If Rajendra obtains 10% marks more then Surendra then how many % less marks are obtained by Surendra

M4maths Previous Puzzles

31 Dec 2015 Marks

If Rajendra obtains 10% marks more then Surendra then how many % less marks are obtained by Surendra than Rajendra.

OPtion

1) 9
2) 9.08
3) 10
4) 10.9
5) 10.01
6) 10.1
7) 9.9
8) 9.8
9) 11
10)9.09

Solution

Let marks of Surendra is x
Then according to given condition marks of Rajendra is 1.1x
Difference of marks is 1.1x – x = 0.1x
Hence marks of Surendra are (0.1x/1.1x)*100 = 100/11 = 9.09 % less than marks of Rajendra.

Option 10)

Correct Option: 10 Best Solution (22)

NIKHIL JAIN   9 years AGO

Let Surendra scores= 100
Rajendra= 10% of 100 more= 110
Then % marks obtained less by surendra= (110-100)/110*100= (10*100)/110= 9.09%

Like? Yes (1) | No   

MRITUNJAY   9 years AGO

let Surendra be 100
rajendra be 110

less % 10/110*100=9.09

option 10

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

% less marks obtained by Surendra than Rajendra=[100 - 100*(100/110)]=100-90.9090=9.09
Option 10)

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ROHIT KUMAR DUBEY   9 years AGO

S=100
R=100+10=110
less%=(10/110)*100=9.09

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Param   9 years AGO

let Surendra 100, Rajendra 110
now 110-100=10
%less =10/110 *100=9.0909

Like? Yes (1) | No   

luciya   9 years AGO

Lets take Surendra =100
Rajendra = 110

% less marks obtained by Surendra = 10*100/110 = 9.09

Like? Yes (1) | No   

JEGATHA.H   9 years AGO

let surender income be 100
then rajndra income=110
required percentage=(110-100/120)*100%=9.09

Like? Yes (1) | No   

Shreeya Kharbanda   9 years AGO

Let the marks obtained by Surendra be 100
Then the marks obtained by Rajendra is 110
Percentage of marks obtained by Surendra is less than the marks obtained by Rajendra = (10/110)*100 = 9.09%

Like? Yes (1) | No   

Jamil Ahmed   9 years AGO

%age of marks obtained less by Surendra than Rajendra = 100-(100*100/110) = 9.09

Like? Yes (1) | No   

Mohammad umar   9 years AGO

Let surendra obtained 90 marks
Then rajendra obtained 99 marks
X% of 99 = 90
X = 90*100/99=90.9% or 9.09

Like? Yes (1) | No   

harsh dhir   9 years AGO

let surendra marks=100
rajendra marks=100+(10/100)*100=110
so surendra marks are less by=(110-100)/110*100=9.09

Like? Yes (1) | No   

Shagun Chaudhary   9 years AGO

let marks of Surendra are x.
Thus the marks of Rajendra are 1.1x
surendra's marks less than rajendra=(1.1x-x)/1.1x=9.09%

Like? Yes (1) | No   

anjali gupta   9 years AGO

let surendra scored x
rajendra scored = 1.1x
difference = 0.1x
% surendra scored less = 0.1x*100/1.1x = 9.09

Like? Yes (1) | No   

debanjan   9 years AGO

Let's surendra gets 100 marks
Rajendra 10% marks more than surendra
I.e. 100*10%of 100=110

Now rajendra is 10 marks ahead of surendra.
(10/110)*100=9.09

Like? Yes (1) | No   

kriti kankariya   9 years AGO

let s's marks be 100
then r's = 100+ 10% of 100 = 110
then ((110-100)/110)*100 = 9.09%

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Ashraf Mahmood    9 years AGO

100 becomes 110
Percentage change over 110=10/110=1/11=9.09

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Suyash Singh Fartyal   9 years AGO

Let Surendra's marks be = x
10% of x = x/10
Rajendra's marks = x + x/10 = 11x/10
Marks(Surendra's) that are less = x/10
Let the percent be y%
Therefore,
y% of Rajendra's marks = x/10
y/100 * 11x/10 = x/10
y = 100/11 = 9.09

Like? Yes (1) | No   

mohan ranga rao   9 years AGO

x>10%y
now % of y less than x is 100y/110y=0.90909*100=90.909
100-90.909=9.09

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Neena George   9 years AGO

Assume surendra got 100 marks ....then rajendra's marks which is 10% more would be 110... 100 is 90.909090% of 110... so Rajendra's marks is (100-90.909090=9.09)% higher than surendra's

Like? Yes (1) | No   

Anurag Bawankar   9 years AGO

Take ex surendra got 100 markd
then rajendra will get 110
thus surendra got 10 marks less
%less =(10/110)*100=9.09

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Vinitha   9 years AGO

raj=sur+.1sur
raj=1.1sur
sur=raj/1.1
sur=.909raj
sur=raj-.091raj

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shubham tiwari   9 years AGO

take rajendra marks as 110
and surendr marks as 100
now less%= ((110-100)/110)*100
=9.09

Like? Yes (1) | No