Rs. 49 were divided among 150 children. Each girl got 50 paisa and a boy 25 paisa. How many boys wer

Gaurav Verma   9 years AGO

no of girls = x
no. of boys = 150-x
50x + (150-x)*25 = 4900
x= 46
no of boys = 150-46 = 104

Like? Yes (29) | No (4)  

Rakhi Modi   9 years AGO

let,there is x no. of girls and y no.of boys.
so,the 1st equation is,50x+25y=4900
and 2nd equation is x+y=1500
by solving we get y=104
so,there is 104 boys

Like? Yes (13) | No (4)  

Aman   9 years AGO

let there will be x boys so (150- x ) girls
now
x*25+(150-x)*50=49*100
so
-25x=4900-7500
x= 104
so
104 boys

Like? Yes (6) | No   

Abhinav Akash   9 years AGO

x + y =150
50x+25y=4900
-------------------------
ans- 104

Like? Yes (8) | No (2)  

ramya   9 years AGO

Let x=boys ,150-x =girls
x*25 +(150-x)*50 = 49*100
(49 rupees is converted to paise)
x= 104.

Like? Yes (7) | No (2)  

premlata   9 years AGO

104 boys (104*.25 = 26 ruppees )
46 girls (46*.50 = 23 rupees )

26+23=49 rupees

Like? Yes (7) | No (2)  

Anand Kumar Mehta   9 years AGO

No. Of boys=y
No. Of girls= 150-y
So (150-y)*50+25*y=4900
Solving this eqation we get y= 104

Like? Yes (3) | No   

Devendra Marghade   9 years AGO

If total girls=g & boys=b, then
g+b=150 ---(i)
50g+25b=4900 ---(ii)
On solving (i) & (ii), g=46, b=104
Option 3)

Like? Yes (4) | No (1)  

jayachandara   9 years AGO

let no.of boys and girls are;b and g
so b+g=150
25*b+50*g=4900
by solving b=104

Like? Yes (3) | No   

shagufta   9 years AGO

let the no of girls be x
then no boys be (150-x)
rupees distribued to girls=0.5x
and rupees distributed to boys= (0.25)(150-x)
acc to qstn,
(0.25)(150-x)+0.5x=49
on solving we get
x=46
and y=104
hence, no of boys=104

Like? Yes (3) | No   

Priya Verma   9 years AGO

50x + (150-x)25 = 4900

on solving above equation,
x i.e. number of girls = 46
hence number of boys = 104

Like? Yes (4) | No (1)  

rashmi r m   9 years AGO

let x and y be number of girls and boys respectively,then
x+y=150
and
0.5x+0.25y=49
solving 2 equations we get y= 104

Like? Yes (4) | No (1)  

junko ayuzawa   9 years AGO

substituting options in 'B' and G=150-B
in equation 50G+25B=4900

Like? Yes (3) | No   

Dhanraj Wanjare   9 years AGO

Let B is total Number of Boys;
and G is Total Number Of Girls
given
1/2G+1/4B = 49;
2G+B = 49*4;
2G+B = 196;................(1)

G+B = 150....................(2)

question 1 and 2

Total number of girls G=46;
and
tatal number of boys B=150-46;
....................................B = 104;
so option 3 satisfied

Like? Yes (3) | No   

ABHINAV PUSHPAM   9 years AGO

Let the boys be X and girls be (150-X)
Then,
25X + (150-X)50 = 49*100 (Converted in Rs.)
On solving X=104
So, no. of boys is 104

Option 3)

Like? Yes (5) | No (3)  

praveendas   9 years AGO

50x+25Y=4900
X+Y=150
solve for x and y. boys =104,girls=46

Like? Yes (2) | No   

Anurag Sahay Sriavsatav   9 years AGO

let number of Girls =x and Number of boys=y
so x+y=150
x*.5+y*.25=49
so y=104
option number 3 is correct.

Like? Yes (3) | No (1)  

Venkatesh kadali   9 years AGO

Here Girls and Boys are:
G+B=150 ----------->a
and each Girl got 50 paisa and each boy got 25 paisa and total money 40 rupees
so
50G+25B=4900
2G+B=196 .------------>b

solve a and b we get 104 boys
so answer is 3

Like? Yes (2) | No   

sudiptaa   9 years AGO

let x = no. of girls
y = no. of boys

x+y=150
50x + 25y = 4900
solving them
x= 46
y=104

Like? Yes (2) | No   

Kaustav Chaki   9 years AGO

let x be no. of girls and y be no. of boys
x+y=150
.5x+.25y=49
=>50(150-y) + 25y=4900
=>7500-25y=4900
=>2600=25y
=>104=y

Like? Yes (2) | No   

patki shrikant   9 years AGO

X----GIRLS
Y----BOYS
NOW EQUATIONS
X+Y=150
2X+Y=196

SO ANS =Y=104

Like? Yes (2) | No   

SAKTHEESVARI S   9 years AGO

b+g=150;50g+25b=4900paise; solving this 2 equation we get boys=104;g=46

Like? Yes (2) | No   

Ashu Kumar   9 years AGO

Let number of boy =x
So number of girls =150-x
So 50*(150-x) +25*y=49
So y =104
So option 3

Like? Yes (2) | No   

Anand Sekar   9 years AGO

no of girls=x; no of boys =150-x
0.5x+(150-x)0.25=49
0.25x=49-37.5
x=46
no of boys=150-46=104

Like? Yes (2) | No   

RUPNARAYAN RANA   9 years AGO

Let no of boys=x , so no of girls=(150-x)
50 paisa=Rs 1/2 and 25 paisa=Rs 1/4
Now A/C,
x/4+(150-x)/2=49
After solving the above equation, we will get
x=104
so total no boys=104 and girls=46.

Like? Yes (2) | No   

K.ARUNA JYOTHI   9 years AGO

1 rupee=100 paise
49 rupees=4900 paise
104*25=2600
46*50=2300
so boys=104

Like? Yes (2) | No   

Praveenkumar Kalikeri   9 years AGO

Trial n error method. .
Boys =104
Girls =150-104=46
Therefore , 104 (25) +(46)(50) =4900
4900/100 =49 Rs

Like? Yes (2) | No   

sheenu garg   9 years AGO

let no of boys=x => no of girls=150-x
100p=1Re
atq
(150-x)*1/2+x*1/4=49
solving for x
we get x=104

Like? Yes (2) | No   

Akash Kumar   9 years AGO

Let number of boys=b then number of girls=150-b
so using given info in problem .25*b+.5*(150-b)=49
solving the equation you'll get b=104
so answer is option-3) 104

Like? Yes (2) | No   

ashvini kumar   9 years AGO

let boys=x
girl=150-x
a/c to problem x/4+(150-x)/2=49
x=104

Like? Yes (2) | No   

BHASKAR MANDAL   9 years AGO

0.25x + 0.5(150-x) = 49
x = 104
option 3

Like? Yes (2) | No   

charan   9 years AGO

girls=x,boys=y
x+y=150,
50x+25y=49×100
solving them we get x=46,y=104

Like? Yes (2) | No   

naveen   9 years AGO

104/4=26 so remaining 23 balance that is distributed to 46 girls

Like? Yes (2) | No   

himanshu jaiswal   9 years AGO

since there are 150 student
If there are 104 boys then they will get 104/.25=Rs 26
so the remaining number of girls will be (150-104)=46
so they will recive 46/.5=23
total 26+23=49
so no of boys = 104

Like? Yes (2) | No   

Ayush Likhar   9 years AGO

104*25= 2600
now,
4900-2600=2300

and 50*46= 2300
so girls = 46
boys = 104
total = 150

Like? Yes (2) | No   

Pesari Udayasree   9 years AGO

answer=104,
let total no. of girls are 'x'
total no. of boys are 'y'
then given x+y=150
and x/2+y/4=49=> 2x+y=196
by solving two equations we get x=46 and y=104.

Like? Yes (2) | No   

Moutam Vishnu Murthy   9 years AGO

x(0.5)+y(0.25)=49, x+y=150 Solve these equations to get these values.

Like? Yes (2) | No   

Vikas Jha   9 years AGO

No of girls=x
No of boys=y
then, x+y=150.................................................(1)
and 50x+25y=4900..........................................(2)
x=46,y=104

Like? Yes (3) | No (1)  

Anubhav jain   9 years AGO

104 boys =Rs 26
46girls= Rs.23
total= Rs.49 and children=150

Like? Yes (2) | No   

akash patil   9 years AGO

let 104 boy
104/4=26
150-104=26 girls
26/2=23
26+23=49rs

Like? Yes (2) | No   

deepthi   9 years AGO

girls+boys=150
50*girls+25*boys=4900 (ps)
by solving
boys=104

Like? Yes (2) | No   

YASWANTH REDDY   9 years AGO

if we make equations for the number of total children and for total no. of rupees distributed, we get total girls = 46 and total boys =104

Like? Yes (2) | No   

Ramesh Sriram   9 years AGO

let boys=x
girls=150-x
according to problem
(x/4)+((150-x)/2)=49
solve
x=104

Like? Yes (2) | No   

Math Lovers   9 years AGO

B + G =150 ------------------- (1)

B/4 +G/2 = 49
=> B+ 2G = 196 ----------------- (2)

from (1) and (2)
G = 46
B=104

Like? Yes (2) | No   

Anant Kumar   9 years AGO

let no of boys are x and no of girls are y..
now
.25x+0.5y=49 ......(1)
x+y=150 ......(2)
hence by solving these equation we get x=104

Like? Yes (2) | No   

Arvind kumar   9 years AGO

let no. of boys =x then no. of girl=150-x
according to question,
50*(150-x)+25*x=4900
which gives x=104
therefore no of boys=104

Like? Yes (2) | No   

Khush Bhardwaj   9 years AGO

let girls = x & boys = y
total students = 150
therefore x+y=150 hence x=150-y
total money = rs.49 = 4900 paisa
50x+25y=4900
by solving
y=104

Like? Yes (2) | No   

Sayan Das   9 years AGO

x=girls
150-x=boys
therefore,50x + 25(150-x) = 4900
deducing the value of x,we get girls=46
boys=104

Like? Yes (2) | No   

gaurav singh   9 years AGO

let the no. of girls =x and no. of boys =y .
x+y=150 -----(i)
0.5 x + 0.25 y = 49 ------(ii)
solving both eq. i and ii, we get x= 46 and y= 104

Like? Yes (2) | No   

PAWAN KUMAR   9 years AGO

Let no of boys and girls be x and (150-x) respectively.
Then, x*25 + (150-x)*50 = 4900
=> x= 104. Ans.

Like? Yes (2) | No   

bindu   9 years AGO

If there are 104 boys and girls will be 46. on substituting the values in the equation 50x +25y = 4900 the eq. should be satisfied

Like? Yes (2) | No   

Nandkishor jaiswal   9 years AGO

let there are G number of girls present
then Boys=150-G
from equation------
4900=50G+25*(150-G)
-->4900=50G+3750-25G
--->25G=1150
--->G=46
so Boys= 150-46=104

Like? Yes (2) | No   

SORNA KAMALAM S   9 years AGO

let b be the no.of boys and g be the no.of girls

given:
b+g=150 ===> g=150-b
25b+50g=4900
25b+50(150-b)=4900
25b+(50*150)-50b=4900
7500-25b=4900
2600=25b
104=b

Like? Yes (2) | No   

naveen   9 years AGO

let no.of girls=x and no.of boys=y
total no.of children=150 ;x+y=150
each girl 50 paisa and each boy got 25 paisa
there fore 50x+25y=4900
by solving them we get total no.of boys =104

Like? Yes (2) | No   

urmi bose   9 years AGO

considering the no.the boys as y and girls as (150-y),and using equation (150-y)/2+y/4=49
Thus y+104

Like? Yes (2) | No   

Siddharth Mehta   9 years AGO

Let there are x girls & y boys so, x+y=150
& 50x+25y=4900
on solving y=104, so there are 104 boys.

Like? Yes (2) | No   

priyanka burnwal   9 years AGO

let the no. of boys be y
so the no. of girl=150-y
1/2(150-y)+1/4(y)=49
y=104
here 50 paise=1/2 and 25 paise=1/4

Like? Yes (2) | No   

SAHITI PENMETSA   9 years AGO

g*50+b*25=4900
25(g*2+b)=4900
g*2+b=4900/25
g*2+b=196----(1)
it is given that g+b=150----(2)
i.e from (2)
g=150-b-----(3)
now sub (3) in (1)
2(150-b)+b=196
300-b=196
b=104

Like? Yes (2) | No   

Deepanshu Chaturvedi   9 years AGO

from options (104*1/4) rs=rs 26 and (46*1/2) rs=rs 23 satisfy the condition hence 3 is the right option.

Like? Yes (2) | No   

ramireddy.sindhuja   9 years AGO

if there r 104 boys then the total is 26rs
nd remaining 23rs from remaining 46girls

Like? Yes (2) | No   

Vishal Barkule   9 years AGO

As distrubution per boy is less then number of boys will be greater.

Like? Yes (2) | No   

Pranay Giradkar   9 years AGO

total 49 rs are there
Re 1=2 girls(distributed)
Re 1= 4 boys(distributed)


23 Rs= 46 Girls
26 RS=104 boys
23+26=49RS

& 46+104=150 childrens
49 Rs= 150 childrens

Like? Yes (2) | No   

CHITHRA V K   9 years AGO

25 paisa coins - 104/4 = 26
50 paisa coins - 46/2 = 23
26 + 23 = 49
So, 104 boys

Like? Yes (2) | No   

CHANDAN KUMAR   9 years AGO

let boys be x & girls be y.
a/q questions

total no. of boys and girls are 150.

so,

x+Y =150 ........ (I)

each boy got 25 paise and each girl got 50 paise .
total money = 4900 paise ( 49rs)
so,
25x + 50y = 4900 ..... (ii)

solving equations (I) & (ii) , we get

x+y =150... (I)
x+2y= 4900/25
or ,
x+2y =196 ..... (ii)

so,
y =46 and x =104

or,
girls = 46
boys = 104

correct option is
3) 104

Like? Yes (2) | No   

Paul Rohit   9 years AGO

x = number of boys, y = number of girls. x+y = 150, 50y +25x = 4900. By solving we get number of boys = 104.

Like? Yes (2) | No   

Samjukta Das   9 years AGO

Let there be x boys so that there be (150-x) girls
x*25+(150-x)*50=49*100
(converted 49 rs to paisa)
25x+150*50-50x=4900
-25x=4900-7500
25x=2600
x=104

Like? Yes (2) | No (1)  

hemanth mallidi   9 years AGO

x+y=150
0.5x+0.25y=49
solve for x and y
x=no of girls
y=no of boys

Like? Yes (2) | No (1)  

Yashi Das   9 years AGO

Let,
No. of boys be x and no. of girls be y
x+y=150 -----(eqn 1)
(25/100)x+(50/100)y=49 ----(eqn 2)
On solving,we get x=104

Like? Yes (2) | No (1)  

samita mandal   9 years AGO

'x' no.of gals ,(150-x)no.of boys
50x +(150 -x)25=4900
so,x=46...no.of boys= 150-46=104
i.e no.of boys

Like? Yes (2) | No (1)  

sonu   9 years AGO

let no. of girls be X
no. of boys be Y

Now Solve Equations
X+Y=150--------1
50X+25Y=4900-------2

ON SOLVING Y=104 => no. of boys

Like? Yes (2) | No (1)  

Siva   9 years AGO

50g+25b=4900,
g+b=150.
By solving these two equations wecwill get g=46,b=104. So the answer is 104

Like? Yes (2) | No (1)  

vikash kumar das   9 years AGO

let the no of girls and boys be x and y then we have
x+y=150
50x/100+25y/100=49
after solving the two equation we get y=104

Like? Yes (2) | No (1)  

paavai   9 years AGO

let number of girls be x and boys be y
total=150
x+y=150-------------(1)
0.50x+0.25y=49-------------(2)
solving (1) and (2)
we get x=46 and y=104
thus no. of boys=104

Like? Yes (2) | No (1)  

deepika mazumdar   9 years AGO

49=26+23
.25*4=1= 4 boys make re1
.50*2=1=2 girls make re1
26*4=104
23*2=46
104+46=150
ans option3

Like? Yes (2) | No (1)  

akhil sharma   9 years AGO

104 boys will get 26 rs. and 46 girls wil get 23 rs so total will be 49

Like? Yes (2) | No (1)  

Priyesh Ram Krishna   9 years AGO

Let x is the no of girl and y be the no of boy.Then given that x+y=150.....1
and also
0.50*x+0.25*y=49.....2
By solving 1 and 2 we get y=no. of boy =104

Like? Yes (2) | No (1)  

manikanta korada   9 years AGO

let there be x boys and so that there are (150-x) girls
x*25+(150-x)50=49*100(in paise)
after calculating x=104

Like? Yes (2) | No (1)  

Rahul kumar   9 years AGO

g+b=150
0.5g+0.25b=49
0.5(150-b)+.25b=49
75-0.5b+.25b=49
75-.25b=49
75-49=.25b

b=26/.25=104

Like? Yes (2) | No (1)  

snigdha roy   9 years AGO

x+y=150
25x+50y=4900
by calculating these two equations we will get y=46,boys=150-46=104

Like? Yes (2) | No (1)  

Amit Kumar Jha   9 years AGO

if 104 boys i.e 104/4=26 Rs
now,girls=(150-104)=46 i.e.46/2=23 Rs
total=26+23=49 Rs.So.option 3 is correct

Like? Yes (2) | No (1)  

SEBA SIBY   9 years AGO

50x+25y=4900
x+y=150
x=46
y=104

Like? Yes (2) | No (1)  

mounika kadudhuri   9 years AGO

let x boys and y girls

0.25x+0.5y=49
x+y=150

solving, x=104 and y=46

Like? Yes (2) | No (1)  

chidige jhansi   9 years AGO

assume total girls ,amount=Rs.75/-
total boys ,amount =Rs37.5/'
G B
75 37.5
49
11.5 26
Ratio=11.5:26
No of boys=(26/37.5)*150=104

Like? Yes (2) | No (1)  

NITESH KUMAR SINGH   9 years AGO

girl=46
rupees=23
left rupe=26
boy=26*4=104
total=104+46

Like? Yes (2) | No (1)  

meghana   9 years AGO

total children =150
total girls = x
total boys = 150-x

(x*0.5)+([150-x]*0.25) = 49
x=46
so boys = 150-x=150-46=104

no of boys are 104

Like? Yes (2) | No (1)  

Srikanth   9 years AGO

each girl 50ps
Let g be total girls.
total amount (girls)=50g
similarly
total amount(boys)=25b
25b+50g=4900
given that
b+g=150
solving
b=104

Like? Yes (2) | No (1)  

s.h.h.praveen   9 years AGO

x+y=150.
x=no. of boys,y= no.of girls
x*0.25+(150-x)=49
by solving we get x=104.

Like? Yes (2) | No (1)  

vimal tiwari   9 years AGO

x*50 + (150- x )*25 = 4900

x=46

boys = 150 - 46 = 104

Like? Yes (2) | No (1)  

sushmita   9 years AGO

50x+25y=4900
x+y=150

on solving these two equations..we get
y=104.so,total no. of boys=104.

Like? Yes (2) | No (1)  

krupani   9 years AGO

Go through options.Let boys=104;
25ps*104+50girls=4900ps,
2600+50girls=4900ps
50girls=4900-2600=2300;
50girls=2300;
girls=2300/50=46;
boys=104 and girls=46 ;Total=boys+girls=104+46=150

Like? Yes (2) | No (1)  

nikhil mishra   9 years AGO

let the boys be "x" so girls will be 150-x
now according to question:-
0.25*x + 0.5 (150-x)=49
on solving
we get x=104

Like? Yes (2) | No (1)  

JEGATHA.H   9 years AGO

boys 104*25=26 Rs & girls 46*50=23
total= 26+23=49Rs

Like? Yes (2) | No (1)  

Nisha Das   9 years AGO

solving through options
104*25=26
if no. of boys =104 then no. of girls :150-104=46
that implies
46*50=23
hence
26+23=49

Like? Yes (2) | No (1)  

Mugesh sivagnanam Krishnapillai   9 years AGO

Let X be girls and Y be boys,then
X+Y=150
0.5X+0.25Y=49
solving both equations
X=46 and Y=104
Therefore Toatl boys = 104.

Like? Yes (3) | No (2)  

ASHISH GUPTA   9 years AGO

let the no. of boys are B and no. of girls are G,then we can write
50G+25B=4900
B+G=150
solve both equation,we get B=104

Like? Yes (2) | No (1)  

kartik sahgal   9 years AGO

let no of boys be x then girls are 150-x.
0.25x+(150-x)0.50=49
0.25x=26
x=104

Like? Yes (2) | No (1)  

sri   9 years AGO

g+b=150
50g+50b=150*50=7500-----1
50g+25b=49*100-----2
1-2=======>
b=104

Like? Yes (2) | No (1)  

Madhusudhan Vaddi   9 years AGO

Rs. 49 = 4900 paisa
Let 'x' = No. of girls
Let 'y' = No. of boys

x+y=150
50x + 25y = 4900

50x + 25(150-x) = 4900 (from y=150-x)
50x - 25x + 3750 = 4900
25x = 4900 - 3750
25x = 1150
x = 1150/25
x = 46

y = 150 - x = 104
Therefore, No. of boys = 104

Like? Yes (2) | No (1)  

MANISH   9 years AGO

x=no. of girls.
y=no. of boys.
x+y=150
0.50x+0.25y=49.
solving these two,we get no. of boys =104

Like? Yes (2) | No (1)  

Vishal   9 years AGO

104 * 25 is 26 rupees and remaining 46 * 50 is 23 rupees so total 49

Like? Yes (2) | No (1)  

vaishali   9 years AGO

let x be no. of girls and y be no. of boys
x+y=150
50x+25y=4900
then x=150-y
so y =2600/25 = 104

Like? Yes (2) | No (1)  

Shikha Mishra   9 years AGO

since there are 46 girls by using the equation:
0.5x+0.25(150-x)=49

Like? Yes (1) | No   

ritu yadav   9 years AGO

Let g be no of girls and b be no of boys then g+b=150
And 0.5g+ 0.25b= 49
Solving these equation we get b =104

Like? Yes (2) | No (1)  

Diksha   9 years AGO

Let boys be x then girls will be 150 -x
Now according to the question x/4 +(150-x)/2 =49
By solving the above equation we will get x=104 which is the required number of boys .

Like? Yes (2) | No (1)  

Mansi Patel   9 years AGO

let number of boys be x
49/150-x=0.25
x=46
150-46=104

Like? Yes (2) | No (1)  

shubham pareek   9 years AGO

x+y=150
25x+50y=4900
x+2y=196

Like? Yes (2) | No (1)  

dheeraj   9 years AGO

(boys*paisa)=no of rupees and (girls*paisa)=no of rupees so,(104*0.25)=26rs and (46*0.5)=23rs, total rs=(26+23)=49 satisfied and total children=(104+46)=150 so no of boys=104 is the answer

Like? Yes (2) | No (1)  

Tushar Bedekar   9 years AGO

b+g=150
0.25b+0.5g=49
solve both the equations and find the value of b
as an answer

Like? Yes (3) | No (2)  

Umesh sahu   9 years AGO

46 girl get 23 rs and 104 boys get 26 rs becouse each girl get double of the boy money

Like? Yes (3) | No (2)  

ved prakash yadab   9 years AGO

104%4=26
49-26=23
23*2=46
104+46=150

Like? Yes (2) | No (1)  

deepak rajwar   9 years AGO

x + y =150 (x-girls,y-boys)
(1/2)x + (1/4)y =49
solve
x=46,y=104

Like? Yes (3) | No (2)  

sumit kumar   9 years AGO

let girl be x so boy will be 150-x
according to question 50x+25(150-x)=4900
after solving x=46
so no of boys=150-46=104
option 3

Like? Yes (3) | No (2)  

muttuluru sruthi   9 years AGO

let no.of boys=x
no.of girls=150-x
x*25 +(150-x)*50=49*100
we get x=104

Like? Yes (3) | No (2)  

Priya   9 years AGO

x+y=150
50x+25y=4900
solve both equation you will get y=104

Like? Yes (3) | No (2)  

TAUSEEF AMEEN   9 years AGO

(104*25)/100+(46*50)/100=49.
hence by using option ..
ans is 104

Like? Yes (2) | No (2)  

ABHIJEET ANAND   9 years AGO

let no. of boys=x, no.of girl=150-x.
now,
x*.25+(150-x)*.50=49.
x=104.

Like? Yes (2) | No (2)  

ramakrishnateja   9 years AGO

g+b=150
50g+25b=4900 (in paise)
solve both equations we get b=104,g=46.

Like? Yes (1) | No (1)  

jayant   9 years AGO

as we know there were only 150 students in class so 104 students gets the 25 paise coin and the the girls were remaining one which by mutipy remaing girls with2 we get the same result as we multiply the same 50 paise coins

Like? Yes (2) | No (2)  

Kethineni Vinodh   9 years AGO

25p*4=1rupee for 4 boys
104/4=26rupees
total 49-26=23rs remaining
total 150-104=46 girls i.e., 46*50p=23rs

so total 104 boys

Like? Yes (2) | No (2)  

Vaibhav Deshmukh   9 years AGO

25b+50(150-b)=4900
=> 25b=7500-4900
=> 25b=2600
=> b=104

Like? Yes (1) | No (1)  

david   9 years AGO

b+g=150
1/2g+1/4b=49
on solving
b=104
g=46

Like? Yes (2) | No (2)  

aman aditya   9 years AGO

Let
No. of boys=x
No. of girls=y

Now, we get two equations:
x+y=150
.50x+.25y=49
solving both we get
x=46
y=104
so, No. of boys are:104

Like? Yes (1) | No (1)  

SAI PRASANNA LAKSHMI   9 years AGO

g*50+b*25=4900
25(g*2+b)=4900
g*2+b=4900/25
g*2+b=196----(1)
it is given that g+b=150----(2)
i.e from (2)
g=150-b-----(3)
now sub (3) in (1)
2(150-b)+b=196
300-b=196
b=104

Like? Yes (1) | No (1)  

Tanya Sachdev   9 years AGO

x->number of girls
y->number of boys
x+y=150
0.50x+0.25y=49
solving these two equations we get y=104

Like? Yes (1) | No (1)  

pranav   9 years AGO

becoz. 104×0.25=26and. 46×0.5=23. and 23+26=49

Like? Yes (1) | No (1)