If y = (6+x)^2/(6-x)^2 is not a perfect square integer and x is less than 6 and greater than 0, then

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09 Feb 2016 Integer

If y = (6+x)^2/(6-x)^2 is not a perfect square integer and x is less than 6 and greater than 0, then the value of y is

OPtion

1) 100/9
2) 16/3
3) 81/8
4) 49/25
5) 20
6) 1/2
7) 121
8) 25
9) 25/16
10) 24

Solution

On taking x = 1, 2, 3, 4, 5 respectively, we get
y = 49/25, 4, 9, 25, 121
Only 49/25 is not a perfect square integer, hence is the solution.

Option 4)

Correct Option: 4 Best Solution (16)

karnatakam.Jaswanth kumar   8 years AGO

Given that the y is not a perfect square integer
Then (6+x)÷(6-x) must not the integer
From values in the interval x
x=1 gives the non integer value
So by substituting the x value we will get y=49/25

Like? Yes (3) | No   

Garrepally Gopikrishna   8 years AGO

As x varies from 0 to 6 (i.e.1,2,3,4,5)
so substitute 1,2,3,4,5
if you substitute 2,3,4,5 gets intezer
but if you substitute 1 you get 49/25 which is not an intezer
so option 4

Like? Yes (3) | No   

RAHUL KUMAR   8 years AGO

Y= (6+x)^2/(6-x)^2
At X = 2,3,4,5 it is a perfect sq number
But At X= 1
the value of Y = 49/25
option (4) is correct.

Like? Yes (2) | No   

Mukund Manohar   8 years AGO

Calculating the value of y by taking x=1,2,3,4 & 5 (because 0

Like? Yes (1) | No   

SHUBHAM   8 years AGO

Solution

On taking x = 1, 2, 3, 4, 5 respectively, we get 
y = 49/25, 4, 9, 25, 121
Only 49/25 is not a perfect square integer, hence is the solution

Option (4)

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vineesha p   8 years AGO

[(6+1)/(6-1)0^2=49/25.
The rest are all perfect squares

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harsh dhir   8 years AGO

on taking x=1,2,3,4,5 we get y=49/25,4,9,25,121.
only 49/25 is not a perfect square integer.
y=49/25

Like? Yes (1) | No   

Yashi Das   8 years AGO

when x= 1 y=49/25
x=2 y=4
x=3 y=9
x=4 y=25
x=5 y=121
Therefore option 4) 49/25

Like? Yes (1) | No   

Akshat Sood   8 years AGO

substituting value of x as 1
we get value of y comes out to be 49/25 that is not perfect square

Like? Yes (1) | No   

satish ojha   8 years AGO

x is putting 1 then give = 49/25

other is give perfect square no so not possible

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Jaikumar Bhatia   8 years AGO

By putting the value of x in the equation
x=1,y=49/25
x=2,y=4
x=3,y=9
and so on....
49/25 is not a perfect square integer
ans is 49/25
option is (4)

Like? Yes (1) | No   

aneesh s s   8 years AGO

(6+1)^2/(6-1)^2
7^2/5^2
49/25.

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Sagar Jinachandran   8 years AGO

y=((36+12x+x^2)/(36-12x+x^2))
substituting values of x from 1-5 we get
x=1, y= 49/25
x=2, y=4
x=3, y=9
x=4, y=25
x=5, y=121
rest all are perfect squares
so we get
49/25
option 4

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aruj chatterjee   8 years AGO

Y is not a perfect square integer then 25 nd 121 are excluded from the option ...so 8 options are left
since 0

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SHAIK JANI BASHA   8 years AGO

(6+x)^2/(6-x)^2..if x=1 then y=49/25 its not a perfect square..if x=2,3,4,5 we get perfect squares

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Jaspalsingh Parmar   8 years AGO

option 4 is correct

Like? Yes (1) | No (1)