ayushi mishra   8 years AGO

x=k/(y*Y)
4=k/(3*3)
k=36
x=36/(6*6)
x=1

Like? Yes (8) | No (3)  

Debajyoti Biswas   8 years AGO

given x is inversely prop as the sq. of y.so if we take k as constant of variation then,

x=k*1/y^2

now putting the initial values of x and y we get,

4=k*1/9 or k =36

so the law of variation becomes x=36*1/y^2

now putting the value of y=6 in this equation we get,

x=36*1/6^2 or x=36*1/36=1

so,x=1 when y=6

Like? Yes (1) | No   

mounika   8 years AGO

from given statement x=k 1/y^2
x=4;y=3 on substituting in above equation we get k=36
now x=k 1/y^2
k=36 and y=6
substitute both values in above equation we get x=1

Like? Yes (1) | No   

Prateek   8 years AGO

k=xy^2
putting values of x, y we get k=36
solve k=36x

Like? Yes (2) | No (1)  

SHEREENA NISHAD   8 years AGO

x proportional to 1/y^2
x=k/y^2
when x=4 , y=3
4=k/9
k=36
when y=6
x=36/36
=1

Like? Yes (1) | No   

shaik basha   8 years AGO

1/x=k.y^2(k constant)
1/4=k.3^2
k=1/36
1/x=1/36.6^2
x=1

Like? Yes (1) | No   

Lakshmi Narayanan.k   8 years AGO

x*sq of Y=k
4*9=k
k=36.
x*sq of Y=36
x*36=36
x=1(option 1)

Like? Yes (1) | No   

pugazh gandhi   8 years AGO

x=k*1/sqr(y)
if x=4, value of y=3
then sub x and y value in above equation
value of k=36
if value of y=6
then value of x=1

Like? Yes (1) | No   

hemanth mallidi   8 years AGO

x=k/y^2
for x=4 and y=3,
4=k/9
k=36
therefore,
x=36/y^2
if y=6 then
x=36/36 = 1

Like? Yes (1) | No   

Indranil Mukherjee   8 years AGO

X=K/Y2
K=XY2
X=4, Y=3,
K=36
HENCE X=?,Y=6
WE GET K=36
SO THE ANS IS X=1

Like? Yes (1) | No   

harshit agarwal   8 years AGO

x=k/y^2
4=k/3^2
k=36
x=36/6^2
x=1

Like? Yes | No   

Mukund Manohar   8 years AGO

x=k*(1/y^2),where k = constant of variation
=> 4 = k*(1/3^2)
=> k = 36
When y = 6,
x = k*(1/6^2)
=> x = 36 *(1/36)
x = 1

Like? Yes | No   

PINTU PRASAD GUPTA   8 years AGO

let x =k*1/y^2
when x=4 than y=3

there for 4= k/9 -> k=36

when y=6
than x= k/y^2=k/36 = 36/36=1
there when y=6 than x= 1 ans.

Like? Yes (2) | No (2)  

Aman Kumar Jaiswal   8 years AGO

x varies with (1/y^2). So x=k.(1/y^2). Putting x=4 and y=3 then k=36. Hence for y =6 , we get x=1.

Like? Yes | No   

Tahair Amjad   8 years AGO

Since x is inversely proportional to y square, x2=((y1^2)/(y2^2))*x1
x2=(3^2/6^2)*4
x2=(9/36)*4
x2=1

Like? Yes | No   

Kunal nemu   8 years AGO

x = k/y^2
4 = k/3^2
k = 36
if y=6
then x = 36/6^2 = 36/36
x = 1

Like? Yes | No   

madanpal vishwakarma    8 years AGO

as per problem

x = k * (1/y^2)

where k is some constant
putting given values

4= k * (1/(3^2))

so k=36

if value of y=6 than

x= k*(1/(y^2))
x= 36 *(1/(6^2))
x=36/36
x=1

option 1 is correct .

Like? Yes | No   

V Swambika   8 years AGO

According to question the expression is in this form x inverse to y^2 which can be wriiten as x=k/y^2 where k is a constant.
Substituting the values x=4 and y=3 we get k=36.

Now substituting the value of k=36 and y=6 we get x=36/36 =1

Like? Yes | No   

aishwarya pandey   8 years AGO

x=[k/(y^2)]
so on putting x=4 and y=3 we get k= 36 where k is proportionality constant
so at y=6 x=1 answer

Like? Yes | No   

Priyaj   8 years AGO

x~1/y^2
x=k/y^2
4=k/9
k=36
now when y=6
x=36/36
x=1

Like? Yes | No   

Amitoj Singh   8 years AGO

x=4,y=3 and x=k/y^2
so k=36,
then, x.y^2=k, y=6
so,x=1

Like? Yes | No   

BIKRAM DEBNATH   8 years AGO

y^2=kx,
When x=4, y=3.. That putting the values in the above equation we get proportional constant k=36...
Now when y=6, putting y=6 & k=36 in the above equation we get x =1,
So ans is 1)1

Like? Yes | No   

Jayavikneshwaran.T   8 years AGO

x*sq(y)=k.
4*9=k=36.
x*36=36.
x=1(option 1)

Like? Yes | No   

akash patel   8 years AGO

we just make a simple equation x1/x2=y2squre/y1squre and put value.

Like? Yes | No   

Vignesh.S   8 years AGO

x=k(1y^2) given equation

if x=4 and y=3 then k=36

therefore if y=6 then
x=36(1/36)

therefore x=1 (option 1)

Like? Yes | No   

Dharms   8 years AGO

given cond: x=k(1/y^2)
for x=4 and y=4 ,the valve of k=36
for y=6 then x=36/36=1

Like? Yes | No   

Dr.Dipin Singh   8 years AGO

x=k/y^2
k= x*y^2 = 4*3^2=36
when y=6,
x= k/Y^2= 36/36=1

Like? Yes | No   

Sandip Das   8 years AGO

As x varies inversely with square of x, we can write
x=k/(y^2) ......(1) where k is constant
given x=4 and y=3
value of x and y put in equation 1
4=k/9
k=36
again given that y=6 and x=?
value of y put in equation 1
x=k/(6^2)
since k=36
=36/36
=1 (option 1)

Like? Yes | No   

Baishali Roy   8 years AGO

x=(k/y^2);
Therefore, 4=(k/3^2). So, k=36.
Now, y=6 & k=36. So, x= (36/6^2)=1
x=1 (opt. 1) (Ans).

Like? Yes | No   

pawan manglani   8 years AGO

x varies inversely as the square of y means x = (k/(y*y))
so by y=3 and x = 4 we get k = 36 .
So the value of x at y=6,
x = 36/(6*6)
x = 1

Like? Yes | No   

Samjukta Das   8 years AGO

x varies inversely as the square of y
Now,
x=k*1/y^2-------- eq1
x=4 when y=3
4=k*1/3^2
4=k/9
k=36
x=36*1/y^2-------- eq2
x=36*1/6^2
36*1/36
=1

Like? Yes | No   

Manisha gouri   8 years AGO

The solution is x=k/y^2
given values are x=4 and y=3 so, 4=k/9 then k=36
now given that value of y=6 then x=36/36=1

Like? Yes | No   

vasavi   8 years AGO

as x is inversely proportional the constant value is 36 and x value is this 36/36 so 1

Like? Yes | No   

NISHANT KUMAR   8 years AGO

x=k/(y*y)
4=k/9
k=36
x=36/(6*6)
x=1

Like? Yes | No   

Sourav Tener   8 years AGO

A/Q, f(x) = k/(y*y)

So, f(x)=4 has to be 36/(3*3)
which gives k=36

Similarly f(x) when y is 6 = 36/(6*6) =1

Thus x=1 when y=6

Like? Yes | No   

Ankit Sharma   8 years AGO

as x is inversily proportional to square of y hence there must be a proportionality constant let it be k.
therefore, x=k/(y^2);
when x=4 and y=3 => 4=k/3^2=k/9 => 4=k/9 => k=36
hence, for y=6,
x= 36/6^2= 36/36=1
hence x=1
option 1 is correct.

Like? Yes | No   

gulshan   8 years AGO

x=k*1/y^2
4=k*1/3^2
4=k*1/9
k=36
that
x=k*1/6^2
x=k*1/36
k=36x
x=1
k=36
tht's my ans 1

Like? Yes | No   

G.S.Kantharao   8 years AGO

As x is inversely proportional to square of y
in other words square root of x is inversely proportional to y.
Given x=4, y=3 that means 2 is inversely proportional to 3.
If y=6 then automatically x should be 1 as it is inversely proportional.
Hence the right choice is 1.

Like? Yes | No   

Garrepally Gopikrishna   8 years AGO

since x inversely proportional to y^2
then x1/x2=(y2/y1)^2
then 4/x2=(6/3)^2
4/x2=4
then x2=1

Like? Yes | No   

Pooja Sugandhi   8 years AGO

since x is inversely as the square of y then we get value of constant as 36 and then x is 36/6^6 = 1

Like? Yes | No   

PALLAB PATRA   8 years AGO

x= k / y^2 (where k=constant)
given x=4 and y=3
so we can write 4=k/9
or,k=36
now y=6
so the value of x will be, x=36/6^2
or, x=36/36
i,e x=1 (ans)

Like? Yes | No   

shivangi rastogi   8 years AGO

x*k=1/(y*y)
for x=4and y=3,
the value of k=1/36
and hence when y=6,
putting the value of kand y in the above eq. the value of x is 1

Like? Yes | No   

Waquar Raza   8 years AGO

we have:
1/x= c y ^2 where c is constant.
putting values x=4 and y=3 we get c= 1/36.
now putting y= 6 we get x=1

Like? Yes | No   

nimisha gupta   8 years AGO

X is intensely propotional to y^2
i. e x=k/y^2
Putting the value x=4 & y=3 we get
K=36
Now using this value of k in the equation having y=6 we get
X=1

Like? Yes | No   

Pawan kumar   8 years AGO

x=k/y^2 determines the value of k=36
then substitute the value of y =6 in equation

Like? Yes | No   

dhruv chaubey   8 years AGO

since the values are in inverse proportion. and given x=4, y=3 which will give, 4=1/9..
thus when y =6, x=1/6^2 and follow the above conditions..
thus x=1

Like? Yes | No   

lakshmi sahithi   8 years AGO

4=k/3^2
k=36
x=36/6^2
x=1

Like? Yes | No   

sachin soni   8 years AGO

x is inversely proportional to y
hence x*y*y = constant = k(say)
hence k = 36 for x=4, y =3
so when y=6 x=1
hence option 1 is correct.

Like? Yes | No   

ASHWIN SHANMUGAM   8 years AGO

const=36
when x is 4 and y is 36
so we get x = 1 when y = 6
x=const/(y)^2

Like? Yes | No   

Abhik Poddar   8 years AGO

x=k/(y*y)
4=k*(3*3)
k=36
So,x=36*(1/36)=1...So the answer is 1

Like? Yes | No   

Sowjanya a v   8 years AGO

x is inversely proportional to y^2
x1/x2=(y1)^2/(y2)^2
given x1=4,y1=3,y2=6,x2=?
4/x2=6^2/3^2
x2=4*9/36
x2=1
therefore answer is 1

Like? Yes | No   

Anant Mishra   8 years AGO

x=k*1/y*y
4=k*1/9
k=36

now
y=6, x=?
x=k*1/y*y
x=36*1/36
x=1;

Like? Yes | No   

sujit sinha   8 years AGO

when x=4 ,and y=3 then the proportionality constant will be.. k = x*y*y..
I.e k=36
now put y= 6and k= 36 .. to get the answer i.e x =1

Like? Yes (1) | No (2)  

Aakash Beniwal   8 years AGO

x = k/(y^2)
put x= 4 , y = 3
k comes 36
now put k=36, y=6
x value comes 1 (answer)

Like? Yes (1) | No (2)  

jayant   8 years AGO

From the question , we can write,
x1/x2=(y2*y2)/(y1*y1) [since x varies inversely as square of y]

putting x1=4; y1=3 and y2=6 in the above equation, we get the answer x2=1
So x =1 when y=6

Like? Yes | No (1)  

DEVANSH SUBNANI   8 years AGO

x=(k)/(y^2)
4=k/9
k=36
x=(k)/(y^2)
x=36/36=1
Option 1)

Like? Yes (1) | No (2)  

kondapuram tirumalreddy   8 years AGO

given
x varies inversly as the square of y
means
x = k/y^2
==> k = 36
then x =k/y^2
x=36/36 = 1

Like? Yes | No (1)  

Leela   8 years AGO

x#(1/Y2)
LET
X= K*(1/Y2)
SUBSTITUTE VALUES X,Y WE GET K =36
HENCE BY SUBSTITUTING Y VALUE AND K VALUE WE GET X NOW

Like? Yes | No (1)  

prakash sharma   8 years AGO

According to puzzle x=k/(y^2) where k is constant
then
4=k/9 then k=36
so
if y=6 thenput the value of kand y in above eq.
x=36/(6^2)=1

Like? Yes | No (1)  

megha agarwal   8 years AGO

x=k/y^2 (k is proportional constant)
when x=4 y=3
4=k/(3^2)
k=36
now equation becomes x=36/y^2
putting y=6
x=36/6^2
x=1

Like? Yes | No (1)  

Dinesh kumar sah   8 years AGO

Simply ,given that x is inversely proportional to y^2.
when x1=4,y1^2=9
when x2=?,y2^2=36
ie 4:x2 :: 36:9
if we simplify the above equation then we will get x2=1 Ans
Hence option (1) is the right answer.

Like? Yes | No (1)  

Joshi Bhargav    8 years AGO

Here the ans is 1.bcz here x is inversely proportional to square of the Y. So here X=1/Y2.
~Now when x=4 and y=3. That time we get 36=1.
~And when Y=6 that time we get 36=1.
So here L.H.S=R.H.S

Like? Yes | No (1)  

VISHAL.MORI   8 years AGO

HERE,
the given condition is X proposnal to 1/Y^2.

so, X=A/Y^2

4=A/9
A=36
then X=A/Y^2
so, X=36/36
X=1

Like? Yes | No (1)  

gayathri   8 years AGO

x is inversely proportional to square of y.To remove proportionality ,introduce a constant A.
X=A*(1/y^2)
sub X=4 and Y=3,
4=A*(1/9)
A=36.
X=? when Y=6
X=36*(1/6^2)
X=1
answer for X is 1

Like? Yes | No (1)  

shivani shukla   8 years AGO

let us assume that x=k/(y*Y]
y=3 for x=4
so k=36
if y=6
then x=1

Like? Yes (1) | No (2)  

Dharini Maheshwari   8 years AGO

x=k/y2 ...
x=4 when y=3... k=36..hence x=1at x =6

Like? Yes | No (1)  

RAVI SHARMA   8 years AGO

we can solve this by inverse variation rule. x1(y1)2 = x2 (y2)2

Like? Yes | No (1)  

sai prathyusha   8 years AGO

x is inversely proportional to y square means
x=k/(y*y)
k is constant
x=4,y=3 then k=36
now k=36,y=6 then x=36/36=1

Like? Yes | No (1)  

T.GOWRISANKAR   8 years AGO

x varies inverse with respect to y
if y=6^2=36.so y increses 4 times from the first one.
then by inverse relation x must be decrease by 4 times.so x=4/4=1.

Like? Yes | No (1)  

Dhaval Vekariya   8 years AGO

x=k/y^2
k=36
x=36/6^2
x=1

Like? Yes | No (1)  

sanjeet kumar   8 years AGO

Since x varies inversly promotional to y^2.

x =k/y^2
Putting x=4 and y = 3.
We get k = 36.
So when y = 6.
x = 1

Like? Yes | No (2)