Three non negative numbers A, B and C are such that the mean is X and the median is 7. If X is 12 mo

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12 Jan 2022 Mean Median Mode

Three non negative numbers A, B and C are such that the mean is X and the median is 7. If X is 12 more than the smallest number and 17 less than the biggest number, find the value of A+B+C.

OPtion

1) 42
2) 27
3) 48
4) 40
5) 29
6) 46
7) 52
8) 36
9) 30
10) None of these

Solution

Given, Median=7 of three numbers A, B and C, so middle number B=7
Mean X=(A+B+C)/3=A+12 ---(1)
Also, (A+B+C)/3=C-17 ---(2)
Now substituting value of B in above eqn. and solving (1) & (2), we get A=0, C=29
Therefore, A+B+C=0+7+29=36

Correct Option: 8 Best Solution (1)