The sum of 2 numbers is 24 and their product is 143. Difference of the numbers is?

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05 Aug 2010 find the difference?

The sum of 2 numbers is 24 and their product is 143. Difference of the numbers is?

OPtion

1) 2
2) 3
3) 4
4) 5
5) 6
6) 7
7) 8
8) 9
9) 10
10) 1

Solution

Answer: x + y =24, x.y = 143
Take y = 24 – x in the second condition we get
x. (24-x) = 143
24.x – x2 = 143
x2 – 24.x +143 = 0
x = 11,13

Correct Option: 1 Best Solution (20)

Amar   13 years AGO

no will be 13 and 11.

diff is 2.

Like? Yes (2) | No   

kamal   13 years AGO

Let the no.s be x and y.
Then x+y= 24 and xy= 143.
Now, (x-y)^2= (x+y)^2 - 4xy
=24^2- 4*143
=576-572
=4
So, x-y= sq. root of 4= +2, -2.
Since difference is an absolute value, so x-y= 2..... Option 1)

Like? Yes (2) | No   

senthilkumaran   13 years AGO

x+y=24,xy=143
x=24-y
(24-y)y=143,24y-y^2=143, y^2-24y+143=0,
(y-11)(y-13)=0, y=11 and y=13.
if y=11 then x=13
So, the difference is 2

Like? Yes (1) | No   

Dr.Dipin Singh   13 years AGO

Numbers are 13 and 11.
13-11=2

Like? Yes (1) | No   

Bawa   13 years AGO

xy=143;
x+y=24;
x=13, y=11
x-y=2.. option 1

Like? Yes (1) | No   

Mamon Sengupta   13 years AGO

Let the no.s be x and y.
Then x+y= 24 and xy= 143.
Now, (x-y)^2= (x+y)^2 - 4xy
=24^2- 4*143
=576-572
=4
So, x-y= sq. root of 4= +2, -2.
Since difference is an absolute value, so x-y= 2..... Option 1)

Like? Yes (1) | No   

ASHOK ROY   13 years AGO

Let the no.s be x and y.
Then x+y= 24 and xy= 143.
Now, (x-y)^2= (x+y)^2 - 4xy
=24^2- 4*143
=576-572
=4
So, x-y= sq. root of 4= +2, -2.
Since difference is an absolute value, so x-y= 2..... Option 1)

Like? Yes (1) | No   

PADMASHREE   13 years AGO

x+y=24
xy=143
y=143/x
x+143/x=24
solving x^2+143-24x=0
we get the factors 13 and 11 and their difference is 2 which is option(1)

Like? Yes (1) | No   

sanjib biswas   13 years AGO

Let the no.s be x and y.
Then x+y= 24 and xy= 143.
Now, (x-y)^2= (x+y)^2 - 4xy
=24^2- 4*143
=576-572
=4
So, x-y= sq. root of 4= +2, -2.
Since difference is an absolute value, so x-y= 2..... Option 1)

Like? Yes (1) | No   

TAPAN SINGHA   13 years AGO

Let the no.s be x and y.
Then x+y= 24 and xy= 143.
Now, (x-y)^2= (x+y)^2 - 4xy
=24^2- 4*143
=576-572
=4
So, x-y= sq. root of 4= +2, -2.
Since difference is an absolute value, so x-y= 2..... Option 1)

Like? Yes (1) | No   

Prabir Sen   13 years AGO

Let the no.s be x and y.
Then x+y= 24 and xy= 143.
Now, (x-y)^2= (x+y)^2 - 4xy
=24^2- 4*143
=576-572
=4
So, x-y= sq. root of 4= +2, -2.
Since difference is an absolute value, so x-y= 2..... Option 1)

Like? Yes (1) | No   

Khanna   13 years AGO

13-11=2

Like? Yes (1) | No   

YadeeshKumar   13 years AGO

let x+y=24 and x.y=143
and
(x+y)^2=x^2+y^2+2.x.y
and
(x-y)^2=x^2+y^2-2.x.y
(x-y)^2=(x+y)^2-4.x.y
=24^2-4*143
=4
(x-y)^2=4
x-y=2

Like? Yes (1) | No   

A J V   13 years AGO

Square[(x-y)]=square[(x+y)]-4xy
--> Square[(x-y)]=square[24]-4(143)
--> Square[(x-y)]=576-572
--> Square[(x-y)]= 4
Therefore, x-y = 2.

Like? Yes (1) | No   

pmvenkatesh   13 years AGO

assume sum of two number is x+y=2
product of two no is xy=143
we can get 143 multiply the nos 13 with 11....
then sum of two 2 nos is 11+13=24
product is 11*13=143
difference is 13-11=2

Like? Yes (1) | No   

Arneet   13 years AGO

The sum of 2 numbers is 24 and their product is 143.
Numbers are 13 and 11.
Difference of the numbers is 13-11=2.

Like? Yes (1) | No   

Dr. Divya   13 years AGO

Two such numbers are 11 and 13. Their difference is 2.

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GovindhaRajan   13 years AGO

(x+y)pow 2=x pow 2 +y pow 2 +2xy
that solve
2

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senthilkumar   13 years AGO

two numbers are 11 and 13

Like? Yes (1) | No   

Achelal Sharma   13 years AGO

The number is x=13 and y=11
so the difference is 2

Like? Yes (1) | No