Ticket numbered from 1 to 20 are mixed up and a ticket is drawn at random. What is the probability t

Abhishek   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7,14}.

P(E) = n(E)/n(S) = 8/20

P(E) = 2/5.

Like? Yes (27) | No (1)  

mohita verma   9 years AGO

total outcome=20
favorable outcome={3,6,9,12,15,18,7,14}
i.e 8
therefore,
probability=8/20=2/5

Like? Yes (19) | No (3)  

darladiwakar   9 years AGO

3 or 7=3,6,9,12,15,18, 7,14
total=20
probability=8/20=2/5

Like? Yes (5) | No (1)  

Ravi shankar   9 years AGO

multiples of 3 are 3,6,9,12,15,18.
multiples of 7 are 7 ,14
total prob=6/20+2/20=2/5

Like? Yes (4) | No (1)  

Deepthi   9 years AGO

between 1 to 20 multiples of 3:
3,6,9,12,15,18----------------6
multiples of 7:
7,14-------2
total 8 numbers
probability :8/20=2/5

Like? Yes (3) | No   

chandrika.k   9 years AGO

there are 8 possibilities such that the number is either multiple of 3 or 7...out of 20 possibilities...so ans is 8/20 i.e 2/5

Like? Yes (3) | No   

asim   9 years AGO

from number 1 to 20 ,
multiples of 3 are : 3,6,9,12,15,18
& multiples of 7 are : 7,14
i.e. given total numbers = 20
and total number of possible outcomes = number of multiples of 3 + number of multiples of 7
=> = 6 + 2
=> = 8

therefore , probability of 1 card drawn at random = no of possible outcomes / total number
= 8 / 20 = 2 / 5 i.e option 3

Like? Yes (3) | No   

Billal Hossain   9 years AGO

Here, S = {1, 2, 3, 4, 5,6,7,8,9,10,11,12,13,14,15,16,17,18,19, 20}.
Let E = event of getting a multiple of 3 or 7 = {3, 6 ,7, 9, 12, 14,15, 18}.
P(E) =n(E)/n(S)=8/20=2/5(ans)

Like? Yes (3) | No   

Veerraj Chauhan   9 years AGO

total multiples of 3 in between 1-20 = 6
total multiples of 7 in between 1-20 = 2
probability = (6+2)/20= 8/20= 2/5

Like? Yes (3) | No (1)  

Pranati Kundu   9 years AGO

3,6,9,12,15,18,7,14
so total is 8 events and sample space is 20
so 8/20
2/5

Like? Yes (2) | No   

RAJAT KHANDELWAL   9 years AGO

A be that no of cards that are multiple of 3=6
B be that no of cards that are multiple of 7 =2
total no of cards =20
Probability that cards drawn is either multiple of 3 or multiple of 7 = P(A) u P(B)
=P(A) + P(B) +P(A^B)
= 6/20 + 2/20 +0=8/20=2/5

Like? Yes (4) | No (2)  

lokesh   9 years AGO

multiples of 3 or 7 are 3,6,9,12,14,15,18

probability = favourable outcome / total outcome
= 8/20
= 2/5

Like? Yes (2) | No (1)  

DEEPAK RAJ   9 years AGO

Multiple of 3 = 3,6,9,12,15,18
So, P(Multiple of 3) = 6/20

Multiple of 7 = 7, 14
So, P(Multiple of 7) = 2/20

Total Probablity = 6/20+2/20 = 2/5 Ans

Like? Yes (1) | No   

Ramdas Singathiya   9 years AGO

3,6,7,9,12,14,15,18 => 8/20= 2/5

Like? Yes (1) | No   

Vivek   9 years AGO

Total number of tickets=20
Number of ticket with multiple of 3=6
Number of ticket with multiple of 7=2
Number of ticket with multiple of 2 or 7=8
Probability has number which is multiple of 3 or 7=8/20
=2/5
Therefore the option is 3)

Like? Yes (3) | No (2)  

Shiva Sharma   9 years AGO

total tickets = 20
ticket which are multiple of 3 or 7 are 3,6,7,9,12,14,15,18
total is 8
so probability = 8/20
=>2/5

Like? Yes (2) | No (1)  

SAGAR BAGCHI   9 years AGO

total possible outcomes are from 1 to 20 i.e 20.
favourable outcomes are:-(3,6,7,9,12,14,15,18)=8
so,probability=8/20=2/5 -option (3).

Like? Yes (1) | No   

ABHINAV PUSHPAM   9 years AGO

The numbers divisible by 3 or 7 are - 3,6,7,9,12,14,15 & 18. i.e total 8.
so, probability = 8/20. = 2/5
option 3)

Like? Yes (2) | No (1)  

vamsi krishna   9 years AGO

numbers mulitiples of 3 or 7 is 8
sample space is 20
ans 8/20=2/5

Like? Yes (1) | No   

BADRI LAL JAT   9 years AGO

multiple of 3=6 and 7=2 so total is 8 number. so probablility is 8/20=2/5. ok.

Like? Yes (1) | No   

sravani   9 years AGO

there are 8 numbers in 1 - 20 which are multiples of 3,7
3,6,9,12,15,18,7,14,,,
so probability is 8/20=2/5

Like? Yes (1) | No   

Urvil shah   9 years AGO

The probability of getting 3 is 6/20 .and getting 7 is 7/20.so 6/20+2/20=2/5

Like? Yes (2) | No (1)  

Nikhil chavan   9 years AGO

3,6,9,12,15,18 and 7, 14
8/20=2/5

Like? Yes (1) | No   

Archie   9 years AGO

Here,
S={1,2,3,4......20}
Let
Event= multiple of 3 or 7
={3,6,9,12,15,18,7,14}
P(E)=(n(E)/S(E))
=8/20=2/5
Hence option 3 is correct :)

Like? Yes (1) | No   

Chandrima Goswami   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}
Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7,14}
P(E) = n(E) / n(S) = 8/20 = 2/5
So ans is option 3)

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

n(s)= 20
n(E)= {3,6,7,9,12,14,15,18}
n(E) = 8
P = 8/20= 2/5

Like? Yes (1) | No   

kanithi.shanmukharao   9 years AGO

multiples of 3 are =3,6,9,12,15,18 =>6.
multiples of 7 are =7,14 =>2.
so 6+2=8,there is no common multiple..
probability=8/20 =2/5..

Like? Yes (1) | No   

SOMA NARESH   9 years AGO

multiples of 3 and 7 from 1 to 20 are 3 6 7 9 12 14 15 18
Total number of multiples of 3 or 7 = 8
Probability = 8/20 = 2/5

Like? Yes (1) | No   

Rajanikanta Pradhan   9 years AGO

Multiple of 3 in 20 is 3,6,9,12,15,18
Multiple of 7 in 20 is 7,14
Probability of multiple of 3= 6/20
Probability of multiple of 7=2/20
6/20+ 2/20 = 8/20
= 2/5

Like? Yes (1) | No   

JYOTI CHHABRA   9 years AGO

Multiple of 3 is 3,6,9,12,15, 18 and multiple of 7 is 7,14 till 20 so probability is 8/20 i. e. 2/5

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Rohit Kumawat   9 years AGO

Answer is : 2/5
Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 7, 14}.

P(E) = n(E)/n(S) = 8/20 = 2/5

Like? Yes (1) | No   

Pranjal   9 years AGO

calculate the multiples of 3 and 7 less then 20 they are 3,6,7,9,12,14,15,18 total number are 8
so probability is 8/20
so 2/5

Like? Yes (1) | No   

prabhat gupta   9 years AGO

multiple of 3 : 3,6,9,12,15,18
multiple of 7 : 7,14

so prob = multi(3)+multi(7) / total = 8/20 = 2/5

Like? Yes (1) | No   

Dinesh Kumar Kumawat   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 7, 9, 12, 14, 15, 18}.

P(E) = n(E)/n(S) = 8/20 = 2/5

Like? Yes (1) | No   

MD IRSHAD ALAM KAMAR   9 years AGO

Here,ticket numbered from 1-20
multiple of 3 : 3,6,9,12,15.18
multiple of 7: 7,14
hence,p=(6+2)/20

Like? Yes (1) | No   

praveendas   9 years AGO

total of cases=20
no of favourable cases =8
8/20=2/5

Like? Yes (1) | No   

BASWARAJ K PATIL   9 years AGO

S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7, 14,}.

p(E) = n (E)/ n(s) = 8/20= 2/5

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SANTOSH   9 years AGO

multiples of 3,7 are 3,6,7,9,12,14,15,18

probability 8/20
=> 2/5

Like? Yes (1) | No   

A M ANKIT KALLURAYA   9 years AGO

the ticket can be 3,6,9,12,15,18,7,14=8
total no of tickets=20
P=8/20=2/5

Like? Yes (1) | No   

NIRAVKUMAR PRAVINBHAI PATEL   9 years AGO

Probability of getting 3 is 6/20
and
probability of getting 7 is 2/20
so answer is =6/20+2/20=2/5

Like? Yes (1) | No   

Piyush Telang   9 years AGO

P(multiple of 3) or P(3x) = 6/20
P(multiple of 7) or P(7x) = 2/20
P(Total) = P(3x) + P(7x) = 2/5

Like? Yes (1) | No   

Soma Naresh   9 years AGO

multiples of 3 or 7 are {3,6,9,12,15,18}{7,14}= 8
total numbers = 20
probability=8/20 =2/5

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vivek   9 years AGO

Toal favorable numbers are- 3,6,7,9,12,14,15,18=8
So required probability is 8/20=2/5

Like? Yes (1) | No   

POOJA SINGH   9 years AGO

S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7,14}.

P(E) = n(E) /n(s)=8/20=2/5 .

Like? Yes (1) | No   

Suganya   9 years AGO

n(s)=20
P(a)=6/20
P(b)=2/20
P(a)+P(b)=2/5

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sreelakshmi   9 years AGO

Multiples of 3 - 6/20
Multiples of 7 - 2/20
total=6/20+2/20=2/5

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

n(s)=20
multiples of 3=20/3
=6
multiples of 7=20/7
=2
n(p)=2+6
=8
p=8/20
p=2/5

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Lavanya Rajendran   9 years AGO

no of multiples of 3 between 1 to 20 is 6 and for 7 is 2 so probability is 6/20 + 2/20 = 2/5

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santosh kumar patel   9 years AGO

ticket no 1 to 20 = 1 , 2 , 3 , 4 , 5 , 6 ,7,8,9,10,11,12,13,14,15,16,17,18,19,20

multiple of 3 = 3,6,9,12,15,18
multiple of 7 = 7,14
total = 8
probability= 8/20= 2/5

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DINESHKUMAR   9 years AGO

possibility of 3 is 3,6,9,12,15,18 and possibility of 7 is 7,14
so 8/20=2/5

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vijay shankar   9 years AGO

for 3, possible outcome...3,6,9,12,15,18
so probability =6/20
for 7....7,14
so probabality 2/20
so total prob. due to (or)=6/20+2/20=2/5

Like? Yes (1) | No   

Dinni   9 years AGO

3, 6, 9, 12, 15, 18 are multiples of 3
7, 14 are multiples of 7
Total=8
Probability=8/20=2/5.

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sai krishna koppaku   9 years AGO

Mutiples of 3 or 7-3,6,9,12,15,18,7,14
Total probability -8/20
. -2/5

Like? Yes (1) | No   

jalaj   9 years AGO

possible outcomes for multiple of 3 is 3,6,9....18=6 for multiple of 7=7,14 =2
6+2=8 for multiple of 3 or 7
total outcomes=20
Therefore,P=8/20=2/5

Like? Yes (1) | No   

Gaurav Sikka   9 years AGO

no. of multiples of 3 between 1 and 20 are 6
no. of multiples of 7 between 1 and 20 are 2
therefore, total no. of elements in sample space is 8
probability is 8/20 i.e. 2/5

Like? Yes (1) | No   

suraj nath prasad   9 years AGO

multiple of 3 b/w 1-20=3,6,9,12,15,18
multiple of 7=7,14
so probability=8/20=2/5

Like? Yes (1) | No   

Anubhav jain   9 years AGO

possible events are =7(3*1,3*2,3*3,3*4,3*5,3*6,7*1,7*2)
totalevents are=20
then prob. is =8/20=2/5

Like? Yes (1) | No   

Dheeraj Bhatia   9 years AGO

there are 6 multiple of 3 between 1 to 20 and 2 multiple of 7. and there is an or condition which means either it shoulb be the multiple of 3 or the multiple of 7 so we will add 6+2=8/20=2/5

Like? Yes (1) | No   

Sambit Pal   9 years AGO

the probability is an 'or' case of selecting 1 card among 6 of 3's multiple or 2 of 7's multiple.... i.e 8/20=2/5

Like? Yes (1) | No   

Dhanraj Wanjare   9 years AGO

3 or 7
total number of cases = 20 tickits
and favrbl number of cases
(20/3=6 and 20/7=2 and 21 is more than 20 so leave it)
probability = f/t
p= 6/20+2/20;
p=8/20
p=2/5
so option 3 is satisfied

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Hardeep Sidhu   9 years AGO

multiples of 3 are 6 + multiples of 7 are 2=8
8/20= 2/5

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venki vemuri   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 7,9, 12, 14,15, 18}.

P(E) = n(E) = 8/20=2/5 .
n(S) 20

Like? Yes (1) | No   

syed kashif ullah   9 years AGO

3,6,9,12,15,18--->6
7,14---> 2
fav/ total= 6+2/20
=8/20=2/5
hence optiin 3

Like? Yes (1) | No   

RAKESH ARYA   9 years AGO

mul. of 3 in 20 = 6
mul of 7 in 20 = 2
mul of (3*7) in 20= 0

hence , total possible cases = 8

probability = 8/20
= 2/5

Like? Yes (1) | No   

sravani podipireddy   9 years AGO

No. of multiples of 3 & 7 from 1 to 20 are
3,6,7,9,12,14,15,18

So , probability = 8/20 = 2/5

Like? Yes (1) | No   

MUKESH   9 years AGO

total number,n(s)=20
let A be multiple of 3 =3,6,9,12,15,18
let B be multiple of 7 =7,14
n(A)=6
n(B)=2
p(A or B)=(P(A)+p(B))/20
therefore answer is 2/5

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Cp Choudhary   9 years AGO

8/20

Like? Yes (1) | No   

Rajeshkumar   9 years AGO

n(s)=20
P(a)=6/20
P(b)=2/20
P(a intersect b)=0
Therefore,
P(a+b)=(6/20)+(2/20)-0
=8/20
=2/5

Like? Yes (1) | No   

akshay ishwarkar   9 years AGO

total event=t
no. of getting multiple of 3 & 7=n={3,6,7,9,12,15,14,18}
probability=n/t
=8/20=2/5

Like? Yes (1) | No   

Shantanu Udapure   9 years AGO

probability for multiple of 3= 6/20
probability for multiple of 7=2/20
probability = (6/20) + (2/20) = 2/5

Like? Yes (1) | No   

RUPALI DADHE   9 years AGO

S={1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}
Let E= events of getting a multiple of 3 or 7
= {3, 6, 9, 12, 15, 18, 7, 14}
P(E)=n(E)/n(S)
=8/20
=2/5

Like? Yes (2) | No (1)  

Akshay Bhandakkar   9 years AGO

probability for multiple of 3= 6/20
probability for multiple of 7=2/20
probability = (6/20) + (2/20) = 2/5

Like? Yes (1) | No   

PAVAN HATWAR   9 years AGO

probability for multiple of 3= 6/20
probability for multiple of 7=2/20
probability = (6/20) + (2/20) = 8/20=2/5
the probability for multiple of 3 or 7 = 2/5

Like? Yes (1) | No   

ajit kumar sharma   9 years AGO

S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 7, 14}.

probability P(E)=n(E)/s(E)=8/20=2/5

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jyothsna   9 years AGO

3,6,9,12,15,18,7,14 are multiples of 3 or 7.hence 8/20 i.e.,2/5 is the answer

Like? Yes (1) | No   

ezhilane   9 years AGO

since ply.of multiple of 3=6/20 and ply.of multiple of 7 is 2/20
and both are added so ans is 2/5

Like? Yes (1) | No   

Gaurav Singh   9 years AGO

Multiples of 3 --> 3,6,9,12,15,18
Multiples of 7--> 7,14

favourable events -->8
Total events--> 20

probability of 3 or 7 = 8/20 = 2/5

Like? Yes (1) | No   

shashi   9 years AGO

multiple of 3 nd 7 are n(e)= 3,6,9,12,15,18,7,14
n(s)=20
p(s)=8/20
=2/5

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nitin   9 years AGO

There are total 8 favourable outcomes i.e. 3,6,9,12,15,18,7,14 out of 20 possible outcomes So, 8/20 i.e 2/5.

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shyamala   9 years AGO

multiples of 3: 6
multiples of 7: 2
6+2=8
total cards 20
probability= 8/20
ans:2/5

Like? Yes (1) | No   

arti kumari   9 years AGO

total probablity = 20
require = 3,6,7,9,12,14,15,18(8)
it means = 8/20=2/5

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harman kaur   9 years AGO

6 numbers divisible by 3 nd 2 by 7..
i.e
(6+2)/20=2/5

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Aravinth kumar   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7,14}.

n(E) = 8 .
n(S) = 20
p(E)=8/20
=> 2/5

Like? Yes (2) | No (2)