A sum of Rs. 12,000 amounts to Rs. 15,000 in 4 years at the rate of simple interest. What is the rat

G.S.Kantharao   7 years AGO

Principle =RS.12000
Amount=RS.15000
Interest = RS.15000-Rs.12000=RS.3000
Rate = 100I/PT
Here P=12000
T=4
Rate R=(100*3000)/(12000*4) = 25/4 =6.25%
Hence the right option is 8.

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PRABHAT KUMAR   7 years AGO

p 12000
a 15000
si 15000-12000=3000
rate (3000*100)/12000*4
6.25%
option 8
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Ramsb   7 years AGO

I=15000-12000
R.I=(3000*100)/12000*4
R.I =100/16
R.I=6.25

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Mukund Manohar   7 years AGO

Rate of Interest = (3000*100)/(12000*4)
= 300/48
= 6.25%

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ishwariya   7 years AGO

interest =15k - 12k =3k ,si=pnr/100
3000=12000*4*r/100
r=300/48=6.25%

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ssssss   7 years AGO

S.I. = Rs. 15000 – Rs. 12000
S.I. = Rs. 3000
Rate of Interest = (100 × S.I.)
(P × T)
= (100 × 3000)
(12000 × 4)
= 6.25 %

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pujithabollareddy   7 years AGO

interest amount -(15000-12000)=3000
per one year 750
in 12000 750 is how much percent =6.25percent

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varun chawla   7 years AGO

beacuse here interest is 3000 and interest = principle* rate*time/ 100 so put the value get the result

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Gaurav kumar   7 years AGO

SI=rs(15000-1200)=3000

Rate=(3000*100/12000*4)%=6.25%

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Pragati Rode   7 years AGO

Simple Interest = 15000-12000 = 3000

Rate = (SI * 100)/(P*N)
=3000 * 100/12000*4
= 300/48
=6.25%

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Abhishek Gupta   7 years AGO

Amount = S.I + P, i.e, 15000 = S.I + 12000, Therefore
S.I = 3000,
S.I = (P*R*T)/100 therefore,
3000 = (12000 * R * 4)/100
R = 6.25%

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Pardeep Jangra   7 years AGO

interest 15000-12000=3000
Time =4 Year
Rate of interest =interest.100/time.
Principal
3000.100/12000.4=
=6.25% Ans

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nimisha gupta   7 years AGO

Principal =12000
Amount=15000
So si=a-p
=15000-12000=3000
Using the formula,
Si=(p*r*t) /100
R=6.25%

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DARE   7 years AGO

SI=PTR/100
SI=AMOUNT-PRINICPLE
SO, 15000-12000=(12000*4*R)/100
3000=120*4*R
R=3000/120*40
R=6.22%

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Rakesh   7 years AGO

SI=amount-sum
SI=3000
r=SI*100/p*T
r=3000*100/12000*4
r=6.26%

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Vaibhavi C   7 years AGO

Simple interest (SI)= total amount- principal amount
= Rs. 3,000
Also,
SI=PRT/100
3,000=12,000*R*4/100
Solving for R we get
R=(3,000*100)/(12,000*4)
R=6.25%

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gowtham   7 years AGO

a=p+si
si=3000
si=ptr/100
r=6.25%

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divya   7 years AGO

Interest for 4 year= 15000-12000=3000
SI=Pnr/100
P=12000,n=4, si=3000 r=?
So 3000=12000*4*r/100
R=3000*100/12000*4
=25/4
=6.25

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Siva   7 years AGO

I=pnr/100
r=(3000×100)/(12000×4)
=6.25%

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UTTAM SINGH   7 years AGO

If we take 1% of 12000 than it will be 120 but to get 3000 in four year we have to be 750 per year so to get 750 interest we have to multiply 120 by 6.25 than we can get 750 so it's answer is 6.25%

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chinnu   7 years AGO

(15,000 - 12,000) = (P*T*R)/100
WHERE P = 12,000 RS/-
T = 4 YEARS
BY SOLVING, WE GET R = 6.25%

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NATCHAMMAI   7 years AGO

simple interest=15000-12000
so SI=3000
we know that,
SI=PNR/100
so 3000=(12000*4*r)/100
r=(3000*100)/(12000*4)
so r=6.25%

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Mani kandan   7 years AGO

SI=PNR/100 ;
R=SI*100/PN => SI =15000-12000 =3000, P=12000,N=4
R=3000*100/12000*4 =6.25%

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Bishal Kumar Shaw   7 years AGO

total SI 3000
amount is 12000
year is 4 yrs
using P*R*T/100 = SI

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Ajay Sharma   7 years AGO

amount = p(1+r*t)%
15000=12000(1+r*4)%
r=1/16%
r=6.25

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amit kumar   7 years AGO

p=12000, S.I=15000-12000=3000, Rate=3000*100/(12000*4)=6.25%

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UMESH REDDY   7 years AGO

principle ampont is 12000
total is 15000
inrest is 15000-12000=3000
a/c to formula I=ptr/100
3000=(12000*4*r)/100
r=6.25%

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varsharani   7 years AGO

si=15000-12000=3000
p=12000
t=4
r=?t
r=(100*si/p*)
=6.25

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Puneet Garg   7 years AGO

S.I. = 15000-12000 = 3000;
3000= (12000 X 4 X rate)/100
rate = 6.25 %

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