+5=15

Like? Yes (42) | No (3)  

Amrita priyadarshi   10 years AGO

let us suppose pipe 1 takes x minutes to fill the tank so in 1 minute it would fill 1/x part of tank.
then 2nd pipe will take x+5 minutes so in 1 minute it would fill 1/(x+5) part of tank.
both pipe will take 6 minutes to fill up the tank.
hence (1/x)+[1/(x+5)]=1/6
after solving we will get 10 and -3 as solution of x. x=(-3) can't be a solution.
thus 1st pipe will take 10 minutes
and 2nd pipe will take x+5 = 15 minutes.

Like? Yes (21) | No (4)  

Sundar Kumar   10 years AGO

Let volume of cistern be V litres

Pipe 1 rate of filling = V / x litres / min
Pipe 2 rate of filling = V / ( x + 5) litres / min

Combined rate of filling = V / 6 litres / min

V / x + V / ( x + 5 ) = V / 6

6 ( x + 5 ) V + (6 x ) V = x ( x + 5 ) V

6x + 30 + 6 x = x ² + 5 x

x ² - 7 x - 30 = 0

( x - 10 ) ( x + 3 ) = 0

x = 10

Pipes take 10 min and 15 min /(6)
1/x + 1/(x + 5) = 1/6
6(2x + 1) = 11x(x + 1)
60x + 30 = 11x^2 + 11x
11x^2 - 49x - 30 = 0
(x - 5)(11x + 6) = 0
One pipe takes 5 minutes and the other 6 minutes to fill the cistern.

Like? Yes (20) | No (8)  

Bobby Nayak   10 years AGO

let pipe 1 takes x min to fill cistern
and pipe 2 takes (x+5) min to fill
therefore,

cistern filled by pipe 1 in 1min = 1/x
cistern filled by pipe 2 in 1min = 1/(x+5)
and together they fill 1/6 in 1min.

so, 1/x + 1/(x+5)= 1/6
by solving for x, we get x=10
thus, pipe 1 takes 10 min and
pipe 2 takes 15 min

answer is option 6

Like? Yes (8) | No (4)  

ananthavalli   10 years AGO

Two pipes can fill a cistern in 6 minute
Let the cistern filled by first pipe take 5 minutes more..so it is (x+5)
Then,second pipe fill it in x minutes
1/(x+5)+1/x=1/6
By solving the equation we get:(x-10)&(x+3)
By taking positive value x=10..Second cistern will take =10 minute
So,the first cistern will take(10+5)=15 minute
Option 6) is correct

Like? Yes (4) | No (1)  

Purnendu Giri   10 years AGO

eliminate the options a

Like? Yes (5) | No (2)  

IFFAT IRAM   10 years AGO

let the time taken by cistern A be x
time taken by cistern B =x+5
1/x + 1/(x+5)=1/6
12x+30=x(x+5)
x^2-7x-30=0
x^2-10x+3x-30=0
(x-10)(x+3)=0
x=10
x+5=15
10 mins and 15 mins
option 6

Like? Yes (4) | No (3)  

vandana   10 years AGO

both pipes one minute work is =1/6
one pipe one minute work is x and other pipes work is x+5.
1/x+1/(x+5)=1/6
=>x^2-7x-30=0
on solving x=10,therefore pipes takes x=10 and x+5=15 minutes

Like? Yes (3) | No (2)  

akrati   10 years AGO

According to ques
Eq are
1/x+1/(x+5)=1/6
On solving them we get
X^2-7x-30=0
X(x-10)+3(x-10)=0
x=-3,10
y=10+5=15
And is
15,10

Like? Yes (3) | No (3)  

Ravi Bhalani   10 years AGO

let one pipe taks x min so another pipe takes x+5 min
now according to given condition ;
(x(x+5))/(x+x+5)=6
solving we get x=10 so ans is in option 6

Like? Yes (1) | No (1)  

Shashank   10 years AGO

let i pipes fill in x thn other fill in x+5
1/x+1/(x+5)=1/6
after solving x=10,-3
time cant not be -ve thn we take 10
other is 10+5 which is 15

Like? Yes (2) | No (2)  

Hanish   10 years AGO

as 1/(x-5)+1/x=1/6
solving,we get
option 6)
..

Like? Yes (1) | No (1)  

NITIN KUMAR GOYAL   10 years AGO

(1/x)+[1/(x+5)]=1/6
x=10

Like? Yes (1) | No (1)  

Udhaya kumar   10 years AGO

(1/6) = (1/x)+(1/(x+5))
by soving this we get x=10... so 10,15....

Like? Yes (2) | No (2)  

rojaranivutukuri   10 years AGO

p1 -> t minutes, p2 ->t+5 minutes
in one minute,
1/t + 1/t+5 = 1/6
=> t=10
=> t+5=15

Like? Yes (1) | No (1)  

mansi garg   10 years AGO

1/X+1/(X+5)=1/6
HENCE X= 10

Like? Yes (2) | No (3)  

Lakshya   10 years AGO

Because 1st pipe take 5 minute more than other

Like? Yes (2) | No (3)  

shree   10 years AGO

(1/X)+(1/X+5)=(1/6)
12X+30=X^2+5X
X^2-7X-30=0
X=10
Time=15 min and 10 min

Like? Yes (2) | No (3)  

Amit kumar   10 years AGO

Let A pipe takes x mins and B takes (x+5)mins.
ATQ
1/x+1/(x+5)=1/6
==> x= 10 mins
Ans 10 mins. and 15 mins.

Like? Yes (2) | No (3)  

D.Gnaphika   10 years AGO

let x be the time taken by one pipe let x+5 be the time taken by other pipe according to the question 1/((1/x)+(1/(x+5)))=1/(1/6) by sloving we get x=10 and x+5=15

Like? Yes (2) | No (3)  

MRITUNJAY KUMAR   10 years AGO

the cistern filled by both pipe in 1 min will be 1/6.
let one pipe filled the cistern in x min.another pipe will fill in x+5 min.
(1/(x+5))+1/x=1/6; we get x=10,-3.neglect -3.
ams will be 10 & 15.

Like? Yes (2) | No (3)  

Ambuj tiwari   10 years AGO

T1*T2/ T1+T2

Like? Yes (2) | No (3)  

Kowshik Sarker   10 years AGO

let one pipe takes x min so another pipe takes (x+5)min. So we can get a equation that is
(1/x)+(1/x+5)=1/6
solving this we get x^2-7x-30=0
solving this we get x=10
so one pipe will take 10min and another will take 15min. so the correct option will be 6.

Like? Yes (2) | No (3)  

AMIT KUMAR ANAL   10 years AGO

x,x+5
(1/x)+(1/x+5)=1/6

Like? Yes (2) | No (3)  

Shanmugapriya   10 years AGO

Let the pipes be x and x+5
Now,
1/x+1/x+5=1/6
since,two pipes fill the cistern in 6 min
Solving the equation, we get
x=10 and -3
Negative answer is rejected
so ans is 10 min and 15 min

Like? Yes (1) | No (2)  

Rashmi bharti   10 years AGO

let one pipe fills the cistern in x min and other in (x+5)mins.
=>(1/x)+(1/(x+5))=1/6
=>x=10 min
other pipe would 15 mins.

Like? Yes (2) | No (3)  

himani chawla   10 years AGO

x-y=5
1/x+1/y=1/6
by solving we get x=15 and y=10

Like? Yes (1) | No (2)  

pankaj kumar   10 years AGO

let speed of first pipe is x
then
6((1/x)+(1/(x+5)))=1
after solution we get x=10
so answer is 10,15

Like? Yes (1) | No (2)  

akash Khandale   10 years AGO

check options

Like? Yes (1) | No (2)  

AMIT SINGH   10 years AGO

let 1st pipe takes x min. to fill the cistern
so, 2nd pipe take x+5 min.
hence the equation becomes
6(1/x +1/(x+5))=1
x=10 or -3
therefore,x=10 (since time cannot be negative).
so,pipes would take 10min and 15min to fill the cistern separately.
option(6).

Like? Yes (1) | No (2)  

nagineni sukumar   10 years AGO

one pipe takes=x min.
another pipe takes =x+5 min.
in one minute 1/x +1/(x+5)=1/6
solve above equation get x=10min
difference in filling two pipes=5
so that other pipe it takes=15 min

Like? Yes (1) | No (2)  

NAVNEET RAJ VAISH   10 years AGO

looking at the options only 6 and 9 satisfy the 5 min difference condition.

for 6 mins time of operation

1st pipe will fil 0.6times cistern
2nd pipe fills 6/15 i.e. 0.4 times cistern hence on taking them together whole (0.4+0.6)times i.e full cistern is filled

Like? Yes (1) | No (2)  

juhi   10 years AGO

work of first pipe=1/x+5;
work of second pipe=1/x;
then 1/6=1/x+1/x+5;
after solving it x=10

Like? Yes (1) | No (2)  

Devendra Marghade   10 years AGO

If one pipe fill the cistern in 'x' minutes, then other will take (x+5) minutes
(1/x)+1/(x+5)= 1/6
x^2-7x-30=0
(x-10)(x+3)=0,
x=10,so (x+5)=15

Like? Yes (1) | No (3)  

Anand Singh   10 years AGO

let first pipe fill the cistern in x minute
and second pipe fill the cistern in y minute
According to question....
x-y=5-----------------(1)
and
(1/x+1/y)6=1-----------(2)
By solving equation (1)&(2)
we get x=15.
and y=10.
so first pipe fill the cistern in 15 minute.
and Second pipe fill the cistern in 10 minute.

Like? Yes (1) | No (3)  

Varunraj Reddy   10 years AGO

Let one pipe can fill the cistern in x min.
Other pipe can fill the cistern in (x+5) min.
Two pipes can fill the cistern in 6 min.

i.e., 1/x + 1/(x+5)=1/6

By solving we get,
x=10 or -3
Then x=10 min, x+5=15 min

Ans: Option 6)

Like? Yes (1) | No (3)  

Anupam Banerjee   10 years AGO

Let, 1st pipe takes x min;
2nd pipe takes (x+5) min;

Together they fill,
(1/x)+(1/x+5) part of the cistern in 1min;

So, 6* [(1/x)+(1/x+5)] = 1;
By solving it, we have x = 10;

So the time taken to fill the cistern by each pipe will be 10 min and (10+5) = 15 min;

Like? Yes (1) | No (3)  

Saraswathy   10 years AGO

Let 1st pipe takes x minute to fill the cistern
1/x + 1/(x+5) = 1/6
Solving, we ll get x = 10 min
x = 10mins, x+5 = 15min

Ans : 15 min and 10 min (Option 6)

Like? Yes (1) | No (3)  

Vaishali Gupta   10 years AGO

1/a+1/b=1/6
1/a+1/(a+5)=1/6
on solving
a^2-7a-30=0
a^2-10a+3a-30=0
(a-10)(a+3)
a=10
b=a+5
10+5
b=15

Like? Yes (1) | No (3)  

D.Sree Navya   10 years AGO

1/x+1/x+5=1/6 this is the equation we get from the given question.
By solving the above equations we get x value as 10 then x+5=15..
15,10

Like? Yes (1) | No (3)  

pawan kumar chhipa   10 years AGO

both the pipe takes 6
then in one minute he takes 1/6 full
let one pipe take x minute
other take 5 more then x+5
in one minute both can fill the pipe 1/x or 1/(x+5)

total in one minute
1/x+1/(x+5)=1/6
solve it
x=10
x+5 =15
ans is 6)

Like? Yes (1) | No (3)  

Dimple   10 years AGO

1/15 +1/10=1/6

Like? Yes (1) | No (3)  

abhilash kumar   10 years AGO

Let time taken by one pipe be x min.then the time taken by other pipe l be x+5 min
Then 1/x + 1/(x+5) =1/6
Solving we get x=10
Hence it is 15 n 10 mins

Like? Yes (1) | No (3)  

krishn kumar gupta   10 years AGO

pipes A an B together filled the cistern in 6 min.:
(1/A+1/B)=1/6----------(1)

now another condition is
A=B+5
now from eq-(1)
we will get B=10,-3(not possible)
so
Pipe A will take (10+5)=15 min
Pipe B will take 5 min
so option 6 is correct!!!

Like? Yes (1) | No (3)  

Mohammed Farook.S   10 years AGO

1/x+1/(x+5)=1/6

Solve the eqn we get x=10 and 15

Like? Yes (1) | No (3)  

Yogesh   10 years AGO

1/x +1/(x+5)=1/6

from this we got

x^2-7x-30=0

x(x-10)+3(x-10)=0

x=10,-3
-3 is not possible
so x=10
x+5=15

Like? Yes (1) | No (3)  

Gourango   10 years AGO

eliminate the options and then check the options.

Like? Yes (1) | No (5)