What least number must be subtracted from 1739 so that the resulting number when divided by 6, 10 and 12 will leave in each case the same remainder 5 ?
LCM of 6, 10 and 12 = 60
⇒ The multiple of 60 are also divisible by 6, 10 or 12.
.'. Nearest number below 1739 divisible by them = 60 x 28 = 1680
Now, 1685 will be the number that will give remainder 5.
Hence, number to be subtracted = 1739 – 1685 = 54