The value of a certain article is 'k' percent more than its value one year earlier, If the value of

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30 Mar 2022 Percentage

The value of a certain article is 'k' percent more than its value one year earlier, If the value of an article was 'a' rupees on January 1, 2019, and 'b' rupees on January 1, 2021, then in terms of 'a' and 'b' what was the value of an article (in rupees) on January 1, 2022 ?

OPtion

1) a²b
2) √b/√a
3) b + [(b-a)/2]
4) b + (√b/√a)
5) b/√a
6) b*√b/√a
7) √a/√b
8) b²/(2a)
9) 2b/√a
10) None of these

Solution

Price in 2019 = a
Price in 2020 = a∗(1 + k/100)
Price in 2021 = a*(1 + k/100)^2 = b => (1+ k/100) = √(b/a)
Price in 2022 = b∗(1 + k/100) = b*√(b/a) = b*√b/√a
Correct option 6)

Correct Option: 6 Best Solution (3)