A number (x) is 3 less than the thrice of other number (y) and the sum of their squares is 97. The

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22 Jul 2021 Number

A number (x) is 3 less than the thrice of other number (y) and the sum of their squares is 97.
The values of x and y are respectively?

OPtion

(1) 8,4
(2) 4,9
(3) 4,8
(4) 9,4
(5) 3,9
(6) 9,3
(7) 5,9
(8) 9,5
(9) 8,5
(10) None of the above

Solution

x = 3y - 3 and x^2 + y^2 = 97
On solving these two equations
x = 9 and y = 4

Correct Option: 4 Best Solution (4)

Billal Hossain   3 years AGO

according to the question,
x=3y-3 ............ (1)
x^2+y^2=97......... (2)
Putting the value of x in equation (2), we get
(3y-3)^2+y^2=97
or, 9y^2-18y+9+y^2=97
or, 10y^2-18y-88=0
or, 5y^2-9y-44=0
or, 5y^2-20y+11y-44=0
or, 5y(y-4)+11(y-4)=0
or, (y-4)(5y+11)=0
Therefore, y=4
Now, we get from equation (1)
x=3*4-3
or, x=12-3
or, x=9
So,The values of x and y are 9 and 4
Hence, My option is (4)

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G.S.Kantharao   3 years AGO

x=3y-3
x^2+y^2=97
(3y-3)^2+y^2=97
9y^2-18y+9+y^2-97=0
10y^2-18y-88=0
10y^2-40y+22y-88=0
10y(y-4)+22(y-4)=0
(10y+22)(y-4)=0
Hence x,y=9,4
My option is 4👈

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Rats   3 years AGO

x=3y-3
x^2+y^2=97
x=9, y=4

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Chinmay Swarup Chiranjeevi   3 years AGO

x + 3 = 3y

x^2 + y^2 = 97
(3y-3)^2 + y^2 = 97
y =4
x = 3y - 3 = 9

Like? Yes | No