A number is divided into two parts such that 60% of the first part is 3 more than the 80% of second

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10 Jun 2022 Number System

A number is divided into two parts such that 60% of the first part is 3 more than the 80% of second part. Also 40% of the first part is 5 less than the 65% of the second part.The number is

OPtion

1) 155
2) 140
3) 120
4) 150
5) 125
6) 145
7) 165
8) 160
9) 135
10) None of these

Solution

Let the first and second part of a number is 'a' and 'b' respectively.
According to given condition:
Case I: (60/100)*a - (80/100)*b = 3 ⇒ 3a - 4b = 15 ---(i)
Case II: (65/100)*b - (40/100)*a = 5 ⇒ 13b - 8a = 100 ---(ii)
From Eqn. (i) & (ii), a=85, b=60
Hence required number = (a + b) = 85+60 = 145

Correct Option: 6 Best Solution (1)

G.S.Kantharao   2 years AGO

Let the parts are x,y
0.6x=0.8y+3=>60x-80y=300
0.4x=0.65y-5=>40x-65y=-500
Solving
120x-195y=-1500
120x-160y=600
-35y=-2100=>y=60
0.6x-0.8*60=3
6x=480+30=>x=510/6=>x=85
Now x+y=85+60=145
My option is 6👈

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