A train covers a certain distance at a uniform speed. If the train had been 8 kilometre per hour faster, it would have taken 3 hour less than the scheduled time and if the train was slower by 8 kilometre per hour it would have taken 5 hour more than the schedule time. Find length of the journey.
Let the speed of the train be 'x' km/h and the time taken by train to travel the given distance be 't' hours and the total distance be 'd' km. We know that, Distance=Speed*Time
.'. d=x*t
According to 1st case: (x+8)*(t-3) = d
-3x + 8t = 24 ------(1)
Similarly, according to 2nd case: (x-8)*(t+5) = d
5x - 8t = 40 ----(2)
Solving eqn. (1) & (2), we get x=32, t=15
Hence, total length of the journey = d = x*t = 32*15 = 480 km.