Rahane scored 38 runs in 2nd innings of test match against Australia which included 4 fours and 2 si

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03 Apr 2017 Percentage

Rahane scored 38 runs in 2nd innings of test match against Australia which included 4 fours and 2 sixes. What percent of his total 2nd innings score did he make by running between the wickets?

OPtion

1) 25.12%
2) 25.32%
3) 25.52%
4) 25.82%
5) 26.02%
6) 26.22%
7) 26.42%
8) 26.32%
9) 26.62%
10)26.82%

Solution

Number of runs made by running = 38 - (4 x 4 + 2 x 6)
= 38 - (28) = 10

Required percentage = (10/38)*100 = 26.32%
Option 8)

Correct Option: 8 Best Solution (9)

G.S.Kantharao   7 years AGO

Rahane Scored 38
Runs scored as per 4s 6s= 4*4+2*6=28
Remaining runs 38-28=10 Percentage= 26.32%
Hence my option is 8.

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Harsh Poddar   7 years AGO

Runs scored in boundaries=4×4+6×2=28
Runs scored running between wickets=38-28=10
%runs=10/38*100=26.32
Option 8

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Azim Uddin Siddiqui   7 years AGO

total runs scored=38;
runs scored in boundaries=4*4+2*6=28;
runs scored by running= 38-28=10
%age of runs scored via running between wickets=10/38*100=26.315=26.32 ans. option no 8

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palak Jain   7 years AGO

Score made by 4 fours and 2 sixes=28
Total runs scored=38
So,runs scored by running=10
10/38*100=26.32%

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Hitesh Kumar Tiwari   7 years AGO

Runs by four and sixes percentage = 28/38 *100
= 73.684%
Then between the wickets = 100 - 73.684
= 26.32 %

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Pratyush Singh   7 years AGO

4foures=16
2six=12
38-28=10
(10*100)/38=26.315

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kandi sindhuja reddy   7 years AGO

rahane total runs = 38
made 4 fours = 4*4 = 16
made 2 sixes = 2 *6 = 12
16+12 = 28
running between wickets = 38-28 = 10
percentage of runs between wickets = 10/38 =0.2631
=> 0.2631*100% = 26.32%

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Indra Kumar mishra   7 years AGO

28 runs by boundaries and 10 by running. so 10/38*100 = 26.32.

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lucky   7 years AGO

after removal of 28 runs from boundaries then remaining 10 runs divided by total 38 runs multiplied with 100 gives 26.31578 which approximately equals 26.32 percent

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