The probability of occurrence of two events E and F are 0.25 and 0.30 respectively. The probability

NAVEEN KUMAR   10 years AGO

P(E)=0.25 P(F)=0.30
P(E∩ F)=0.14
P(E OR F)=P(E)+P(F)-P(E∩ F)=0.25+0.30-0.14=0.41

Like? Yes (25) | No (3)  

Kethineni Vinodh   10 years AGO

P(A U B)=P(A)+P(B)-P(A intersecton B)
=0.25+0.30-0.14
=0.41

Like? Yes (5) | No   

Tania Chatterjee   10 years AGO

P(E OR F)= P(E)+P(F)-P(E & F) = 0.25 + 0.30 - 0.14 = 0.41

Like? Yes (5) | No (1)  

Mahesh   10 years AGO

Probability of A=0.25
Probability of B=0.3
Probability of A and B =0.14
Probability of A or B= A+B-A and B=0.25+0.3-0.14=0.41
Answer is 0.41 that is none of these

Like? Yes (3) | No   

jitendra varshney   10 years AGO

p(A ∪ B)=p(A)+(B)-p(A ∩ B),
=0.25+.030-0.14,
=0.41 so option 10 is correct

Like? Yes (5) | No (2)  

vikas   10 years AGO

p(a)+p(b)-p(a and b)= p (a or b)
there fore ans =(.25 +.3)-.14=.41

Like? Yes (3) | No (1)  

Nischay Jain   10 years AGO

P(EuF) = P(E) +P(F) -P(EnF)
= 0.25 +0.30 -0.14
=0.41

Like? Yes (2) | No   

Sanjit Kumar Sharma   10 years AGO

0.25+0.30-0.14=0.41

Like? Yes (2) | No   

NISHANT VERMA   10 years AGO

e=0.25, f=0.30
e and f occurence =0.14
so either e or f will occur = e+f-e and f occurnce
= 0.25+0.30-0.14
= 0.41

Like? Yes (2) | No   

MUKESH YADAV   10 years AGO

probability will be .41

Like? Yes (3) | No (1)  

Gaurav Agrawal   10 years AGO

answer is 0.41

Like? Yes (2) | No   

Enukonda Ramakrishna   10 years AGO

P(EUF)=P(E)+P(F)-P(E).P(F)
=0.25+0.30-0.14
=0.41

Like? Yes (2) | No   

PAWAN KUMAR   10 years AGO

p(EUF) = p(E) +p(F) -p(E intersection F)

=> P(EUF) = 0.25 + 0.30 - 0.14 = 0.41 Ans.

Like? Yes (2) | No (1)  

purushottam sah   10 years AGO

P(A U B)=P(A)+P(B)-P(A ∩ B)
=0.25+0.30-0.14=0.41

Like? Yes (2) | No (1)  

Subhash Kumar   10 years AGO

P(E) = 0.25
P(F) = 0.30
P(E and F) = 0.14
P(E or F) = P(E) + P(F) - P(E and F) = 0.25 + 0.30 - 0.14 = 0.41
Ans 0.41 not in the given option

so, option is: 10) None of these.

Like? Yes (1) | No   

madhurima   10 years AGO

P(AUB)=0.25+0.30-0.14=0.41

Like? Yes (1) | No   

RAKESH   10 years AGO

p(E or F) = p(E) + p(F) - p(E & F)

= .25 + .30 - .14
= .41

Like? Yes (1) | No   

Sukanya   10 years AGO

P(A or B)=P(a)+P(b)-P(a and b)
0.25+0.30-0.14=0.41

Like? Yes (1) | No   

vikash kumar   10 years AGO

p(f)+p(e)-p(f)p(e)=0.41

Like? Yes (1) | No   

Neel Patel   10 years AGO

0.25(0.7)+0.3*(0.75)=0.40
so ans. option 10

Like? Yes (1) | No   

Sayanta Chowdhury   10 years AGO

P(E)+P(F)-2P(EF)=0.55-0.28=0.27

Like? Yes (1) | No   

ANKIT SHARMA   10 years AGO

P(e U f)=p(e)+p(f)-p(e n f)=0.41

Like? Yes (1) | No   

S.SHAFI   10 years AGO

P(EUF) = P(E) + P(F) - P(E^S)

P(EUF) = 0.25 + 0.30 - 0.14 = 0.41

Like? Yes (1) | No   

DIPAK TIWARI   10 years AGO

P(A∩B) = P(A) + P(B) - P(A∪B)
=.25+.30-.14
=.41
Option 10

Like? Yes (2) | No (1)  

ANUP KUMAR   10 years AGO

P(E)=0.25, P(F)=0.30, P(E & F)=0.14
SO, P(E or F)=P(E)+(F)-P(E & F) = 0.25+0.30-0.14=0.41

Like? Yes (1) | No   

Suganya   10 years AGO

p(E)=0.25
p(F)=0.30
p(EnF)=0.14
p(EUF)=p(E)+p(F)-p(EnF)
=0.25+0.30-0.14
=0.41 is the answer

Like? Yes (1) | No   

sai naveen vanapalli   10 years AGO

0.25+0.3-0.14=0.41

Like? Yes (1) | No   

vipul gupta   10 years AGO

because answer will be 0.25+0.30-0.14=0.41

Like? Yes (1) | No   

Tark Patel   10 years AGO

P(EUF) = P(E) + P(F) - P(E ^ F) = 0.25 + 0.30 - 0.14 = 0.41

Like? Yes (1) | No   

Pradeep Saw   10 years AGO

p(e)+p(f)-p(e&f)=>
0.25+0.30-0.14=0.41

Like? Yes (1) | No   

RISHIKA GUPTA   10 years AGO

ans is 0.425 ,happening of any one event out of two.

Like? Yes (1) | No   

saimeera   10 years AGO

either e or f must occur.
so it is ef'+e'f=0.25*0.7+0.3*0.75=0.40

Like? Yes (1) | No   

TUSHAR    10 years AGO

0.41

Like? Yes (1) | No   

Neha V   10 years AGO

the formula to be used is:
P(E U F) = P(E) +P(F) - P(E (INTERSECTION) F)
= 0.25+0.30-0.14
= 0.41

Like? Yes (1) | No   

Mani kandan   10 years AGO

p(E U F) = p(E) + P(F) - p(E ^ F) so .25+.30 -.14 = .41

Like? Yes (1) | No   

Pramod Gaikwad   10 years AGO

P(E or F) = P(E) + P(F) - P(E and F)
P(E or F)=0.25+0.30-0.14
=0.41

Like? Yes (1) | No   

Rahul Rathod   10 years AGO

p(E or F)=P(E)+P(F)-P(E and F)
=0.25+0.30-0.14
=0.41
so probability that either E or F will occur is 0.41

Like? Yes (1) | No   

KESANI ADINARAYANA   10 years AGO

P(e+f)=p(e)+p(f)-p(e&f)
i.e. 0.3+0.25-0.14=0.41

Like? Yes (1) | No   

sumit   10 years AGO

0.25+0.30-0.14=0.41 option(10)

Like? Yes (2) | No (1)  

Ankit Sirohi   10 years AGO

P(E)=0.25 and P(F)=0.30 and P(E and F)=0.14
so P(E or F)=P(E)+P(F)-P(A and B)= 0.25+0.30-0.14=0.41

Like? Yes (1) | No   

Jhilik Sil Sarma   10 years AGO

(0.25+0.30)-0.14=0.41

Like? Yes (1) | No   

Shubham Ghosh   10 years AGO

probabilityt that either e occurs or f occurs is P(e) + P(f) - 2* P(eintf)

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

Ans 10

Like? Yes (1) | No   

surya   10 years AGO

x=0.25+0.30-0.14=0.41

Like? Yes (1) | No   

Dinesh thatti   10 years AGO

p(E U F) = p(E) + P(F) - p(E ∩ F) so .25+.30 -.14 = .41

Like? Yes (1) | No   

Nomendra Sinha   10 years AGO

P(a or b)=P(a)+P(b)-P(a and b)
=0.25+0.3-0.14=0.41

Like? Yes (1) | No   

T.VIGNESWARA REDDY   10 years AGO

0.55 0.14 0.41

Like? Yes (1) | No   

NIVEDA SIVAPRAKASAM   10 years AGO

0.41

Like? Yes (1) | No   

B.Sriteja   10 years AGO

ans is 0.41

Like? Yes (1) | No   

sarthak garg   10 years AGO

.25+.30-.14

Like? Yes (1) | No   

urvish   10 years AGO

p(E U F) = p(E) + P(F) - p(E ^ F) so .25+.30 -.14 = .41

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

Answer must be -
0.25 + 0.30 - 0.14 = 0.41
so option 10 is correct.

Like? Yes (1) | No   

syed soheb   10 years AGO

not in the option

Like? Yes (1) | No   

kumar aryan   10 years AGO

required probability is =p(a)+p(b)-p(a intersectiob b)=0.41

Like? Yes (1) | No (1)  

Pallekonda Rajesh   10 years AGO

ans:0.25+0.3-0.14=0.41

Like? Yes (1) | No (1)