A man riding a cycle at 12 km/hr can reach a village in 9/2 hours. If he is delayed by 3/2 hours at

Supriya Mondal   10 years AGO

Speed of the man is 12km/hr and he takes 9/2 hr i.e 4.5 hr.
So total distance is=12*4.5=54km
Due to delay he looses 3/2hr i.e 1.5 hr.
So time in hand is=(4.5-1.5)=3 hr to reach the destination.
So speed needed to reach the destination in time=(54/3)=18km/hr.
So option 4)18 hr is the right answer

Like? Yes (9) | No (5)  

P.Pandeeswari   10 years AGO

distance=12*9/2 =54,
speed=54/(9/2-3/2) == 18 km/hr

Like? Yes (8) | No (4)  

Saranjit Singh   10 years AGO

Distance = 12*9/2= 54 kms
speed for reaching destination in (9/2-3/2=3 hrs) = 54/3= 18 kmph

Like? Yes (2) | No   

SAYAN CHATTERJEE   10 years AGO

distance = s= v*t= 12*9/2=54 km
now delaying by 3/2 hours he has (9/2-3/2)=3 hours time
so. v= s/t'
= 54/3
= 18 km/hr (4)

Like? Yes (1) | No   

Surit Datta   10 years AGO

According to the question
A man riding a cycle at 12 km/hr can reach a village in 9/2 hours
So the total distance covered is (12*9)/2
which is 54 km
If he is delayed by 3/2 hours at the start
so distance covered by (9/2-3/2) = 3 hour is 54 km
So in order to reach his destination in time
he should ride with a speed 54/3 = 18 km/hr
So option 4
That's it.

Like? Yes (5) | No (4)  

Sagar Jadhav   10 years AGO

speed=12kph
time=4.5hr
so, dist=12*4.5 = 54km
and delay is 1.5 hr
means he has to reach in 3 hrs
so new speed is 54/3 = 18kph

Like? Yes (1) | No   

Abhishek Porwal   10 years AGO

Distance=12*9/2 = 54,
speed=54/(9/2-3/2) = 18 km/hr

Like? Yes (1) | No   

alamuri vijaya sekhar reddy   10 years AGO

his journey distance = 12*9/2 = 54 km

new journey time after time reduction = 9/2 - 3/2 = 3 hours

his new speed = 54/3 = 18 km/hr

Like? Yes (1) | No   

K.NagaSugunaManasa   10 years AGO

distance=speed*time
distance=x;
time=9/2;
speed=12km/hr
so x=12*(9/2)=54
now x=second speed*second time
now 54=s*(9/2-3/2)
s=18km/hr
so option is 4

Like? Yes (1) | No   

Lakhan Nagrale    10 years AGO

12 *9/2=54
in 4.5 hrs he goes 54 km
after 3/2 i.e 1.5 hr delay he has to cover same distance in
4.5-1.5=3 hours
thus 54/3=18 km/hr

Like? Yes (1) | No   

Mithun Kumar Kesari   10 years AGO

18 km/hr

Like? Yes (1) | No   

Yuvaraj   10 years AGO

Total distance to be traveled at 9/2 hours = 12*(9/2)
= 54 kms

9/2 = 4.5 hours.. 3/2 = 1.5 hours.
Time need to travel same distance is 4.5-1.5 = 3 hrs.

Distance to travel for 3 hours for time = 54/3
= 18km/hr

Like? Yes (1) | No   

kiran nekkanti   10 years AGO

Total distance to be travelled is 54 km
he is delayed by 1.5 hours
so,he has to travel to destination in 3hours
speed=distance/time=54/3=18

Like? Yes (1) | No   

Sahil Thakral   10 years AGO

from speed = 12km/hr and time = 4.5hr, distance = sp*t = 54km
Now dis=54 km/hr, time = 9/2-3/2hr = 6/2hr = 3hr ,
so speed = dis/time = 54/3 = 18km/hr

Like? Yes (1) | No   

APPIKONDA SANTOSH NAIDU   10 years AGO

18km/hr

Like? Yes (1) | No   

guru   10 years AGO

Total distance traveled= 12x9/2= 54 km
If he is delayed by 3/2 hours at the start, then he has to cover the distance in 9/2-3/2=6/2=3 hours.
So the speed he needs to travel at = 54/3=18 km/hr

Like? Yes (1) | No   

A.Vignesh Guru   10 years AGO

distance=12* 9/2 =54Km
actual speed= 54 / ( (9/2)-(3/2) ) =18 km/hr

Like? Yes (1) | No   

Abhishek Singh   10 years AGO

becuase distance to cover is 54 km and he need to cover it in 3 hr then speed should be 18 km/hr

Like? Yes (1) | No   

jatin arora   10 years AGO

12*9/2*1/3

Like? Yes (1) | No   

JUHI RAI   10 years AGO

D=12*9/2=54km
new speed=54/3=18km/hr

Like? Yes (1) | No   

Sravanthi   10 years AGO

d=s*t

Like? Yes (1) | No   

khushboo goenka   10 years AGO

distance is 12*9/2= 54 km'
so new speed = 9/2-3/2=3
so speed will become 54/3

Like? Yes (1) | No   

pallavi kumbhar   10 years AGO

Total distance he have to travel=12*4.5=54km
speed to reach within 3 hour=54/3=18km/hr

Like? Yes (1) | No   

niraj   10 years AGO

3*18=12*9/2

Like? Yes (1) | No   

komal kumar bandi   10 years AGO

9/2*12=54
9/2-3/2*18=54

Like? Yes (1) | No   

b.subbarao   10 years AGO

cycle speed=12 km/hr, time taken for reach the destination=9/2 hrs,destination distance=9/2*12=54 km. after delaying 3/2 hrs, the remaining time is 3 hrs. so the speed of the cycle=d/t=54/3=18 km/hr

Like? Yes (1) | No   

siddharth prakash singh   10 years AGO

distance=speed*time
so, D=12*(9/2)=54km
delayed by 3/2 hr means remaining time = 3 hr.
required speed= 54/3= 18kmph

Like? Yes (1) | No   

THUMMALA VINEESHA   10 years AGO

dis=sp*time=12*(9/2)=54 km
time=tot-delay=(9/2)-(3/2)=3 hrs
sp=d/t=54/3=18 km/hr

Like? Yes (1) | No   

jitendra kumar   10 years AGO

distance=speed*time
distance is constant here
s1*t1=s2*t2
s1=12 t1=9/2 t2=9/2-3/2=3
s2=18km/hr

Like? Yes (1) | No   

Asim Dinda   10 years AGO

(12*9/2)/(9/2-3/2)=18

Like? Yes (1) | No   

Rishabh   10 years AGO

12 km/h* 9/2 hr is total distance which is 54 km.now divided by remaining time which is 3 hr so 54/3=18km/hr ans.

Like? Yes (1) | No   

susanta   10 years AGO

s=v*t
=12*9/2
=54
t=9/2-3/2
=3
now, 54=v*3
v=18 km/hr

Like? Yes (1) | No   

Gaurav Sharan   10 years AGO

dist = 12*(9/2)= 54
or, 54= v*(4.5-1.5)
v= 18

Like? Yes (1) | No   

Harshabh Srivastava   10 years AGO

this is answer

Like? Yes (1) | No   

VISHNU   10 years AGO

Distance = speed x time
here,
speed = 12km/hr and time = 9/2hrs

so D = 12 x 9/2
= 54
delay of 3/2 which means new time is 9/2 - 3/2 = 3

54 = speed x 3
speed = 54/3
= 18 km/hr

Like? Yes (1) | No   

abhishek   10 years AGO

dist=12*9/2
=54
now time=9/2-3/2
=6/2=3Hrs
speed=54/3
=18Km/hr.

Like? Yes (1) | No   

ABHAS TIWARI   10 years AGO

the distance to be covered = 12 * 9/2 = 54 km
time available = 9/2 - 3/2 = 3 hrs
therefore the required speed should be = 54/3 = 18kmph

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

d=4.5*12=54km
speed=54/(4.5-1.5)=18km/hrs

Like? Yes (1) | No   

Pankaj Kumar Mishra   10 years AGO

A/Q, Speed = 12 km/hr
Time = 9/2 hrs
So, Distance = Speed * Time
=> Distance = 12 * 9/2 = 54 km

Again,
Since he is 3/2 hrs delayed,
So he has 9/2 - 3/2 hrs = 3 hrs to reach destination.

So, Required Speed = Distance / Time
= 54 / 3 km/hr
= 18 km/hr
= Option (4) Answer

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

time delayed =9/2-3/2=3hr
he has to complete 54 km in 3 hr.
so his speed will be s*3=54
s=18km/hr
ans...

Like? Yes (1) | No   

Nagesh   10 years AGO

12 km/hr = D/(9/2).
D = 54 km

new Speed = 54/(9/2-3/2) = 18km/hr

Like? Yes (1) | No   

Abdul kadir khan   10 years AGO

18 km/hr

Like? Yes (1) | No   

lavanya   10 years AGO

distance=12*9/2 =54, speed=54/(9/2-3/2) == 18 km/hr

Like? Yes (1) | No   

aman   10 years AGO

from- dis = time*speed

dis = 12*9/2 = 54km
then
time req = 9/2-3/2 = 3hr
speed = 54/3 = 18km/hr

Like? Yes (1) | No   

Vinay Sipani    10 years AGO

Speed = 12 kmph in 9/2 = 4.5 hrs
=> distance = 4.5 * 12 = 54 km

He delays 1.5 hrs
Remaining time = 3 hrs
=> Required speed = 54 / 3 = 18 kmph

Like? Yes (2) | No (2)  

Md.Sultan Khichi   10 years AGO

D=12*9/2=54 km
Time remaining =9/2-3/2=3 hr
Speed =d/t=54/3=18
Ans ob 4.

Like? Yes (1) | No (1)  

Akhil Malhotra   10 years AGO

Speed of man=12kmph
Time taken=9/2 hrs=4.5 hrs
Distance=12*4.5=54km

Time delay=3/2 hrs=1.5 hrs
Time left=4.5-1.5=3 hrs
Distance =54km
So new speed= 54/3= 18kmph

Like? Yes (6) | No (6)  

Ashwin Dinesh   10 years AGO

using v = d/t
d=54, t=3 then v = 18
which is option 4)

Like? Yes (1) | No (1)  

A M ANKIT KALLURAYA   10 years AGO

s=12kmph
t=9/2hr d=st=12*9/2=54km
d=s(t-3/2)
54=s(9/2-3/2)
=>s=18kmph

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

Option)4

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

d = 12* 9/2 = 54 km

s = 54 / (9/2 -3/2) = 18 km/h

Like? Yes (1) | No (1)  

Pradyumna K S   10 years AGO

Let d km be the distance to be covered. Given that d km is covered within 9/2hr in the speed of 12 km. Then d=12*9/2km=54km. If he by delayed by 3/2hthen to reach by the time he should reach within 3hr.therefore required speed is 54/3kmph=18kmph 4th option

Like? Yes (4) | No (4)  

Aarti Galar   10 years AGO

Ans. is 18 km/hr
as we know that Speed = Distance/Time
=> Distance = Speed x Time Distance is same in both the cases therefore,
12 x 9/2 = s x 6/2
54 = s x 3
s = 18 km/hr

Like? Yes (1) | No (1)  

Sanu Panji   10 years AGO

distance = 12*9/2 =54 km
time = 9/2- 3/2 = 3 hr
speed = 54/3 = 18 km/hr

Like? Yes (2) | No (2)  

priti sagar   10 years AGO

total distance=12km/hr * 9/2hr
=54km
3/2 hr is passed so remaining time required to complete 54 km is 9/2hr-3/2hr=3hr
so,speed =54km/3hr
=18km/hr

Like? Yes (3) | No (3)  

NITHYA   10 years AGO

speed=dist/time

=12/9/2=54 km

he is delayed by 3/2. so he should take the time of (9/2-3/2=6/2)

actual speed= 54/6/2=18 km

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   10 years AGO

Distance= 9/2*12= 54 KM
So, time after 3/2 hrs of late tart wii be= 9/2- 3/2= 6/2= 3 hrs. i.e in 3hrs He has to travel 54 KM. So, now required time would be= 54/3= 18 km/hr. Hence option 4 is right

Like? Yes (1) | No (1)  

MRITUNJAY   10 years AGO

distance=12*9/2=54 km
time to cover distance after delay is 4.5-1.5=3 hr
speed to cover distance in 3 hrs=54/3=18km/hr
that is option 4.

Like? Yes (1) | No (1)  

Yekollu Muneeswar   10 years AGO

given, 12 km/hr*9/2hr= 54km

he delayed 3/2 hrs means he having 9/2hr-3/2hr=3hr time

54km in 3 hr means=> 54km/3hr=18km/hr

so option 4) 18km/hr

Like? Yes (2) | No (2)  

Ajinkya Kulkarni   10 years AGO

54km
Time req 3hr
So speed 54/3=18

Like? Yes (2) | No (2)  

Faisal JAffry   10 years AGO

Total distance= 12*9/2;
= 54 Km;
Time Delayed=3/2;
Therfore total time= 9/2-3/2=3 hrs;
Hence Speed = 54/3==> 18 km/hr;

Like? Yes (1) | No (1)  

viveka subraya bhatta M.S   10 years AGO

distance =12*9/2 =54 km
due to delay, time left =9/2-3/2 = 3 hours
required speed = 54/3 =18 km/hours

Like? Yes (1) | No (1)  

PAWAN KUMAR   10 years AGO

Distance = 12*9/2 = 54km.
Time of travel = 3 hours
Therefore, speed = 54/3 = 18 kmph. Ans.

Like? Yes (1) | No (1)  

pappu kumar priye   10 years AGO

total distance=(12*9)/2=54 km
remaining time after delay=9/2-3/2=3hrs
so speed =54/3=18km/hr

Like? Yes (1) | No (1)  

RAVI KUMAR   10 years AGO

total distance = 9/2*12=54
time remaining = 9/2-3/2= 3
req speed = 54/3
= 18 km/hr

Like? Yes (1) | No (1)  

Sheetal Ghutukade   10 years AGO

the distance is 54km. so if we are starting 3/2 hrs late then we have only 3hrs in hand so speed will be 54/3=18km/hr

Like? Yes (2) | No (2)  

BHASKAR MANDAL   10 years AGO

12*4.5 = x * (4.5-1.5 )
=> x = 18

Like? Yes (1) | No (1)  

Satya B   10 years AGO

12 km/hr time to reach 9/2 hrs
distance traveled= 12*9/2= 54 km
delayed by 3/2 hrs the remaining time left to reach on time is
9/2hrs - 3/2 hrs = 6/2 hrs
seed=distance/time
speed=54/(6/2)
=54*2/6
=18km/hr ans

Like? Yes (2) | No (2)  

jassi   10 years AGO

D=s*T

D=12*(9/2)=54

T=9/2-3/2=6/2

S=54/(6/2)=18km/h

Like? Yes (1) | No (1)  

Jagdish Joshi   10 years AGO

d=4.5 * 12 = 54 km
reduced time = 9/2- 3/2 = 3 hrs
s=54/3 = 18 km /hr

Like? Yes (1) | No (1)  

Ankit   10 years AGO

Distance=speed*time=12*(9/2)=54km
late by 3/2 hr so time left is 9/2-3/2=6/2=3 hrs
tehrefore, new speed will be distance/time=54/3=18km/hr

Like? Yes (1) | No (1)  

swarupa nuggu   10 years AGO

18

Like? Yes (1) | No (1)  

Dibakar Mandal   10 years AGO

D = 54km
s=54/3=18km/hr

Like? Yes (1) | No (1)  

ASHISH MITTAL   10 years AGO

distance=speed*time
distance= 12*9/2 =54km
now new time=(9/2) - (3/2) =3 hours
so new speed = 54/3 = 18 km/hr

Like? Yes (2) | No (2)  

vikram   10 years AGO

dist= speed *time
d=12*9/2=54kms
as his start was delayed by 3/2 hrs, then the remaining time to reach the destination in right time is 9/2-3/2= 6/2 hrs
now speed = distance /time
S=54/6/2=18Kmph.

Like? Yes (1) | No (1)  

Suganya   10 years AGO

s=12km/hr
t=4.5hrs.
d=128*4.5=54km
4.5-1.5=3
so speed =54/3=18
speed is 18km/hr

Like? Yes (1) | No (1)  

Raghwendra Sharan   10 years AGO

total distance covered in first scenrio is
12*4.5 = 54KM
if delayed by 1.5 hrs, then need to cover 54 KM in 3 hrs
so the speed should be 544/3 = 18KM/HR

Like? Yes (1) | No (1)  

LOKESH KUMAR   10 years AGO

Speed of cycle=12kmph
Time man takes=4.5hrs
Total distance man covers
=12kmph*4.5hrs
=54kms
Man is delayed by 1.5hrs.
Remaining time he has
=4.5-1.5hrs.
=3hrs.
So, Speed needed to cover the same distance in 3hrs.
Speed=54km/3hrs.
=18kmph.

Like? Yes (1) | No (1)  

sravani   10 years AGO

Giveen speed is 12 Kmph
Time taken is 9/2hr
so, dist is 12*9/2=54km
time tobe taken is 9/2-3/2=3hr
dist=54Km
speed =54/3=18Kmph

Like? Yes (1) | No (2)