A alone can complete a piece of work in 30 days. B is 50% more efficient than A. With the help of C,

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28 Apr 2022 Time and Work

A alone can complete a piece of work in 30 days. B is 50% more efficient than A. With the help of C, together they completes the work in 6 days, then C is ___ efficient than ___ (Fill the blanks with given options separated by ,)

OPtion

1) 66.66% more, A
2) 100% more, B
3) 150% less, A
4) 66.66% more, B
5) 133.33% more, A
6) 166.66% more, B
7) 33.33% more, B
8) 150% more, B
9) 66.66% less, A
10) None of these

Solution

Let A, B and C's 1 day work=100, 150 and x units respectively.
Given, A alone can complete the work in 30 days .'. Total work=30*100=3000 units.
6 day's work of A, B & C = 6*(100+150+x) = 3000
x=250
.'. Ratio of work done by A, B & C = 100 : 150 : 250
⇒ C is more efficient than A and B.
% efficiency of C compared to B = (250/150)*100 = 166.66
% efficiency of C compared to A = (250/100)*100 = 250
⇒ C is 66.66% more efficient than B or 150% more efficient than A.
.'. From the given Option 4) is correct

Correct Option: 4 Best Solution (1)

Pargat Pal Singh   2 years AGO

B=1.5A
30A= 6(A+1.5A+C)
C=2.5A
C/B=2.5A/1.5A=5/3= 1.666
means C is 66.66% more efficient than B.

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