A is 4 years older than B and B is twice as old as C. The total of the ages of A, B and C is 44 year

Mukund Manohar   7 years AGO

A = B+4 and B/2 = C
A+B+C = 44
=> B+4+B+B/2 = 44
=> 5B+8 = 88
=> B = 16 years
So, A = 20 years and C = 8 years
Product of their ages = 20*16*8 = 2560

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AYAN PAUL   7 years AGO

Let the Age of B is x so Age of A will be x+4 and Age of C will be x/2
So we can write x+x/2+x+4 = 44
from here we get x = 16
So A = 20 B = 16 and C = 8
Now product of ages of A B & C will be 16*20*8 = 2560

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SAYAN CHATTERJEE   7 years AGO

B=2C
A=B+4
=2C+4
SO, C+2C+2C+4= 44
SO, C= 8
B= 16
A= 20
SO, A*B*C= 20*16*8
2560.
Option 8.

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Ravi   7 years AGO

let c's age is x then B's will be 2x and c's will be 2x+4 so total age of A+B+C=44
then 2x+4+2x+x=44 ,then x= 8 age of A=20
B=16 and C=8 product of their ages will be
20×16×8=2560

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Varun   7 years AGO

Let C's age be x
Then B's age = 2x
A's age = 2x + 4
Sum of ages = 5x + 4 = 44
Therefore x = 8

That gives present ages as :
C = 8
B = 16
A = 20

So, it gives product as 2560.

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abhishek   7 years AGO

Let age of C is x.
Then age of B is 2x.
And age of A is 2x + 4.
Now x + 2x + 2x + 4 = 144.
5x + 4 = 44
x = 8.
Then age of A is 20, B is 16 and C is 8.
Therefore there product is 8 * 16 * 20 = 2560.

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Deepesh Mittal   7 years AGO

C age x,
then B age is 2x.
so A age is 2x+4.
(2x+4)+2x+x=44
5x=40
x=8
So, B is 2x=2(8)=16
A is (2x+4)=20
C is 8.
Hence, 20*16*8 = 2560.

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G.S.Kantharao   7 years AGO

Let the age of C =x
Then B's age=2x
A'sage is =2x+4
Their sum =(2x +4)+ (2x)+ (x)=5x+4=44
5x=40
X=8
Then their ages are=20,16,8
Product=20*16*8=2560
Hence the right option is 8👈

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KRISHNAKUMAR   7 years AGO

Let age of c is =x
The age of b is =2x
The age of a is =2x+4
Sum of age is =5x+4=44
So x= 8
Product is =8×16×20=2560

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Pritam Paul   7 years AGO

Let the age of C is X.
Age of B is 2X.
Age of A is 2X+4

X+2X+(2X+4)=44
X= 8
Age of C is 8, B is 16 and A is 20
The product of A,B and C is (8×16×20)= 2560

Like? Yes | No   

Tarun varshney   7 years AGO

let b age = x
and a age =x+4
then c age = x/2
age ( a+b+c)=44
x.=16
age multiple =20*16*8

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mandeep   7 years AGO

a=b+4. b=2c
a+b+c=44
solve and get a=20 b=16 c=8
and the product is 2560

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g lokesh   7 years AGO

Let us assume age of C = x yrs
so , B =2x
A = 2x+4
total age is x+2x+2x+4=44
on solving X= 8
ages of a,b and c is 20,16 and 8
product of them is 2560

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Nidhi kumari   7 years AGO

A= B+4 years
B= 2C years
C = B/2

A+B+C= 44years
B+4+B+B/2 =44years
B = 16years
A= B+4= 16+4= 20years
C= B/2 = 16/2= 8years

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umend   7 years AGO

Let A,B,C be the ages of A,B,C respectively
Then A=4+B
B=2C
A+B+C=44
Solving abv 3 equation gives
A=20. B=16. C=8
ABC=20*16*8=2560
Ans:2560

Like? Yes | No   

Madhuvani v   7 years AGO

Let C=X years, B=2X years , A=(2X+4) years
A+B+C=44
2X+4+2X+X=44
X=8
The product of the ages is = (2X+4)(2X)(X)
= 4X^3+8X^2 = 2048+512 = 2560

Like? Yes | No   

Arijit sarkar   7 years AGO

let c age be x.
then B age will be 2x.
A will be 2x+4.
5x =40
since sum is given . so x=8.
after multiplying we get 2560

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ManikumarSoruvu   7 years AGO

c=x,b=2x,A=2x+4
2x+4+2x+x=44
x=8
Therefore,product=8*16*20=2560

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pooja khannawalia   7 years AGO

Let the age of C be x.
then the age of B = 2x.
Now the A is four years older than B i.e., 2x + 4.
A.T.Q.
x + 2x + 2x+4 = 44
x= 8
2x = 16
2x + 4 = 20
8*16*20 = 2560 (Ans)

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D Ramya   7 years AGO

first we will find B age by using given information..then remaining ...so the product will be 2560

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Akash   7 years AGO

A=B+4
B=2C => A=2C+4
WKT A+B+C = 44
2C+4+2C+C=44
5C+4=44
5C=40
C=8
A=20
B=16
A*B*C=2560

Like? Yes | No   

Shaswata Bisi   7 years AGO

Let the age of A, B and C be a,b and c respectively
b=2c
a=4+b=4+2c
a+b+c=44
4+2c+2c+c=44
c=8
b=16
a=20
product of ages= a*b*c=20*16*8=2560

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babita maurya   7 years AGO

let C=x years old.Then according to the question
B=2x,
A=4+2x
now it is given that sum of the ages of A B C is 44 years
i.e. x+2x+(4+2x)=44
5x=40
x=8
It means A=20
B=16
C=8
so product of their ages=20*16*8
=2560
hence option 8 is correct.

Like? Yes | No   

krishna reddy   7 years AGO

A= B+4 and B = 2C so we can write that
A=2C+4
and we also know that A+B+C=44
substituting all the equations we get
C=8.
now B=16. And A=20
ABC=8×20×16=2560.

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Vijeta Budania   7 years AGO

let age of c=x
so, age of b and a are 2x and 2x+4 respectively.
given, a+b+c=44
2x+X+2x+4=44
x=8
therefore, abc= 2560

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KOWSALYA   7 years AGO

a=4+b;b=2c
a+b+c=44
c=8;b=16;a=20
ABC=2560

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Sai Charan   7 years AGO

Age of A = B + 4
Age of B = 2C
i.e, Age of C = B/2

Given that,
A + B + C = 44
(B + 4) + B + (B/2) = 44
B = 16
A = 20
C = 8
A X B X C = 2560

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SARATCHANDRAN   7 years AGO

B=2C
A=(B+4)=2C+4
Given A+B+C= (2C+4)+2C+C=44
5C=40
C=8
therefore B=16 and A=20
A×B×C=20×16×8=20×128 =2560

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shubham kumar   7 years AGO

A=2x+4
b=2x
c=x
2x+4+2x+x=44
x=8
20*16*8=2560

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prasanna   7 years AGO

a+4=b,b=2c
a+b+c=44
solving above equations we get a=20,b=16,c=8
so product of these a,b,c is 2560

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shreya   7 years AGO

A=B+4
B=2C
A+B+C=44
(B+4)+B+(B/2)=44
B=16
A=20
C=8
AXBXC=2560

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Gayatri   7 years AGO

4x=40
x=8
A=2x+4=20
B=2x=16
C=x=8

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S. Subramanyam   7 years AGO

C=x then B=2x and A=2x+4
A+B+C=44
so x=8
then A*B*C=8×16×20=2560

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B.Sri Pravallika   7 years AGO

a=b+4;b=2c;c
a+b+c=44
2c+4+2c+c=44
c=8
a*b*c=2560

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Anandhakumar   7 years AGO

A=B+4
B=2C
A=2C+4
A+B+C=5C=44
So C=8,B=16,A=20,
Product of ABC=2560

Like? Yes | No   

Anjali M Verma   7 years AGO

2x+4+2x+x=44
x is the age of C
so solving we get
x=8
so A=8
B=16
C=20
A×B×C=2560

Like? Yes | No   

Macharla Ramya   7 years AGO

let age of c be 'x'
b=2x,a=2x+4
a+b+c=44
x+2x+2x+4=44
x=8
a=8,b=16,c=20
abc=8×16×20==2560

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Rohan shenoy   7 years AGO

C age is taken as 'x' then B will be '2x' and A will be'2x+4'
2x+4+2x+x=44
x=8
(20)(16)(8)=2560

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Venkatesh V   7 years AGO

by solving with the equation
we get the ages 8,16,20
product = 2560

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Raji Baskar   7 years AGO

B=2C
A=2C+4
A+B+C=44
=>2C+4+2C+C=44
On Solving,
C=8
A*B*C=>20*16*8==>2560

Like? Yes | No   

Rex   7 years AGO

a=b+4;b=2c and a+b+c=44 then converting all in terms of c we have a=2c+4; b=2c; then putting them in the equation a+b+c=44 we have
->(2c+4)+(2c)+(c)=44
->5c+4=44
->5c=40
->c=8
Therefore,
b=2c=2(8)=16 and a=b+4=16+4=20.
Hence the product of their ages = 20*16*8=320*8=2560 answer.

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Navini Kulurkar   7 years AGO

5c=44-4
C=8
B=16
A=4+16=20
A*B*C=20*16*8=2560

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tushar   7 years AGO

(C)x+(B)2x+(A)(2x+4)=44
5x=40
x=8
So 8*16*20=2560

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manisha   7 years AGO

Let b=x, a=x+4, c=x/2
x+x+4+x/2=44
x=16=b , a=16+4=20, c=8
Abc= 16*8*20= 2560

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Raj   7 years AGO

A=B+4
B=2c
A+B+C=44
B=16
A=20
C=8
A*B*C=2560

Like? Yes | No   

Saleena Qureshi   7 years AGO

A= B+4
B = 2C
A+B+C=44

(B+4)+B+(B/2) = 88

B=16
Therefore, C=8, A= 20

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d bose   7 years AGO

let C BE X
SO, B=2X
A=2X+4
SO,A+B+C=44
2X+4+2X+X=44
X=8
SO, C=8
A=20
B=16
SO, ABC=2560

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Riya malaiya   7 years AGO

let c age is x than b age will be 2x and a age will be 2x+4........now.......x+2x+2x+4=44...........we get x=8...now..............8*16*20=2560=ans.

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Divakar   7 years AGO

its simple
x+2x+2x+4=44
x=8
now product of their ages = 8*16*20= 2560

Like? Yes | No   

Sanju Ambiger   7 years AGO

A=4+B
B=2C
4+2C+2C+C=44. c=8
A=20
B=16

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Raghu kln   7 years AGO

a=2x+4
b=2x
c=x
2x+4+2x+x=44
5x+4=44
x=8
20*16*8=2560

Like? Yes | No   

Prabhanshu   7 years AGO

Age of C = 8 yrs.
Age of B = 16yrs.
Age of A= 16+4 = 20yrs
total = 8+16+20=44 yrs..
product = 2560..

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Priti Dhanawade   7 years AGO

A=20
B=16
C=8


20*16*8=2560

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aishwarya pandey   7 years AGO

A=x+4
B=x
C=x/2
as B = 2y
x=2y
y=x÷2
So,
A=x+4
B=x
C=x÷2
SO,
x+4+x+(x÷2)=88
(5*x)+8=80
x=16

A=20
B=16
C=8
20*16*8=2560

Like? Yes | No