Ten years ago A was half of B in age. If the ratio of their present ages is 3:4 what is the sum of t

Surit Datta   9 years AGO

Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.

Like? Yes (13) | No (6)  

Vijendra singh   9 years AGO

ratio of present age is 3:4
so age let it 3x and 4x
10 years ago age was- (3x-10)=(4x-10)/2;
so x=5
so current age is 3x and 4x
3*5 =15 and 4*5=20
then sum is 35 .
option is 3

Like? Yes (8) | No (1)  

Supriya Mondal   9 years AGO

10 years ago age of A=5 and B=10
Now, age of A=15 and age of B=20
So,sum of their age is =15+20=35
So, option 3)35 is the right answer

Like? Yes (15) | No (8)  

Balakumaran N.A   9 years AGO

Let the present age of P and Q be 3x and 4x respectively.

Ten years ago, P was half of Q in age

=> (3x – 10) = ½ (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5

total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

Like? Yes (9) | No (2)  

neelabh   9 years AGO

Let there present age be 3x & 4x.
Than
2(3x-10)=(4x-10)
2x=10
x=5.
There fore A present age =15 & B present age= 20
15+20=35

Like? Yes (3) | No   

Debraj Ghosh   9 years AGO

suppose today there age is 3x,4x respectively
so 10 years ago their age was (3x-10),(4x-10) respectively
Now, according to the question
(3x-10)=(4x-10)/2
=>6x-20=4x-10
=>2x=10
=>x=5
so today their present age=(3*5+4*5)=35

Like? Yes (3) | No   

Srinivas   9 years AGO

it is the answer a:b = 1:2 before
present a:b = 3:4
change is 2 parts..so 1 part = 5 yrs
Present 3+4 = 7 parts = 7*5=35

Like? Yes (2) | No   

Mehul D Parmar   9 years AGO

age of A and B 10 years ago be x and 2x years respectively

so,
x+10/2x+10=3/4

4(x+10)=3(2x+10)

4x+40=6x+30

10=2x

x=5


then sum of their ages=(5+10)+(2*5+10)=35

so ans is 3 option are 35

Like? Yes (3) | No (1)  

santhosh   9 years AGO

3x,4x are the present ages of a&b,
ten years ago so, 3x-10=1/2(4x-10)
3x=10+2x-5
x=5
3x+4x=35years

Like? Yes (3) | No (1)  

ADERU CHENCHU NITHISH   9 years AGO

Let the present age of P and Q be 3x and 4x

Ten years ago, P was half of Q in age
=> (3x – 10) = ½ (4x – 10)
=> 6x – 20 = 4x – 10
=> 2x = 10
=> x = 5
so total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

Like? Yes (2) | No (1)  

ABHINAV PUSHPAM   9 years AGO

Let the present age of P and Q be 3x and 4x respectively.



Ten years ago, P was half of Q in age

=> (3x – 10) = ½ (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5



total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

Like? Yes (3) | No (2)  

K.M.AYESHA SHARMIL JAHAN   9 years AGO

from the question,
A-10=(B-10)/2
A:B=3:4
by soiving,we get B=20 & A=15
A+B=35

Like? Yes (1) | No   

k sureshbabu   9 years AGO

change in ratio is 2 parts i,e
after 10 years 1:2 changes to 3:4
so 2 parts is equal to 10 years 1p=5 years
3p+4p=7p so 7*5=35years

Like? Yes (3) | No (2)  

Yathiraj   9 years AGO

from the given data,
A-10 = (B-10)/2
which can be written as 2A-B=10
Also, their present age ratio i.e. A:B=3:4 => B = (4A)/3 -> Substitute this in above equation to derive A
2A - (4A/3) = 10
A=15
B=4A/3 = 20
So, the sum of their current age will be 15+20=35.

Option 3.

Like? Yes (2) | No (1)  

MRITUNJAY   9 years AGO

10 years ago age of A is x and B be 2x
present age be x+10
and 2x+10
x+10/2x+10=3/4
x=5
present age be 15 1nd 20
so total age is 20+15=35

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

Let the ages of A and B 10 years ago be x and 2x years.
then, (x+10)/(2x+10) =3/4
so, x=5
sum of their present ages = (x+10) + (2x+10) =35 years.

Like? Yes (1) | No   

kiruthika   9 years AGO

let age of A be x and b becomes 2x and ratio given is 3:4 by adding A and B to 10 for present ages
the equation becomes
x+10/2x+10=3/4
by solving x is 5
now a and b is 15+20=35

Like? Yes (1) | No   

RAVAL   9 years AGO

their age ratio is 3:4
so before 10 years, a=b/2
ans .35 yrs
present age is 15 & 20 yrs

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

A and B are present ares
2(A-10) = B-10....1
3/4 = A/B......2
by solve these two equations
A = 15 , B = 20
A+B = 15+20 = 35

Like? Yes (1) | No   

Gaurav Singla   9 years AGO

3X-10/4X-10=1/2 A/B=3/4
6X-4X=10
X=2

Like? Yes (1) | No   

sainath   9 years AGO

(3x-10)=(1/2)*(4x-10)
x=5

3x+5x=15+20=35

Like? Yes (1) | No   

Srinutha Dasaroju   9 years AGO

10 years ago ages are A,2A.
present (A+10) : ((B=2A)+10)=3:4
(A+10) / (2A+10)=3/4
2A=10
A=5 thus B=10.
Present their ages will be 15 and 20. Sum= 35

Like? Yes (1) | No   

pratap kumar sahoo   9 years AGO

A-10=(1/2)(B-10);---------------------------(1)
A:B=3;4;
A=(3/4)B
putting in eq(1),
B=20;
A=15;
A+B=35

Like? Yes (1) | No   

Ayan Patra   9 years AGO

Let current age of A be 3x and that of B be 4x.
10 years ago A was half the age of B.
So, 3x - 10 = (4x - 10)/2
or, x = 5
Therefore the sum of their current age is 3x + 4x = 3*5 + 4*5 = 35.

Like? Yes (1) | No   

Muhammad Nadeem Haider Naseem   9 years AGO

Let the present age of A and B be 3x and 4x respectively.



Ten years ago, A was half of B in age

=> (3x – 10) = ½ (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5



total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

Like? Yes (1) | No   

Dharshana   9 years AGO

Ten years before :
(A-10)=(B-10)/2 ; so rearranging the equation 2A-B=10
Present ratio:
A:B = 3:4
rearranging the equation 4A-3B=0; sloving both B= 20 and A= 15 . so sum of their present age is 35.

Like? Yes (1) | No   

B.venkata suresh   9 years AGO

3x,4x
x=5
sum=3*5+4*5=15+20=35

Like? Yes (1) | No   

M,MATHIVANI   9 years AGO

10 years before, A's age is 5 and B's age is 10. presently A and B's ages are 15 and 20 respectively,Hence their present ratio is 3:4. therefore the answer is 35

Like? Yes (1) | No   

saket kumar   9 years AGO

because let present age of A is 3x and b is 4x,
10 years ago.... 3x-10=(4x-10)/2
therefore x=5
hence 3x+4x= 35

Like? Yes (1) | No   

Atishay jain   9 years AGO

we have to choose that sum of ages that is satisfaction for this question....
if we choose 35 then we have sufficient answer.. becoz this question says ten years ago.. so there are two person A and B . so we have to subtract 20 .. then see the remaining answer which is in ratio of 1:2.. then add 10 yrs per candidate .. then saw the ratio of 3:4 between A and B....
so 35 is accurate.......

Like? Yes (1) | No   

SURESH   9 years AGO

A-10=(1/2)(B-10) ----- (1)
A/B=3/4----------(2)

2A-20=B-10---FROM(1)
4A=3B-----FROM(2)

FROM(1) * 2

4A-40=2B-20
3B-40=2B-20....USING RESULT FROM(2)

B=20
A=15
TOTAL=35

Like? Yes (1) | No   

kshitij   9 years AGO

distribution 15+20
10 years back
a =5 , b=10
ratio of current = 3:4

Like? Yes (1) | No   

varsha   9 years AGO

1. (A-10)=.5×(B-10)
2. 4A=3B
by solving 1&2
A=15 B=20
A+B=35

Like? Yes (1) | No   

Kamlesh Kumar   9 years AGO

let age is x in present
10 year ago (x-10)=(2x-10)
ratio is 3:4
(x-10)/(2x-10)=3/4
4x-40=6x-30
2x=10
x=5
=>5*3+5*4
35

Like? Yes (1) | No   

Srinivas Rao   9 years AGO

A-10 = 1/2(B-10)
2A-20 = B- 10
2A-B=10--------- (1)

A/B= 3/4
4A=3B
4A-3B = 0 --------(2)
SOLVING EQUATIONS 1 AND 2 U WILL GET
A=15 years
SO B=20 YEARS (AS RATIO GIVEN, MULTIPLY BY 5)
SO SUM = 35 YEARS

Like? Yes (1) | No   

Aakash   9 years AGO

let present ages be 3x and 4x.
so, (3x-10) = (4x-10)/2
we get x =5;
hence sum of present ages is 7x = 35

Like? Yes (1) | No   

Sara Banova   9 years AGO

A was x years old
B was 2x years old
x+10/2x+10=3/4
x=5
=> A is 15
B is 20
A+B= 35

Like? Yes (1) | No   

Surendhar Ramanujam   9 years AGO

let A's present age be x and B's present age be y
Then before 10 years' {(x-10)=(y-10)/2}
Also x:y=3:4 Therefore by substituting x=(3y/4) in the above equation we get y=20 and subtituting y value we get x=15
Therefore sum of the ages is x+y=20+15=35

Like? Yes (1) | No   

vishal chandrola   9 years AGO

x is age age A
y is age of B
x:y=3:4
x-10=(y-10)/2
evaluating
x=15
y=20

Like? Yes (1) | No   

kinchit trivedi   9 years AGO

let a=x and b=y; then from question we form two equations. 4x=3y and 2x-y=10; so x=15 and y=20

Like? Yes (1) | No   

aman aditya   9 years AGO

10 year ago:
a=5
b=10
so now,
a=15
b=20
a+b=35

Like? Yes (1) | No   

kishor Mali   9 years AGO

let present age be 3x and 4x...
10 year ago...(3x-10)=(4x-10)/2
x=5
a is 15 year and b is 20 year sum is 15+20=35

Like? Yes (1) | No   

Shiva Sharma   9 years AGO

A-10 = (B-10)/2
2A-20 = B-10
multiply by 2
4A-40 = 2B-20 ...........1
A/B = 3/4
4A = 3B
put in first eq.1
3B-40 = 2B-20
B = 20
A = 15
A+B = 35

Like? Yes (1) | No   

Divyansh jaiswal   9 years AGO

suppose ages 10 yrs ago a=x then b=2x

current (x+10)/(2x+10)=3/4 x=5 current ages a=15 yrs b=20yrs sum is 35

Like? Yes (1) | No   

Thanakkumar T   9 years AGO

We have 3x and 4x ages now 7x is their sum so exactly 35 is divisible by 7 so 35 is the answer.

Like? Yes (1) | No   

thendral   9 years AGO

x , 2x are ages of A and B 10years ago.
So, x+ 10/2x+10 = 3/4
2x= 10 x=5
Sum of present ages (5+10)+(10+10)
= 35 years

Like? Yes (2) | No (1)  

geeta   9 years AGO

let suppose the present age of A and B be x and y respectively
... 10 yrs before, A's age is (x-10) and is 1/2 that of B's age i.e (y-10)... and present age's ratio i.e x/y = 3/4 . solving 2 equations we get x=15 and y=20 ... sum of their ages = 15+20=35

Like? Yes (1) | No   

Deepak kushwaha   9 years AGO

in present their ages in ratio 3:4
let A's age be 3x
and B's age be 4x
10 years ago
their ages A=3x-10 & B=4x-10
and we know 10 years ago A=B/2------(1)
put these value of A & B in eqn (1)
we get x=5
A=15 & B=20
total is 35

Like? Yes (1) | No   

Chetan Arya   9 years AGO

two equations
2(A-10)=(B-10)
and A=(3/4)A
after solving them
A=15 and B=20
So Answer is 35

Like? Yes (1) | No   

kishor anap   9 years AGO

go back 10 yrs...consider ages as a=x, b=2x
after 10 yrs :
(a+10) /(b+10) = 3/4
i.e. (x+10) /(2x+10) = 3/4
solving gives x=5,

so now a= 5+10 = 15, b=20
sum = 35

Like? Yes (1) | No   

Urvashi Jain   9 years AGO

A was half of B x, 2x
10 years ago
x+10/2x+10=3/4
x=5
so A IS 5 and B is 10
sum of present age is 5+10+10+10=35

Like? Yes (1) | No   

hemant jain   9 years AGO

let the ratios be x.
then present age of a=3x and b=4x
ten years ago ages of a=2*age of b
=> 3x-10=2*(4x-10)
on solving we get x=5
that means present age of a=3x=15 years
and that of b=4x=20 years
therefore the sum of ages will be(present)=15+20=35 years

Like? Yes (1) | No   

mohita verma   9 years AGO

let 3x and 4x be the present age of A and B respectively
10 years ago,
3x-10=(1/2)(4x-10)
x=5
sum of present age=3x5+4x5=35 years

Like? Yes (1) | No   

bipro biswas   9 years AGO

x/y=3/4
x-10=(y-10)/2
solving x=15
y=20
x+y=35

Like? Yes (1) | No   

AMMU TESSA JOSEPH   9 years AGO

let the ages of A and B 10 years ago be x and 2x respectively
then, x+10/ 2x+10 =3/4
=> 2x=10
x=5
then sum of their present ages=(x+10)+(2x+10)=35
thus the ans is 35 years

Like? Yes (1) | No   

Mounis Swaleh   9 years AGO

present age of A:B = 3x:4x
after 10 years
3x-10 = (4x-10)/2
x=5
A=15, B=20
A+B=35

Like? Yes (1) | No   

Vishnu Varthan A   9 years AGO

A-10=1/2(B-10)=>2A-B=10
given present ages in ratio 3:4
total age be x
A=3x/7, B=4x/7 on substituting in first line, we get x=35

Like? Yes (1) | No   

Shreya Maiwal   9 years AGO

Let present age of A=x
and that of B =y
Given x/y=3/4
10 yrs ago, age of A would have been x-10
and that of B=y-10
Given 10 yrs ago age of A is 1/2 of B hence
x-10=1/2(y-10)
after solving we get y=20 i.e. age of A
and x=15 i.e. age of B hence x+y=35

Like? Yes (1) | No   

ammar   9 years AGO

Let the present ages of A and B be 3x and 4x respectively.
According to given conditions,we have
2(3x-10) = 4x-10
2x = 10
x = 5
Therefore,
A's present age = 3x5 = 15
B's present age = 4x5 = 20
Sum of their ages = 15 + 20 = 35

Like? Yes (1) | No   

Karthick Raja   9 years AGO

10 years ago age ratio of A & B is
A=(B/2)

present age A+10:B+10 = 3:4
A+10/B+10 = 3/4
4A+40=3B+30
B=2A
4A-6A=30-40
-2A=10
A=5
B=10
Present ages of A 15
Present age of B 20
Sum of present ages 35

Like? Yes (1) | No   

Akash Dinkar   9 years AGO

10 years ago, Let B's age=x years
According to Question, A's will be of age=x/2 years
for present ages:
x/2+10/(x+10)=3/4
On solving,
x=10
So, Ans=10+5=15 years

Like? Yes (1) | No   

sourav pal   9 years AGO

Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.

Like? Yes (1) | No   

Gaurab Kumar Jha   9 years AGO

let the age ten year ago be x and 2x
(x+10)/(2x+10)=3/4
x=5
therefore the present age will be 15 and 20 and the sum will be 35

Like? Yes (1) | No   

Kajal Gupta   9 years AGO

present ages be 3x and 4x
and 10 yrs ago ,so eq will be
((3x-10)/(4x-10))=1/2
by solving this we get present age as 15 and 20 yrs and sum is 35 yrs

Like? Yes (1) | No   

Ramdas Singathiya   9 years AGO

a-10=(b-10)/2 .........................(1)
a= 3b/4 ...................................(2)

solving equation (1) and (2)
a=15 , b=20 so a+b= 35

Like? Yes (2) | No (2)  

RAKESH   9 years AGO

2*(3x-10) =(4x-10)
or, x = 5
sum of present ages = 7x = 7*5 = 35

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

A-10=(B-10)/2 or 2A-B=10 ---(i) and
A/B=3/4 or 4A=3B ---(ii)
Solving (i) & (ii), A=15, B=20
So A+B=15+20=35
Answer is option (3)

Like? Yes (1) | No (1)  

Ayush Gupta   9 years AGO

Let present ages be A and B
Ten years before
2(A-10)= B-10
at present 4A=3B
solve this and get A and B

Like? Yes (2) | No (2)  

Venkatesh kadali   9 years AGO

10 years ago A age is half of b age i.e
A : B=1:2
present ages of A and B is A:B=3:4
difference of ratios is 2
2----->10
1------->5
sum of their present ages is=(3+4)*5
= 7*5
=35

Like? Yes (1) | No (1)  

SANTOSH   9 years AGO

Let their ages Ayrs,Byrs
10yrs ago, their ages (A-10)yrs, (B-10)yrs
Conditions,
(A-10) = (B-10)/2
and A/B = 3/4

By solving we get A=15, B=20

A+B=5

Like? Yes (1) | No (1)  

Math Lovers   9 years AGO

(A-10)/ 2 = (B-10)
=> 2A - B = 10 -------------------- (1)

now, A/B = 3/4
=> B = 4A/3

putting the value in eqn (1)

=> 2A/3 = 10
=> A =15
=> B = 4A/3 = 20
A+B = 35 years

Like? Yes (1) | No (1)  

Chirag Jindal   9 years AGO

A-10=(B-10)/2 where A and B are present ages.
Also,A:B=3:4

solving above 2 relations give A=15 and B=20
therefore,
A+B=35

Like? Yes (1) | No (1)  

viswambher   9 years AGO

let the ages of A and B 10 years ago be a,b respectively where
a=b/2 and ten years the ages will be a+10 and b+10 which are in the ratio 3:4.
so 4(a+10) = 3(b+10) and a=b/2 .
on solving the two equations we get b=10.
hence the present age of B=20 whereas present age of A=15 , therefore the sum of their ages is 35

Like? Yes (1) | No (1)  

Lavanya Rajendran   9 years AGO

(A-10)=1/2(B-10) , A/B = 3/4 , A /2A-10= 3/4 , A= 15 , 5=1/2(B-10),B=20 , 20+15=35

Like? Yes (1) | No (1)  

shivaprabhu   9 years AGO

A-10=(B-10)/2

A/B=3/4

A=(3/4)B

solving
we get A=15 B=20 so A+B=35

Like? Yes (1) | No (1)  

sravani   9 years AGO

from given question
A will be 20
B will be 15
A+B=35 Years

Like? Yes (1) | No (1)  

asim   9 years AGO

Let present age be A and B respectively ,
10 years ago (A-10) = (B-10)/2 ..............................(i)
present ratio is A : B :: 3 : 4
=> 4A = 3B .....................................................................(ii)

on solving eq (i) and (ii) ,
we get
B = 20 => A = 15

A + B = 15 +20 = 35 i.e. option 3

Like? Yes (1) | No (1)  

Rakesh Kumar Thakur   9 years AGO

Let present age of A & B be 3x & 4x respectively.
10 yrs ago, according to given condition

(3x-10)=(4x-10)/2;
solving the above equation , we get x=5;
Therefore present age of A & B is 15yrs & 20yrs..
sum=15+20=35yrs

Like? Yes (1) | No (1)