What is the probability of getting a product of 36 from three throws of a dice?

M4maths Previous Puzzles

06 Dec 2017 Probability

What is the probability of getting a product of 36 from three throws of a dice?

OPtion

1) 9/216
2) 6/216
3) 1/24
4) 1/27
5) 15/216
6) 2/27
7) 11/216
8) 10/216
9) 2/36
10)None of these

Solution

Total Number of possible outcomes = 6C1*6C1*6C1 = 6*6*6 = 216
Positive outcomes must satisfy D1*D2*D3= 36
Below are such values of D1, D2 and D3:
1, 6, 6
2, 6, 3
2, 3, 6
3, 6, 2
3, 4, 3
3, 3, 4
3, 2, 6
4, 3, 3
6, 6, 1
6, 3, 2
6, 2, 3
6, 1, 6


Count of positive outcome = 12
Probability = Positive outcome/Total Possible Outcomes = 12/216 = 1/18 = 2/36
Option 9)

Correct Option: 9 Best Solution (7)

Dimple   7 years AGO

Possible combinations are
1,6,6 ... 3 options
2,3,6.... 6 options
3,3,4.... 3 options.
so probability = 12/216=1/18=2/36

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Rajaboina Radhika   7 years AGO

possible combinations to get the product 36 are
1,6,6
6,1,6
6,6,1
2,3,6
2,6,3
3,2,6
3,6,2
3,3,4
3,4,3
4,3,3
6,2,3
6,3,2
so the probability of getting the product of 36 from three throws of a dice is 12/216=1/18=2/36
hence ans is option 9

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Rajaboina Rajababu   7 years AGO

possible combinations to get product 36 are
1,6,6
6,1,6
6,6,1
2,3,6
2,6,3
3,2,6
3,6,2
6,2,3
6,3,2
3,3,4
3,4,3
4,3,3
so the probability of getting a product of 36 from three throws of a dice is 12/216=1/18=2/36
hence ans is option 9

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Varun   7 years AGO

Possible combination of dice are :
1 6 6
2 3 6
3 3 4
And they can be arranged/got in
3
6
3
ways respectively.
So total possibilities are 3+6+3 = 12

Total number of possibilities without any conditions = 6*6*6 = 216

Hence, required probability = 12/216 = 2/36

Option 9)

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MD IMDAD   7 years AGO

possible for product of 36= (1,6,6), (6,1,6),(6,6,1)
=(4,3,3),(3,4,3),(3,3,4)
=(6,2,3),( 3,2,6),(2,6,3),(3,6,2),(6,3,2),(2,3,6)
possiblity for product of 36 =12

sample space =36

probablity=12/216
=2/36
option 9 ans

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shalu   7 years AGO

n(s)=6*6*6
n(e)=(6,6,1),(6,1,6),(1,6,6),(6,3,2),(2,3,6),(3,6,2),(3,2,6),(6,2,3),(4,3,3),(3,3,4),(3,4,3),(3,2,6)
p=n(e)/n(s)

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prasanna   7 years AGO

we have only 2 dice
total possibi;ities are 6*6=36
but we get 36 only in 2 dice having 6
so 2 possibilities
probability is =2/36

Like? Yes (1) | No (3)