The length and breadth of a square are increased by 30% and 20% respectively. The area of the rectan

Ankush Surana   9 years AGO

100*100=10000
130*120=15600
% increase= (15600-10000)/ 10000*100=56%

Like? Yes (9) | No (3)  

Sushmita Ghanty   9 years AGO

let length and breadth of the square is 100 m
the area of square is= 100*100= 10000 m^2
new length of the rectangle is=130 m
new breadth of the rectangle is=120 m
area if the rectangle is 130*120=15600 m^2
therefore, The area of the rectangle so formed exceeds the area of the square by (15600-10000)/10000*100=56%

Like? Yes (5) | No (1)  

sudiptaa   9 years AGO

let side of square = 100
len of rect = 130
bre of rect = 120
area of rect= 130 * 120 = 15600
area of square = 10000
too much = 5600
in % = (5600 *100)/10000
= 56 %

Like? Yes (7) | No (3)  

Devendra Marghade   9 years AGO

If original length & breadth are 'x' & 'y' respectively, then Area=x*y
If increased length=x*130/100=1.3x and
increased breadth=y*(120/100)=1.2y then
New Area=(1.3x)*(1.2y)=1.56xy
% increase in Area=100*(1.56xy-xy)/xy=56
Option 10)

Like? Yes (2) | No   

Deepak kumar kumawat   9 years AGO

let length and breadth are 10x
now increased length and breadth 13x and 12x
so (13x)*(12x)-100x=56x
required %= 56x/100x=0.56*100=56%

Like? Yes (2) | No   

Tarang gupta   9 years AGO

let the length be 'L' & breadth be 'B'....so area is L*B
now the length is increased by 30%of the original length
so new length =1.3L
similarly breadth=1.2B
new area =1.3L*1.2B=1.56LB
area increased=.56
%=(.56/100)*1=56%

Like? Yes (2) | No   

Aamir Beriwala   9 years AGO

first the area of square is lxb
then area of rectangular is 1.3l x 1.2b
so ans. is 1.56 lxl which is 56% of square

Like? Yes (2) | No   

Dubey Nandini M   9 years AGO

Say Len of Square=2 and Breath of square=2
area=(side)2=4

len of rectangle incre by 30%
terefore, 2+2*30/100= 13/5

Breath of rectangle incre by 20%
terefore, 2+2*20/100= 12/5

area=l*b=156/5

let ap=exceeds % of area
so,
4+4*ap/100=156/25
solving above equation we get
ap=56%

Like? Yes (2) | No   

sainath somisetty   9 years AGO

consider length and breadth of rectangle as 100 and 100 then area=10000
as the length increases by 30% hence length is 130
as the breadth of rectangle is increased by 20% then breadth is 120 then area=15600.
difference in area=5600
percentage increase in area=(5600/10000)*100=56%

Like? Yes (2) | No   

Manish Kumar Rana   9 years AGO

initially
area of rectangle = l*b = lb
after increment in length and breadth
length = 1.3l
breadth = 1.2 b
area= 1.3l*1.2b= 1.56lb
% increment= (1.56lb-lb)*100 = 56 %

Like? Yes (2) | No   

KajriSingh   9 years AGO

assume the side of square =x
length of rectangle=130x/100
breadth of 120x/100
area of square=x^2
area of rectangle=130x/100*120x/100=(39x^2/25)-x^2

i.e. 14x^2/25

increased percentage of area of rectangle is (14x^2/25)*100=56%

Like? Yes (2) | No   

Priya Dharshini   9 years AGO

for eg :
let us take length as 100m;
and Breadth as 100m;
so the area of the square is 10,000sq.m;


now....length is increased by 30% & breadth is increased by 20%

so,length=130;
breadth=120
Area of Rectangle=L*B
which is 130*120=15,600;


to find the exceeded percentage
(5600/10000)*100=56%

Like? Yes (2) | No   

Altaf Hussain   9 years AGO

If the sides of square are increased by 30% and 20% then the sides will be 1.3 and 1.2 times. On calculating area of the rectangle 1.3*1.2=1.56. Hence the area is increased by 56%.

Like? Yes (1) | No   

shashank verma   9 years AGO

Area 1+X%=area2
10000+X%=15600
x=56
56% is answer

Like? Yes (1) | No   

gopiraju   9 years AGO

100*200=20000
(100+30)*(200+40)=31200
change is=(31200-20000)/20000=0.56
now %=0.56*100=56%

Like? Yes (1) | No   

SOUVIK   9 years AGO

suppose previously length was x and breath was y.so area xy.now after increasing it became 13x/10 and 12y/10 respectively.so area is 156xy/100 .so increament is 56%

Like? Yes (1) | No   

Kethineni Vinodh   9 years AGO

side of square=x
then length=1.3x
breadth=1.2x
area of rectangle=1.3x*1.2x=1.56x^2
area of square=x^2
so 56%

Like? Yes (1) | No   

Nishith HM   9 years AGO

let l=10 b=10 area now is 100(l*b)
after increasing l=12 n b=13 area is 156 total increase is 56%

Like? Yes (1) | No   

Naveen Tiwari   9 years AGO

The lenght and breadth are incresed by 30% and 20% , hence square become rectangle...
Area of rectangle i=L*B
after increasing
the new area=1.3*1.2=1.56
hence changes in area is 56% increase..

Like? Yes (1) | No   

jaya   9 years AGO

area of rectangle exceed area of square by=
area rectangle -area of square
area of rectangle = (130b/100)(120b/100)
area of square=b*b
=(156(b*b)/100) - (b*b)
=56% (b*b)
i.e. 56% of area of square

Like? Yes (1) | No   

sneha sri   9 years AGO

let x be the side of a square
then dimensions of rectangle are 1.3x and 1.2x
area exceeded by 56%

Like? Yes (1) | No   

mithilesh kumar   9 years AGO

a1=l*b
a2=(130/100*l)*(120/100*b)
=156/100*l*b
=156/100*a1
So 56% increase

Like? Yes (1) | No   

kartik dolas   9 years AGO

let l-length,b-bredth.initialy area be a=l*b
now acording to conditn let new area be A=(l+30l/100)(b+20b/100)=13*12/100lb=1.56lb=1.56a...(as a=lb)
now,%change=(A-a)/a*100=56%

Like? Yes (1) | No   

jasbir kaur   9 years AGO

with 30% increase the area becomes 130, further 20% increase makes it 156, so (156-100)/100=56%

Like? Yes (1) | No   

karan minocha   9 years AGO

let
length=x
breadth=x(as it is a square)
new length= 1.3x (as it is increased by 30%)'
new breadth=1.2x (as it is increased by 20%)'
therefore area of rectangle exceeds = 1.3*1.2=1.56 (56%)

Like? Yes (1) | No   

chinna madhu   9 years AGO

let the squre be 10*10=100 after changes 13*12=156
so the percentage change is 56%

Like? Yes (1) | No   

phani krishna   9 years AGO

l1=b1=y,a1=(y*y).....l2=1.3y,b2=1.2y,a2=(1.3y)*1.2y=(1.56*y*y).%increase=((1.56-1)*y*y)*100/(y*y)=56

Like? Yes (1) | No   

Madhurima Bhattacharyya   9 years AGO

let 100 be the length and breadth of square.then length and breadth of rectangle be 130 and 120 resp.area of sq=10000 and that of rect=15600.inc in area is 5600.then percentage inc in area is 56%

Like? Yes (1) | No   

anubhav kumar gupta   9 years AGO

actual area of rectangle=l*b
after transformation area=1.3l*1.2b=1.56
difference in area=1.56lb-1lb=0.56lb
% increase=(difference/actual area)*100=56%

Like? Yes (1) | No   

nikita gupta   9 years AGO

initial length = l units
initial breath = b units
initial area = l*b sq units
increased length = 13/10 units
increased breadth = 6/5 units
new area= 39/25 l*b sq units
so, increased area = 56%

Like? Yes (1) | No   

RAGNI RUPAM   9 years AGO

let side of square,s=100
area= 10000
new length, l=130
new breadth, b=120
area of rectangle= 15600
diff= 5600
%diff = (5600*100)/10000

Like? Yes (1) | No   

Kuheli   9 years AGO

increased area =( 130X * 120Y)/100*100
so (156/100 - 1 )XY = 56XY/100
so percent is 56 percent

Like? Yes (1) | No   

vamsi   9 years AGO

Assume l=10 and b=10
when l is increased by 30% and b is increased by 20%,then the l becomes 10+3=13 and b becomes 10+2=12
Hence area of rectangle is 13*12=156 i.e 56% more than area of square i.e 100

Like? Yes (1) | No   

M Nikhil kumar   9 years AGO

Assume the initial values of square as 100,100
Increased values are 130,120 and hence the final area is 15600
it is increased by 56%

Like? Yes (1) | No   

poojasaisri   9 years AGO

length increased by 1.3
breadth increased by 1.2
area will increase by 1.3*1.2=1.56
=56%

Like? Yes (1) | No   

lokesh kumar   9 years AGO

let 100 be the side of square.
old area=100*100=10000
new area formed = 130*120=15600
%age area=(15600-10000)/10000 *100= 56%

Like? Yes (1) | No   

pankaj kumar   9 years AGO

let length is 1 and breadth is 1 then increment in both is
as follow .3 & .2 then area after increment will be 56%

Like? Yes (1) | No   

Sanjeeb Chatterjee   9 years AGO

let length of sq be x unit.
therefore area of sq is x^2 unit.
now length and breadth exceeds by 30% and 20% then
length becomes 13x/10 unit and breadth 12x/10 unit.
area becomes 156x^(2)/100 unit.
area increases by {(156x^2)/100 - x^2}*1/x^2*100=56%

Like? Yes (1) | No   

Avik Das   9 years AGO

Previous area 10000. After change it becomes 15600. So, percentage increase by 56. option 10 is correct.

Like? Yes (1) | No   

Gyanranjan   9 years AGO

let the sides of the square be 100 units
so length and breadth of the rectangle will be 130 & 120 units
so area of rectangle =15600 units^2 and area of the old square =10000 units^2
%increase=((15600-10000)/10000)*100%=56%

Like? Yes (1) | No   

Priyanjay Kumar   9 years AGO

net increase =
a+b+(a*b)/100
where a is % increase in first quantity and b is % increase in second quantity .

Like? Yes (1) | No   

momin ashraf ahamed   9 years AGO

assume side of square as 10,
30% increase in side=13
20% increase in side =12
area of original square =10*10=100
area of increased square=12*13=156
therefore increase in area =156/100*100=156
therefore increase in %=156-100=56%

Like? Yes (1) | No   

Karthick Raja   9 years AGO

assume the side of the square is 100 units
so area is 10000
Length increase by 30% & width increase by 20%
so Length is 130 width is 120
area=130*120=15600

area increased =
(15600-10000)*100/10000
=56%.

Like? Yes (1) | No   

Prabakaran   9 years AGO

consider 100m be side of square
so area is 10000
length is 130m (30% increase)
breadth is 120m(20% increase)
area is 15600
area of rectangle exceeds by square is (5600/100)%=56%

Like? Yes (1) | No   

Juhi Gupta   9 years AGO

let the length & breadth of rectangle be x & y.
original area=xy m2
new length=130x/100
new breadth=120y/100
new area=156xy/100
156xy/100-xy/100=56xy/100
increase%=([56xy/100]*[1/xy]*100)
56%

Like? Yes (1) | No   

deepak kumar   9 years AGO

area after increment is 1.2*1.3=1.56of previous area
hence increment in % is=56%

Like? Yes (1) | No   

Akarsh Kumar   9 years AGO

increasing the sides by 30% and 20 % gets your length and breadth as 1.3s and 1.2s , assuming side of the square to be s.
1.2s*1.3s=1.56s^2 increasing the area to 56%

Like? Yes (1) | No   

Subhodeep Ghosh   9 years AGO

If length is suppose a and breadth is suppose b then Formula is: (a+b+((a*b)/100))=(30+20+(600/100))=56

Like? Yes (1) | No   

manasa   9 years AGO

new length=a+(30/100)a=(13/10)a
new breadth=b+(20/100)b=(6/5)b
rectangle area=(13/10)a*(6/5)b=(78/50)ab=(ab+(28/50)ab)
=>ab+(56/100)ab
=>ans=56%

Like? Yes (1) | No   

satyam kumar   9 years AGO

let area be 100 .den increase in 30 % is 130 and then increase of 20 % of 130 is 156 ..so 56% is d %change..

Like? Yes (1) | No   

Rupa Kumari   9 years AGO

Let, length=x, bredth=x,
original Area of square =x*x;
New area=(x+0.3x)*(x+0.2x) =(1.56 x^2)m^2;
Area increment=[ (1.56 x^2- x^2)/x^2] *100= 56%

Like? Yes (1) | No   

AASTHA MITTAL   9 years AGO

new area=(l+.03l)*(b+0.2b)
=1.56lb
%age increase=(1.56-1)/1
=0.56
i.e. 56 %

Like? Yes (1) | No   

kumaravel   9 years AGO

assume lenth of a side of square be 100,so it's area is 10000(area of square=a^2)..if length is increased by 30%,then lenth becomes 130,breadth is increased by 20% it becomes 120.so the area of rectangle is 15600(arae of (rectangle =l*b) ,so difference ia area is (15600-10000=5600)..(therefore (5600/10000)*100=56%)

Like? Yes (1) | No   

Naveen Chaudhary   9 years AGO

% increase in area=[a+b+(a*b)/100] %
=[30 +20+(30*20)/100]%
=[50+600/100]%
= (50+6)= 56 %

Like? Yes (1) | No   

pratik avinash   9 years AGO

New L=13/10l
new B=6/5b
therfore area incresed = 156/100
therefore 56%

Like? Yes (1) | No   

Kajal Manohar Roshni Rangwani   9 years AGO

Area of square= l*l
Area of rectangle=(l+30/100*l)*(l+20/100*l)=156l^2/100
%increase= %(area of rectangle-area of square)

Like? Yes (1) | No   

anushka bansal   9 years AGO

length = L
breadth = B
area = LB
new length = 1.30L
new breadth = 1.20B
new area = (1.30L)*(1.20B)
= 1.56LB
therefore 56% increase

Like? Yes (1) | No   

Prabhat Burnwal   9 years AGO

x'=x(1+20/100)
y'=y(1+30/100)
new area=x'*y'
%age increase=(new area-old area)/old area*100

Like? Yes (1) | No   

Mugesh sivagnanam Krishnapillai   9 years AGO

Let the sides of square be 1 unit .
then Area =1 sq.unit.
After increase,the length and breadth would be 1.3 & 1.2
so area=1.56 sq.unit
Hence increase in area =( (1.56-1)/1)*100=56%.

Like? Yes (1) | No   

jomon v j   9 years AGO

let length=100
breadth =100
then area =10000
now the length is increased by 30% ,then length =130

breadth =120

area =15600

change in area =5600

% in increase = (5600/10000)*100=56

Like? Yes (1) | No   

abhishek kumar singh   9 years AGO

let us consider the previous length will be x nd breath also x means area=x^2
new lenght =1.3x
new breath=1.2x
area=1.3x*1.2x=1.56x^2
56% increased

Like? Yes (1) | No   

srikanth   9 years AGO

it will increase area by .56 times the original so answer will be 56%

Like? Yes (1) | No   

rimjhim gupta   9 years AGO

suppose initially l and be are 100
after increase l and b will be 130 and 120
so change in area will be 5600
and percent change will be 56.

Like? Yes (1) | No   

shivjee yadav   9 years AGO

let length=10,
width=10,
area=100
after increase length=13,
width=12
area=156 that meanst increase 56%

Like? Yes (1) | No   

Shweta Sharma   9 years AGO

let dimensions be l and b
new dimension=130/100l=1.3l and 120/100b=1.2b
increase=(1.3lX1.2b)-lXb
=1.56lb-lb
=.56lb
increase percent=(0.56lb/lb)X100
=56%

Like? Yes (1) | No (1)  

Pritam Das   9 years AGO

Suppose a is the length and b is the breadth. New length (a 0.3a) and new breadth (b 0.2b) and multiplying them we get 1.56ab. Thus, area is 56%more

Like? Yes (1) | No (1)  

SUNIDHI   9 years AGO

let intial area be 10000
new area =15600
inrease 5600 or 56%

Like? Yes (1) | No (1)  

Narendra Gopi   9 years AGO

area of a square is x^2
so rectagle length is :130x,breadth is 120x
rectagle area is 1.30x*1.20x=1.56x^2
so the are of rectangle exceeds is (1.56x^2-x^2)=0.56
percentage increase is 0.56*100=56%

Like? Yes (1) | No (1)  

aman aditya   9 years AGO

Let l=20m
b=10m
so area=20*10=200m*m

now after 20% increment.
l=26
b=12
new area=26*12=312 m*m

so new area exceed old by 56%

Like? Yes (1) | No (1)  

Bairi Sowjanya Reddy   9 years AGO

new length= s+(30 s/100) =13 s/10
new breadth= s+(20 s/100) =12 s/10
area=13 s/10 *12 s/10= ( 156 s*s )/100
% increase={(156 s*s)/100 - (s*s)}/(s*s) *100 = 56%

Like? Yes (2) | No (2)  

jayaram   9 years AGO

let a be the side of square then
Here the increase in area when length is extended to 30% and breadth is extended to 20 % then the area of rectangle will be 56%+area of square

Like? Yes (1) | No (1)  

velmala gangadhar   9 years AGO

n% of value=(getting/need)*100
from that 30% length(l) means getting=0.3l
breadth(b)means getting=0.2b
actual area of square=l*b
area of rectangle=(l+0.3l)(b+0.2b)
=1.3l*1.2b
=1.56lb
=(1+0.56)lb
actual area is lb and exceeding area is 0.56 times
It means exceeding area is 56%......

Like? Yes (1) | No (1)  

SURAJ KUMAR   9 years AGO

let x,y be the length and breadth of square
area of square= xy
length increased by 30%= x+0.3x
breadth increased by 20%=y+0.2y
then area of rectangle so formed is
=(x+0.3x)(y+0.2y)
=xy+0.2xy+0.3xy+0.06xy
=0.56xy
then area of rectangle is increased by 56%.

Like? Yes (1) | No (1)  

Rishikesh Ranjan   9 years AGO

area of square=L*L,
NOW the length of rectangle= L+L*30/100=(13/10)L
and breadth= L+L*20/100=(6/5)L
so area of rectangle= (39/25)L*L
so % increase in area= [39/25 L^2 - L^2]*100 = 56% of L^2

Like? Yes (1) | No (1)  

Ashu Kumar   9 years AGO

LET SIDE OF SQUARE IS 100 UNIT
SO AREA EQUALL TO=10000UNIT^2
NOW NEW LENGTH=130, BREADTH=120
SO AREA OF RECTANGUL=130*120=15600
SO AREA OF SQUARE EXCEED BY
15600-10000=5600=56%
SO 56% OPTION 10

Like? Yes (1) | No (1)  

Soma Naresh   9 years AGO

length of rectangle=l+(30×l/100)
breadth of rectangle=b+(20×b/100)
area of rectangle=(130l/100)(120b/100)
= 15600lb/10000=lb+(56lb/100)
area of rectangle=area of square+(56% ) area of square

Like? Yes (1) | No (1)  

ramya   9 years AGO

Let length =a and breadth=b.
Let area =ab .
new length: a+30a/100
= 13a/10
Similarly new breadth : b+20b/100
=120b/100 =>6b/5

New Area= (13a/10 * 6b/5)+ab
=>(78ab/100) = 50ab/50 +28ab/50
= ab + 56ab/100


New area is increased by 56%

Like? Yes (1) | No (1)  

deepak singh   9 years AGO

new length =1.3x
new breadth=1.2x
new area=1.56x
change in area =1.56x^2-x^2=.56

Like? Yes (1) | No (1)  

A M ANKIT KALLURAYA   9 years AGO

A=lb
A'=1.3*1.2lb
A'=1.56A
so there is an increase of 56%

Like? Yes (1) | No (1)  

santosh kumar patel   9 years AGO

Let a be the length of rectangle
and b be the breadth of rectangle
the old area = ab units
Length increased by 30% and Breadth increased by 20%
Therefore new length = a+(30a/100)=13a/10
and new breadth = b+(20b/100)=6b/5
New area of rectangle = 13a/10*6b/5
=78ab/50
=ab+(28ab/50)
=ab+(56ab/100)
=56%

Like? Yes (1) | No (1)  

Sneha Kurapati   9 years AGO

length of rectangle= a+ (30 a /100)= 13 a/10
breadth of rectangle = a+ (20 a/100) = 12 a/10
area of rectangle = 13 a/10 * 12a/10 = 156 a*a /100
% increase = {(156 a*a /100 - a*a )/(a*a) }*100=56%

Like? Yes (1) | No (1)  

siddhi datri   9 years AGO

new length=130/100
new breadth=120/100
new area=((130*120/10000)-1)*100=56%

Like? Yes (1) | No (1)  

SOMA NARESH   9 years AGO

length of rectangle=l+(30×l/100)
breadth of rectangle=b+(20×b/100)
area of rectangle=(130l/100)(120b/100)
= 15600lb/10000=lb+(56lb/100)
area of rectangle=area of square+(56% ) area of square

Like? Yes (1) | No (1)  

Danda Sindhura   9 years AGO

Suppose let the side of square be 100...(130/100)*(120/100)=156..
so rectangle increased by 156-100=56

Like? Yes (1) | No (1)  

Sriparna Boote   9 years AGO

At first lenght=breadht=x
Area is x^2

Now lenght =1.3x and breadth =1.2x
Area is 1.56x^2

Difference of area is 1.56x^2-x^2=0.56x^2 that is 56%

Like? Yes (1) | No (1)  

sushma   9 years AGO

if suppose side of square is 4cm. the increased length n breadth will be 26/5,24/5. now area of rectangle will be 624/25. area of square is 16. increase in are is 224*100/25*16=56%

Like? Yes (1) | No (1)  

ruby   9 years AGO

difference b/n area of rectangle and square is 5600.
percentage is 56%

Like? Yes (1) | No (1)  

Math Lovers   9 years AGO

Let side = 100 so area = 10000
new length = 130, new width = 120
new area = 15600

%age increment = 5600*100/10000 = 56%

Like? Yes (1) | No (1)  

manohar   9 years AGO

Side of squre be a,
Then length and bredth of rectangle =a+30/100,a+20/100

a*a(1.56-1)=.566

Like? Yes (1) | No (1)  

pandali   9 years AGO

Lets say square initial area :10*10=100;
after inc it 30% and 20% it will become =13*12=area of rectangle =156;
rectangle area is 156
square area is =100
rectangle exceeds square by 56%

Like? Yes (1) | No (1)  

Rudra   9 years AGO

l becomes=1.3 times & b become =1.2 time
so area will be=l*b
=1.3*1.2
=1.56
means increasd by 56%

Like? Yes (1) | No (1)  

rahul shaw   9 years AGO

area of square=l^2
area of rect=( l*B*120*130)/10000=1.56l*B
subtracting both we get
.56=56?
option 10

Like? Yes (1) | No (1)  

NITESH KUMAR SINGH   9 years AGO

let area of sq be x then l of rect=1.3x nd bnreadth=1.2x area of rec=1.56x y=(0.56x/x)*100

Like? Yes (1) | No (1)  

karthiga   9 years AGO

Let side of the square is x;
Area is x^2;
Side increased by 30% &20%..
Area of rectangle is 130x*120x/(100*100)
= 156/100 x^2;
Increased % = 56x/100/(x^2)*100
= 56%.

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Lavanya Rajendran   9 years AGO

130/100*l(*)120/100*b=1.56lb
1.56lb-lb=0.56
=56%

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Tinku   9 years AGO

Since side1 * side2= area.
: Net % change in area
= (x + y + xy /100) %
= ( 30 + 20 + 30*20/100) % ( x = 30, y = 20)
= 56%.
Therefore, the area of rectangle so formed exceeds the area of square by 56%.

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Deepanshu gupta   9 years AGO

Difference comes out to be 28/50 x^2..which is 56%.
Hopefully correct

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Archie   9 years AGO

let original length b l and b be the breadth
New length=13l/10
new breadth=6b/5
Area of square=lb
Area if rectangle =78lb/50
%increase in area=
(((78lb/50)-(lb))/lb)*100=56%

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vimal tiwari   9 years AGO

let 100 be side of square

initial area =10000

after inc sides

new sides 130 and 120

new area =15600

% change = 15600-10000=5600/10000=.56*100=56%

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hemant jain   9 years AGO

old area=X^2
new area=156x^2/100
increase in area=56/100
i.e 56 %

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ArmyKIRI   9 years AGO

length(1+(30/100))*breadth(1+(20/100))=area(1+(ans/100))
ans=56%

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Gaurab Kumar Jha   9 years AGO

Let side of the Square be L
Area Before : L^2
Area After :1.3l * 1.2 l = 1.56L^2
Change in Area = (1.56-1)L^2
Therefore, area increase by : ((0.56*L^2)/L^2 )* 100 = 56 %

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