A body falls 12 m in the first second of its motion, 28 m in the second, 44 m in the third, 60 m in the fourth and so on. How far does it fall during the 16th second of its motion?
The distances through which the body falls in first, second, third, fourth, ..... seconds form an A.P. 12 + 28 + 44 + 66 + ...
Here, a = 12, d = 16
Distance through which it falls in 16th second = 16 the term of the A.P.
= a + 15d
= 12 + 15 (16)
= 12 + 240 = 252 m