The population of town is 352800. If it increases annually at 5%, what will be its population 2 year

ayushi mishra   8 years AGO

2 year hence population is
p*((1+r/100)^n)
p=population=352800,r=5,n=2
352800*((1+5/100)^2)=388962
2 year ago,
P/((1+r/100)^n)
352800/((1+5/100)^2)=320000

Like? Yes (11) | No (4)  

himanshu   8 years AGO

just use the formula ,p=P(1+(growthrate/100))^n
where n is no. of year
to calulate 2 year ago use p=P(1-(growthrate/100))^n

Like? Yes (15) | No (9)  

sanjeet kumar   8 years AGO

5% of 352800 = 17640
Now 352800 + 17640 = 370440
Total population after 10 years = 370440 + 5% of 370440 = 388962.
Then using the given data we see 10 years ago the population was 320000.
Since 5% of 32000 and again 5% of the obtained numbers gives the same result

Like? Yes (7) | No (2)  

Ankit Sharma   8 years AGO

2 Year Hence -
1st year => 352800*5/100=17640 => 352800+17640=370440
2nd year =>370440*5/100=18522 => 370440+18522=388962

2 year ago-
352800*100/105=336000
336000*100/105=320000
so answer is option 8,
388962,320000

Like? Yes (3) | No   

BIKRAM DEBNATH   8 years AGO

Total Increase rate in 2 yrs = 5+5+(5*5/100) % = 10.25%
So after 2 yrs total population will be 352800+ 352800*10.25% = 388962,
Let Before 2yrs population was x, 2 yrs ago it was x+ x*10.25%= 352800, x = 320000... Hence ans is option 8

Like? Yes (4) | No (2)  

Vishnu Prakash   8 years AGO

By adding 5% of population of town successively for two times, we get population after 2 years and similarly for 2 years ago.

Like? Yes (1) | No   

PINTU PRASAD GUPTA   8 years AGO

let population 2 year ago is x :
population after 1 year = x(1+5/100)= x*21/20
population after 2nd year = x*21/20(1+5/100) = x*21*21/400 this is current population 352800
x= 400 * 352800/441= 400*800 = 320000

population after 2 year = 352800*21*21/400=388962

answer will be : 8) 388962 , 320000

Like? Yes (1) | No (1)  

Vijay   8 years AGO

actually it is 352800 .After two years it becomes 388962.
before 2 years it is 320000

Like? Yes (1) | No (1)  

mohana priya.k   8 years AGO

populatoin after n years=p(1+r/100)^n
therefore, population after 2 years=352800(1+5/100)^2
=388962
population n years ago=p/(1+r/100)^n
therefore 2 years ago=352800/(1+5/100)^2
=320000

Like? Yes (2) | No (2)  

karthi   8 years AGO

GIVEN: P=352800,R=5%,n=2
population after 2 yr=P(1+R/100)^n
=352800(1+5/100)^2
=352800(100+5/100)^2
=352800(21/20*21/20)
=388962
population 2yr ago =P/(1+R/100)^n
=352800/(1+5/100)^2
=352800*20/21*20/21
=320000

Like? Yes (1) | No (1)  

G.S.Kantharao   8 years AGO

Population = 352800
Increse rate = 5% per annum
After 2 years population=
352800(21/20)^2=388962
Two years backk populatiin= 352800(20/21)^2 =320000
Hence the answer is 388962,320000.
Right choice is 8.

Like? Yes (2) | No (2)  

Samjukta Das   8 years AGO

Population after n years=P(1+R/100)^n
So 352800(1+5/100)^2
388962

Population before n years=P/(1+R/100)^n
So 352800/(100+5/100)^2
320000

Like? Yes | No   

lakshmi sahithi   8 years AGO

p=352800(1+5/100)^2=388962
p(1+5/100)^2=352800=320000 is ago two years

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DEVANSH SUBNANI   8 years AGO

Population 2 years hence=352800*(105/100)*(105/100)=388962
Population 2 years ago=320000*(105/100)*(105/100)=352800
Option 8)

Like? Yes | No (1)  

Gayathri Murugesan   8 years AGO

5% of 352800 is 17640 then after 1 year, population will become 370440. 5% of 370440 is 18522 thereafter after 2 years population will be 388962.
5 % of 320000 is 16000, before 1 year population will be 336000. 5% of 336000 is 16800 therefore at present population is 336000+16800 = 352800.
Hence the correct answer is option 8

Like? Yes | No (1)  

harshit agarwal   8 years AGO

352800+5% of 352800
352800+17640=370440
370440+5% 370440
370440+18522=388962

Like? Yes (1) | No (2)  

brijesh tripathi   8 years AGO

for calculating 2 year hence population we use this formula
a=p(1+r/100)^n
then =352800(1+5/100)^2=388962
and
calculating 2 years ago population by this formula p/[1+r/100]^n
352800/[1+5/100]^2=32000

Like? Yes | No (1)  

deb   8 years AGO

2 years after 352800(1+5/100)^2=388962. 2 years ago 352800/(1+5/100)^2=320000

Like? Yes | No (1)  

NIKHIL   8 years AGO

35200(1+5/100)^2=388962
35200(1-5/100)^2=320000

Like? Yes | No (1)  

pugazh gandhi   8 years AGO

5% increase from 352800
352800*1.05=370440
for second year
370440*1.05=388962

so ans is opt 8

Like? Yes | No (1)  

Anant Mishra   8 years AGO

consecutive % formula
a+b+ab/100

after 2 years
5+5+5*5/100=10.25%
352800+(10.25*3528)=388962

before 2 years
x +(10.25*x)=352800
then x=320000

Like? Yes | No (1)  

pranav   8 years AGO

let given population be "x" therefore
after one year population will be y= x+ .05x
therefore after two years population will be z= y+.05y
which will be 388962
now for one year before we are given population of one year after, therefore a+.05a=352800, a=336000
one year before , b+.05b=a=336000,b=320000
so option 8 is correct

Like? Yes | No (1)  

A.KARTHIKA   8 years AGO

population now=352800
1 yr hence= 352800*(105/100)=370440
2 yrs hence= 370440*(105/100)= 388964
ans:- 8) 388964

Like? Yes | No (1)  

dhruv chaubey   8 years AGO

105%of 352800=sum
105%of sum=population aftr 2yrs= 388962
similarly do it for 2years ago

Like? Yes | No (1)  

Deepapriya.s   8 years AGO

formula:p(1+r/100)^n
here p=352800,n=2,r=5%
so
352800(1+5/100)^2=388962
similarly for the 2 years back we get
a(1+5/100)^2=352800
here a is the population of the town and it is increased by 352800 for two years is already we know .
p=352800/(1.05*1.05)=320000.

Like? Yes | No (1)  

prakash sharma   8 years AGO

let the population of two year ago=x
then according to puzzle (x*105/100)*105/100=352800
so x=320000 means population of two year ago was=320000
then now
after two year (352800*105/100)*105/100=388962

Like? Yes (1) | No (2)  

JENSI KARUNYA.S   8 years AGO

CI=352800[(21/20)^2-1]
CI=36162
POPULATION AFTER 2 YEARS=388962
X+(X/20)+(X/20)+(X/400)=352800
X=320000

Like? Yes | No (1)  

nimisha gupta   8 years AGO

For 2 years hence,
105% *(105% *352800)
=388962

For 2 years ago,
X=(352800*100*100)/(105*105)
=320000

Like? Yes | No (1)  

Chitrala Venkatesh Babu   8 years AGO

population after n years=p(1+(r/100))^2
population after 2 years=352800*(441/400)
=388962

population before n years=p(1+(r/100))^2
population before 2 years=352800/(441/400)
=320000

Like? Yes | No (1)  

Rahul Das   8 years AGO

For 2 years hence,
After 1st year =(352800+17640)
After 2nd year=388962
For 2 years ago,
1 year before = (320000+16000)=336000
and 352800 is present population

Like? Yes | No (1)  

Jyoti Adwani   8 years AGO

1.for 2 years hence->5% of 352800=17640,hence population after 1 year 3,70440 and 5% of 3,70440=18522and hence population after 2 yrs =388962
2. with similar reasoning lets population yrs ago be x and hence current population is 1.1025x and hence x=320000

Like? Yes | No (1)  

Laxmi Thakkannavar   8 years AGO

Population after 2 year is given by=352800(1+(5/100))^2
which is equal to 388962
and population before 2 years ago was=352800/(1+(5/100))^2
which is equal to=320000

Like? Yes | No (1)  

Prantik Chatterjee   8 years AGO

simple formula

New populations=old(1+r/100)^n

Like? Yes | No (1)  

akash patel   8 years AGO

we apply simple formoola of math and put value and solve it

Like? Yes (1) | No (2)  

Devireddy Jashuva   8 years AGO

352800*(105/100)*(105/100)=388962
x*(105/100)*(105/100)=352800 then x=320000

Like? Yes | No (1)  

Gandham bharath   8 years AGO

population 2 years hence= p*(1+(r/100))^n
population 2 years ago= P/(1+(r/100))^n
where p=352800, r=5%, n=2.
therefore, by sub we get solution as 388962,320000

Like? Yes | No (2)  

Dinesh kumar sah   8 years AGO

Very simple given that p=352800,r=5?,t=2years

1)After 2 years population is p[1+r/100]^t=352800[1+5/100]^2=388962

2)2 years ago population is p/[1+r/100]^t=352800/[1+5/100]^2=320000

Hence option (8) is the right answer.

Like? Yes | No (2)  

SHUBHAM GUPTA   8 years AGO

increase of 5% in 1 year =370440
increase of 5% in 2 year =388962
similarly
it was 320000 back 2 years.
as
for past 1 yr 105% of x=352800
so x=336000
for past 2 yr 105% of x=336000
so x=320000

Like? Yes | No (2)  

tejaswi A   8 years AGO

352800+(352800*5/100)=370440
hence population after 1 yr=370440
hence after one more year=388962
only 8th option contains first answer=388962 ..hence option 8

Like? Yes (1) | No (3)  

sonal agrawal   8 years AGO

p = 352800
1st year = 352800 (1.05)
=3,70,440
2nd year= 3,70,440 (1.05)
= 3,88,962
let 2year ago be x
1st year = x (1.05)=1.05x
2nd year = (1.05)^2x =(1.1025)x

(1.1025)x = 3,52,800
x = 3,20,000

Like? Yes | No (2)  

Lakshmi Narayanan.k   8 years AGO

352800*1.05*1.05=388962
X*1.05*1.05=352800
X=320000.(option 8)

Like? Yes | No (2)  

Vignesh.S   8 years AGO

since it is given as every year the population is increased by 5% so every year the population is multiplied by 1.05

therefor for 1year after the population is
352800*1.05 = 370440
after two year the population is 370440 *1.05 = 388962


similiarly we have to divide for previous year therefore

1 year before the population is 352800/1.05 =336000
2 year before the poipulation is 336000/1.05 = 320000

therefor the answer is 388962,320000 option (8)

Like? Yes | No (2)  

ujjawalkumar    8 years AGO

formula is :
p(1+/- r/100)^m

where p= current population
r= rate of increase or decrease
m=no. of month

Like? Yes | No (2)  

Pallavi Pawar   8 years AGO

1st year = 352800*5/100=17640
Population after one year = 352800+17640=370440
Population after 2nd year = 370440+370440*5/100=388962

Like? Yes | No (2)  

Mayank Kumar   8 years AGO

5% of 352800 = 17640,
352800+17640= 370440

5% of 370440 =18522
370440+18522= 388962.

(5% of x) + x = 352800,
x =336000

(5% of y) +y = 336000
y = 320000

hence option 8 is correct

Like? Yes | No (2)  

Saurabh Upadhyay   8 years AGO

Population after n years = 352800(1 + 5/100)^2
Population before n years = 352800/(1 + 5/100)^2

Like? Yes | No (2)  

abhinav   8 years AGO

after 2 yrs = 1.05*1.05*352800= 388962
x*1.05*1.05=352800 == x=320000

Like? Yes | No (2)  

Divya   8 years AGO

the population is compounded annually @ 5%
so population after 2 years will be

352800(1+5/100)^2=388962

8 is the only option with answer

Like? Yes | No (2)  

Mukund Manohar   8 years AGO

Population after 2 years = 352800[1+(5/100)]^2
= 882 * 441
= 388962
Population 2 years ago = 352800/[1+(5/100)]^2
= 320000

Like? Yes | No (2)  

Manish   8 years AGO

two years later population(352800*105*105)/100*100=388962
two years ago=(352800*95*95)/100*100 =320000

Like? Yes | No (3)  

shivani shukla   8 years AGO

2 year hence population is
p*((1+r/100)^n)
p=352800,r=5,n=2
352800*((1+5/100)^2)=388962
2 year ago
p/((1+r/100)^n)
352800/((1+5/100)^2)
=320000

Like? Yes | No (3)  

SUSANTA KUMAR DAS   8 years AGO

352800×(105/100)×(105/100)=388962( For 2 years hence)
352800×(95/100)×(95/100)=320000(For 2 years ago)

Like? Yes | No (5)