Roshan's present age is five times his daughter's present age and five-eighth of his mother's presen

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28 Jul 2022 Age Problem

Roshan's present age is five times his daughter's present age and five-eighth of his mother's present age. The average age of all of them is 32 years 8 months, then what is the difference between present ages of Roshan's daughter and mother (in years)?

OPtion

1) 56
2) 39
3) 42
4) 59
5) 45
6) 35
7) 40
8) 49
9) 47
10) None of these

Solution

Let Roshan's present age = x years
His daughter's age = x/5
His mother's age = (8/5)*x
Average of all three = [x + x/5 + (8/5)*x] / 3 = 98/3
14x / 5 = 98
x = 35
Present age of daughter=35/5=7 years
Present age of mother=(8/5)*35=56 years
Hence, required difference=56-7=49 years.
Correct Option 8)

Correct Option: 8 Best Solution (3)

G.S.Kantharao   2 years AGO

Let their ages are 5x,x,8x
Average=14x/3=98/3yrs
=>x=7
Difference of their ages=7x
=7*7=49yrs.
My option is 8 👈

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Aarjav jain   2 years AGO

Let's suppose rohan's age is x, so his daughter age is x/5, and his mother's age is 8x/5.
so average is (x+x/5+8x/5)/3=392 months
so value of x is 35 yrs.
then his daughter age is 7 years
and his mother age is 56 years
so difference between their ages is 49 years.

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RAMADURAI NATESAN   2 years AGO

R = 5D = 5M/8. M - D = 8R/5 - R/5 = 7R/5.
R + D + M = 98 (GIVEN) .I.E.,R + R/5 + 8R/5 = 98. R = 35
M - D = 7R/5 = 49

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