If ABHAY = 54, VINOD = 80, KARAN = 64, YOGESH = 142 then SURESH = ?

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04 Dec 2009 code for suresh

If ABHAY = 54, VINOD = 80, KARAN = 64, YOGESH = 142
then SURESH = ?

OPtion

1) 102
2) 124
3) 118
4) 132
5) 142
6) 128
7) 98
8) 86
9) 168
10) 156

Solution

According to the positional values word
ABHAY = 1, 2, 8, 1, 25
Code is [Sum of numbers + mod (even integers – odd integers)]
= 37 + |10 - 27|
= 37 + 17
= 54
Similarly for others

Correct Option: 6 Best Solution (3)

Dr.Dipin Singh   14 years AGO

ABHAY = 54,
Give number value to letters

1,2,8,1,25

Add odd numbers and even numbers separately.

Sum of even numbers ... 10
sum of odd numbers = 1+1+25=27.
Out of 10 and 27 , 27 is larger.

Ignore smaller sum.

Double larger sum (27) to get 54 as code .

Similarly for

VINOD = 80, KARAN = 64, YOGESH = 142
Then SURESH = ?

SURESH ..19,21,18,5,19,8

Sum of odd nos = 19+21+5+19= 64
sum of even nos. = 18+8=26 ..ignore it

Double larger sum of 64 to get 128 as code.

so option 6

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Pargat Pal Singh   14 years AGO

Give numerical value to all letters of the word.

Add all even numbers separately and odd numbers separately.

Double the larger sum to get the desired code.

In SURESH ,

odd Nos are
19, 21, 5,19 and sum = 64
even numbers are
18, 8 and sum = 26

Code is obtained by multiplying larger sum ( in this case 64 ) by 2 and get code as 128.

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Aman   14 years AGO

Considering positional value of letters in different names , list separately the odd numbers and even numbers.

Add them separately.

Consider only larger sum out of these two.

Double this sum to get the code.

In SURESH

CODE is 2* ( 19+21+5+19)= 2*64=128 .. option 6

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