Rajendra invested 1/3 of his capital at 7%, 1/4 at 8% and the remainder at 10%. If his annual income

M4maths Previous Puzzles

24 Mar 2016 Simple Interest

Rajendra invested 1/3 of his capital at 7%, 1/4 at 8% and the remainder at 10%. If his annual income is Rs.1122, the capital is

OPtion

1) 10800
2) 13800
3) 12000
4) 14400
5) 14200
6) 14800
7) 10400
8) 13200
9) 12800
10)8800

Solution

Let the capital be Rs.x Then,
x/3 * 7/100 * 1 + x/4 * 8/100*1 + 5x/12 * 10/100 * 1 = 1122
7x/300 + 8x/400 + 50x/1200 = 1122
102 x = 1122*1200
x= 1122*1200/102
x = 13200

Option 8)

Correct Option: 8 Best Solution (20)

G.S.Kantharao   8 years AGO

let the amount is 1200. It is because l.c.m of 3 and 4 is 12. Imagine amount as its multiple of hundreds.
Now the incomes are 400 x 7/100 + 300 x 8/100 + 500 x 10/100 = 102.
If the income is 102 then the amount is 1200
If the income is 1122 then the amount is = 1200 x 1122/102 = 13200.

Like? Yes (9) | No (2)  

Sahil Arora   8 years AGO

Let capital be Rs x
According to Question we have,
1/3 at 7% , 1/4 at 8% means
remaining capital would be 1-(1/3+1/4)=5/12 and invested at 10%,
Now forming an equation,as the question says,
(0.07x)/3 + (0.08x)/4 + (0.5x)/12 = 1122
solving the above equation
we get (1.02x)/12=1122
means
x=Rs 13200(capital)

Like? Yes (3) | No   

KRISHNA KIREETI MAMIDI   8 years AGO

let the total capital be 'x'
7% of (x/3) + 8% of (x/4) + 10% of (5x/12)=1122
by solving the equation we get x= 13200

Like? Yes (2) | No   

rajesh kumar   8 years AGO

let capital is c

(7*c)/(3*100)+(8*c)/(4*100)+(5*c*10)/(12*100)=1122

c=13200

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Ankush Surana   8 years AGO

P=(100*I)/(a*R1+b*R2+c*R3)
P=(100*1122)/(7/3+8/4+50/12)
P=13200
I=income
a,b,c= fraction of money
P=principal or invested amount
R1,R2,R3=rate of investment with respect to fraction of money.

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THUMMALA VINEESHA   8 years AGO

let capital be x
(1/3)*x*(7/100)=(x/100)*(7/3)
(1/4)*x*(8/100)=(x/100)*(8/4)
remaining (5/12)*x(10/100)=(x/100)*(25/6)
total income=1122
(x/100)*[(7/3)+(8/4)+(25/6)]=1122
(x/100)[102/12]=1122
x=13200

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Vinodkumar Shirguri   8 years AGO

let x be the investment (principal)


[(x/3)7+(x/4)8+(5x/12)10]/100=1122

solving we get x=13200

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Vikas William   8 years AGO

let the cap be x.
(1/3 x *8)/100 + (1/4 x*8)/100 +(5/12x *10) =1122
solve for x

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Venkateswarlu   8 years AGO

{(0.07/3)+(0.08/4)+(0.5/12)}*x=1122
x=1122/0.085
x=13200

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sandip burnwal   8 years AGO

(x/3)*0.07+(x/4)*0.08+(5*x/12)*0.1=1122
x=13200

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Reshma   8 years AGO

let capital=x
by given data
(7x/300)+(8x/400)+(25x/1200)=1122
so x=13200.

Like? Yes (1) | No (1)  

tasho k   8 years AGO

SUPPOSE X CAPITAL
(x/3*7*1)/100 +(x/4*8*1)/100+(5/12x*10*1)/100=1122

solving this x=13200

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Shobha   8 years AGO

solving the value of x:
1/3*x*7/00+1/4*x*8/100+5/12*x*10/100=1122

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MRITUNJAY   8 years AGO

let the total capital is p.
remaining capital=p-p/3-p/4=5p/12
so
1/100(p/3*7+p/4*8+5p/12*10)=1122
p=13200
option 8

Like? Yes | No (1)  

Dinesh kumar sah   8 years AGO

Let his capital is Rs x.
then according to the question,
(7x/300)+(8x/400)+(50x/1200)=1122
or, (28x+24x+50x)/1200=1122
or, 102x=1346400/102
or, x=Rs.13200Ans

Like? Yes | No (1)  

Akshat Sood   8 years AGO

Let the capital be x
Then, 7x/300,2x/100 and x/24 is the invested amount
7x/300+2x/100+x/24=1122
Solve x=13200

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Arka Bhattacharjee   8 years AGO

annual income=total si=prt/100
(7/300)x+(8/400)x+(1-1/3-1/4)×1/100×x=1122

Like? Yes | No (1)  

SRITAMA CHOWDHURY   8 years AGO

Say,Rajendra's capital is x rs.

so,7x/300 + 8x/400 +50x+1200=1122
and,28x+24x+50x=1122*100*12
and,x=13200.

Like? Yes | No (1)  

Jyoti gupta   8 years AGO

(x*1/3*7/100*1)+(x*1/4*8/100*1)+(x*5/12*10/100*1)=1122
X=13200

Like? Yes | No (1)  

Lenin   8 years AGO

let's assume his capital is X,
then as per the given statement
(X/3)7% + (X/4)8% + (5X/12) 10% = 1122
(4X) 0.07 + (3X) 0.08 + (5X) 0.1 = 13464
0.28X + 0.24X + 0.5X = 13464
1.02X = 13464
X = 13200

Like? Yes | No (1)