Three non negative numbers A, B and C are such that the mean is X and the median is 7. If X is 12 more than the smallest number and 17 less than the biggest number, find the value of A+B+C.
Given, Median=7 of three numbers A, B and C, so middle number B=7
Mean X=(A+B+C)/3=A+12 ---(1)
Also, (A+B+C)/3=C-17 ---(2)
Now substituting value of B in above eqn. and solving (1) & (2), we get A=0, C=29
Therefore, A+B+C=0+7+29=36