Find the value of x^2 - 3x/2 - 4 Given equation: (3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7

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22 Feb 2017 Find the value

Find the value of x^2 - 3x/2 - 4
Given equation:
(3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7 + x^2

OPtion

1) 0
2) 1
3) 2
4) 3
5) 4
6) 5
7) 6
8) 7
9) 8
10)None if these

Solution

Given
(3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7 + x^2
=>x^2 = 6^2 - 2 - 1 - 6 - 2 - 1 - 1 - 7
=>x^2 = 16
=> x = 4
So x^2 - 3x/2 - 4= 16 - (3/2)*4 - 4 = 16 - 6 - 4 = 6

Correct Option: 7 Best Solution (20)

G.S.Kantharao   7 years AGO

(3!)^2-(2!)^1-(1!)^0-3!-2!-1!-0!=7+x^2
(6)^2-(2) - (1)- (6) - (2) - (1) - (1) = 7 + x^2
36 -2-1-6-2-1-1 = 7 + x^2
36 - 13 - 7 =x^2
x^2 = 16
x = ± 4 (But here 4 was taken)
The value of x^2 - 3x/2 -4 = 4^2 - 3*4/2 - 4= 16 - 6 - 4 =6
Hence the right option is 7.

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Nitish kesarwani   7 years AGO

Solve given eqn X =4
Put in eqn 1
So that 4^2-3*4/2-4 =6
Optn 7

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Amarnath Kumar Upadhyay   7 years AGO

on solving given equation x^2=16
x=4 and x=-4

now value of X^2-3x/2-4 when x=4
value=6

Like? Yes (1) | No   

Mukund Manohar   7 years AGO

In the given equation,
7 + x^2 = 36-2-1-6-2-1-1
=> 7 + x^2 = 23
=> x^2 = 16
=> x = 4
Now,
x^2 - 3x/2 - 4
= 16 - 6 - 4
= 6

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Harsh Poddar   7 years AGO

36-2-1-6-2-1-1=7+x^2
X^2=16
X=4,-4
Putting 4 in equation value =6
Option 7

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sindhu   7 years AGO

36-2-1-6-2-1-1=7-x^2
X^2=16
X=4
16-3*4/2-4=6

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DIVYANSHU SHEKHAR   7 years AGO

36-2-1-6-2-1-1=7+x^2
=>x=(16)^1/2 =4
now, x^2-3x/2-4
=4^2-3*4/2-4
=6

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RANJEET KUMAR   7 years AGO

X=4,
now putting the value in above equation we will get the required value as 6

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Rolly Agarwal   7 years AGO

36-2-6-2-1-2=7+x^2
x=4
x^2-3x/2-4
=6

Like? Yes | No   

Pragati Rode   7 years AGO

By solving given equation we get

6^2 - 2^1 - 1^0 - 6 - 2 - 1 - 1 = 7 x^2
36 - 2-1-6-2-1-1 -7 = x^2
x^2 = 36 - 20=16

=> x = 4

put this value in x^2 - 3x/2 - 4
=16 - 6 - 4=6
so option is 7

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Baishali Roy   7 years AGO

The given equation states that 7+x^2= (6^2)-2-1-6-2-1-1
Therefore, x^2=16, & x=4
Now, x^2-(3x/2)-4=(4^2)-(3*4/2)-4=6 (Ans). (Opt 7)

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Dhaval   7 years AGO

from given equation we can get x=4
after that put the value of x in equation x^2-3x/2-4. and value is 6.

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sani musa tsoho   7 years AGO

Here, (3!)^2-(2!)^1-(1!)^2-3!-2!-1!-0!=23
=> 23=7+x^2
23-7=x^2
x^2 =16
therefore, x=4
Hence, 4^2-3(4)/2 - 4
= 16- 6-4
=6
Option 7 is correct option

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SHUBHAM   7 years AGO

X^2+7=36-2-1-6-2-1-1-1
=>X=4
hence X^2 - 3(X/2) -4=6

hence option 7 is correct

Note:0!=1

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himabindu   7 years AGO

given that
(3!)^2 - (2!)^1- (1!)^0 - 3! - 2! - 1! - 0! = 7+x^2
(6)^2 - 2 - 1 - 6 - 2 - 1 - 1 = 7+x^2
36 -13 = 7 + x^2
x^2 = 16
x=4
so
x^2 - 3x/2 - 4 = 16 - 6 -4 =6

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yamini velaga   7 years AGO

on solving the given equation, we get
(6^2) - 2 - 1 - 6 - 2 - 1 - 1 = 7 + x ^ 2
x = 4
then 4^ 2 - (3×4 ÷ 2 ) - 4 = 6

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Golluru Lalitha   7 years AGO

From given condition ( 2nd line ) we get x^2 as 16
so we get x as 4
put this values in given equation 1 then we get result as 6

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mandeep   7 years AGO

solve second equation
36-2-1-6-2-1-1=7+x^2
x=4
put value in the first equation
it gives 6

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vky   7 years AGO

x^2 = 16
hence by putting the value we can get the value of given funcation is 6

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Ajay Sharma   7 years AGO

from eq. (3!)^2-(2!)^1-(1!)^0-3!-2!-1!-0!=7+x^2
=36-2-1-6-2-1-1-7=x^2
=16=x^2
x=+4 or -4
putting value in eq.x^2-3*x/2-4
=16-3*2-4 or 16+6-4
6 or 18
since 1 of option is 6, hence 7 is correct option

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