What is the next number of the following sequence 54, 21, 3, 9, 81,.......

Balasaheb Rathod   9 years AGO

ans is 9
4^2=16+5=21
1^2=1+2=3
3^2=9+0=9
9^2=81+0=81
1^2=1+8+9

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Supriya Mondal   9 years AGO

1st term is 54
So, 2nd term is=5+4^2=21
then, 3rd term=2+1^2=03
then,4th term=0+3^2=09
then,5th term=0+9^2=81
So, next term will be=8+1^2=9
So, option 7)9 is the right answer

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Surit Datta   9 years AGO

here the next number can be formed by,
second number's square + first number
like,
4^2 + 5 = 21
1^2 + 2 = 3
3^2 + 0 = 9
9^2 + 0 = 81
1^2 + 8 = 9
so option 7
that's it.

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anusha   9 years AGO

ans is 7 ie 9

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sompon temtheerakij   9 years AGO

21 = 5*4+1
3 = 2*1+1
9 = 3*3
81 = 9*9
9 = 8*1+1

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ABHINAV PUSHPAM   9 years AGO

(No. At units place)^2+no. At tens place
So answer is 9. I.e. option 7)

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Meenakshi   9 years AGO

square of unit digit+digit in ten's place
option 7

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KALYAN KUMAR REDDY VALLURU   9 years AGO

(1's digit)^2 + (10's digit) = next number

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madhusudhana   9 years AGO

54
5x4=20 + 1 = 21
2x1=2 + 1 = 3
3x3=9
9x9=81
8x1=8 + 1 = 9

In case of 2 digit number, split and multiply them and then add 1
In case of single digit number, just multiply with itself.

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Yallapu Uday tarun kumar   9 years AGO

(No at unit's place)^2+number at ten's place
so ans is 9.

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devendrachary   9 years AGO

9

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rakhi kumari   9 years AGO

5+4^2=21
2+1^2=3
0+3^2=9
0+9^2=81
8+1^2=9

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SAGNIK PAL   9 years AGO

[(Number at units place)^2 + number at tens place]
So the correct answer is 9.

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Jaspalsingh Parmar   9 years AGO

option 7 is correct

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jaganmohan rao .pola   9 years AGO

9

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KUMAR HARSH   9 years AGO

second digit ^2 +first digit =next number
4^2+5=16+5=21
1^2+2=1+2=3
3^2+0=9+0=9
9^2+0=81+0=81
1^2+8=1+8=9

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aman aditya   9 years AGO

4^2=16+5=21
1^2=1+2=3
3^2=9+0=9
9^2=81+0=81
1^2=1+8+9

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sandeep ramchandra pawaskar   9 years AGO

option 7 is correct

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saranya sankar   9 years AGO

second digit ^2 +first digit =next number
4^2+5=16+5=21
1^2+2=1+2=3
3^2+0=9+0=9
9^2+0=81+0=81
1^2+8=1+8=9
ans is 9

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sudarshan arya   9 years AGO

Next Outcome = Unit's digit ^ 2 + Ten's digit
As,
4^2+5 = 21
1^2+2 =03
3^2+0 =09
9^2+0 =81
Hence,
1^2+8 =09

Like? Yes (2) | No (1)  

karthik hariharan   9 years AGO

54
4²+5=21
1²+2=3
3²+0=9
9²+0=81
1²+8=9
So the next number is 9.

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SUSHANT KUMAR   9 years AGO

5+4^2=5+16=21
2+1^2=2+1=3
0+3^2=9
0+9^2=81
8+1^2=9

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sairamesh   9 years AGO

second digit ^2 +first digit =next number
4^2+5=16+5=21
1^2+2=1+2=3
3^2+0=9+0=9
9^2+0=81+0=81
1^2+8=1+8=9 ans 9..,option 7

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surbhi mittal   9 years AGO

second digit^ 2 + first digit= next number
4^2 + 5= 21
1^2+ 2=3
3^2 + 0= 9
9^2 +0 = 81
1^2 + 8= 9
so, 9 is the answer

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RAKESH   9 years AGO

54 : 5 + 4^2 = 21

81 : 8 + 1^2 = 9

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tasho k   9 years AGO

Sqr of second digit +first digit

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pooja L   9 years AGO

second digit ^2 +first digit =next number

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manali jain   9 years AGO

second digit ^2 +first digit =next number
4^2+5=16+5=21
1^2+2=1+2=3
3^2+0=9+0=9
9^2+0=81+0=81
1^2+8=1+8=9
ans is 9

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Thirupathi Reddy   9 years AGO

second digit ^2 +first digit =next number
4^2+5=16+5=21
1^2+2=1+2=3
3^2+0=9+0=9
9^2+0=81+0=81
1^2+8=1+8=9
ans is 9

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Thirupathi    9 years AGO

second digit ^2 +first digit =next number
4^2+5=16+5=21
1^2+2=1+2=3
3^2+0=9+0=9
9^2+0=81+0=81
1^2+8=1+8=9
ans is 9

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RAVI KUMAR   9 years AGO

second digit^2+first digit=next number
1^2+8=9

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CHAYAN KUMAR   9 years AGO

54,21,3,9,81
21=4*4+5
3=1*1+2
9=3*3+0(we can write 3 as 03)
81=9*9+0(we can write 9 as 09)
we can see that next no= ((2nd digit of previous no)^(2nd digit of previous no)+1st digit of previous no))
therefore the required no is (1*1+8)=9

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Jay parmar   9 years AGO

option 7 is correct

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