Two inlet pipes lead into a large water tank. First pipe can fill the tank in 1 hour 20 minutes; the second pipe can fill it in 50 minutes. At 10:20 am, the first pipe is opened. At what time second one should be opened so that tank gets full by 11:00 am ?
Starting from 10:20 am, tank is to be filled by 11:00 am i.e. in 40 min.
Filling capacity per minute of first pipe=1/80 and of second pipe=1/50
First pipe will fill for total 40 min. and second say opened after 't' min, then 40*(1/80) + (40-t)*(1/50) = 1
Solving, we get t=15
Therefore, second pipe is opened after 15 minute i.e. at 10:35 am.