A body falls 12 m in the first second of its motion, 28 m in the second, 44 m in the third, 60 m in the fourth and so on. How far does it fall during the 16th second of its motion?
The distances through which the body falls in first, second, third, fourth, ..... seconds form an A.P. 12 + 28 + 44 + 66 + ...
Here, a = 12, d = 16
Distance through which it falls in 16th second = 16 the term of the A.P.
= a + 15d
= 12 + 15 (16)
= 12 + 240 = 252 m
The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?
frank
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