M4maths Previous Puzzles

21 Mar 2016 Sequence

What is the next number of the following sequence.
1342, 1365, 1416, 1430, .......

OPtion

1) 1442
2) 1448
3) 1458
4) 1446
5) 1434
6) 1438
7) 1462
8) 1456
9) 1454
10)1472

Solution

1342
1342+(1*3)+(3*4)+(4*2) = 1342+3+12+8 = 1365
1365+(1*3)+(3*6)+(6*5) = 1365+3+18+30 = 1416
1416+(1*4)+(4*1)+(1*6) = 1416+4+4+6 = 1430
Similarly
1430+(1*4)+(4*3)+(3*0) = 1430+4+12+0 = 1446

Option 4)

Correct Option: 4 Best Solution (4)

Devendra Marghade   8 years AGO

1342+(1*3+3*4+4*2)=1342+23=1365
1365+(1*3+3*6+6*5)=1365+51=1416
1416+(1*4+4*1+1*6)=1416+14=1430
1430+(1*4+4*3+3*0)=1430+16=1446
Option 4)

Like? Yes (4) | No   

Richa Saini   8 years AGO

First number : 1342
Second number : previous number + (first digit*second digit + second digit*third digit + third digit*fourth digit)
=> 1342 + (1*3 + 3*4 + 4*2) =1342 + 23 = 1365

Third number = 1365 + (1*3 + 3*6 + 6*5) = 1416
Fourth number = 1416 + (1*4 + 4*1 +1*6) = 1430
Fifth number = 1430 + (1*4 + 4*3 + 3*0) = 1446

=>option(4) is the answer.

Like? Yes (2) | No   

tasho k   8 years AGO

1365-1342=23
1416-1365=51
1430-1416=14

1×3+3×4+4×2=23
Similarly
1×4+4×3+3×0=

So next number 1430+16=1446

Like? Yes | No (1)  

RAKESH   8 years AGO

1342+(1*3+3*4+4*2) = 1365

1430+(1*4+4*3+3*0) = 1446

Like? Yes | No (1)