Next number of the sequence 1, 4, 12, 32, 80, …. would be

Dr.Dipin Singh   13 years AGO

Next number of the sequence 1, 4, 12, 32, 80, ...

1=1*2^0......
4=2*2^1....
12=3*2^2.....
32=4*2^3.....
80=5*2^4....
192= 6*2^5= 6*32.......option 6

Like? Yes (16) | No (5)  

Dolly   13 years AGO

1=1*1, 4=2*2, 12=3*4, 32=4*8, 80=5*16,

Next number will be 6*32=192

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Sonam H Dhongde   13 years AGO

Sequence is
1. 1
2. 1*2 +2=4
3. 4*2 +4=12
4. 12*2 +8=32
5. 32*2 +16=80

hence
6. 80*2 +32=192

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Pargat Pal Singh   13 years AGO

n*2^(n-1)

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dharmaveer   13 years AGO

we will get the series by using formula n X 2^n-1.
and n= 1,2,3,4,5,6...

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Dimple   13 years AGO

here every term = n*2^(n-1) as 1=1*2^0=1*1=1
4= 2*2^1... similarly 80 = 5*2^4 ...
Hence next number will be 6*2^5 =6*32=192

Like? Yes (4) | No (1)  

Dimple   13 years AGO

6x2^5 =6x32=192

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Bimal   13 years AGO

32*6=192

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KALPANA G   13 years AGO

2^0*1=1, 2^1*2=4, 2^2*3=12, 2^3*4=32, 2^4*5=80, 2^5*6=192.

Like? Yes (3) | No (1)  

Vinay Naveen Christopher.J   13 years AGO

1,2*2=4,3*4=12,4*8=32,5*16=80,6*32=ANS=132

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suneil   13 years AGO

1 4 12 32 80 ?
sequence=(present number*4)-(previous number*4)
so (1*4) - (0*4) = 4
(4*4) - (1*4) = 12
(12*4) - (4*4) = 32
(32*4) - (12*4) = 80
(80*4) - (32*4) = 192

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Ranjeet Verma   13 years AGO

because diffence between previous two digit multiplied by 4 is the current digit
(4-1)*4=12
(12-4)*4=32
(32-12)*4=80
(80-32)*4=192

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Rama Chandra Prakash Kapa   13 years AGO

1*2^0 = 1
2*2^1 = 4
3*2^2 = 12
4*2^3 = 32
5*2^4 = 80
so formula is
n*2^(n-1) which is 6*2^(6-1) = 6*(2^5) = 6*32 = 192

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Suresh Varma P   13 years AGO

Actual formula is = n * 2^(n-1)
Sequence is
1*2^(1-1), 2*2^(2-1), 3*2^(3-1), 4*2^(4-1), 5*2^(5-1), 6*2^(6-1)

6*2^(6-1) = 192 (ans: Option is 6)

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kapil    13 years AGO

1*2+2 = 4
4*2+4 = 12
12*2+8 = 32
32*2+16 = 80
hence: 80*2+32=192

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Saurabh Dua   13 years AGO

the series is of the type-
(2^0)*1=1, (2^1)*2=4, (2^2)*3=12, (2^3)*4=32, (2^4)*5=80
so next term will be
(2^5)*6=192

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Gaurav Kalra   13 years AGO

1 4 12 32 80
Difference between 1 and 4 is 3 so 4*3=12
difference b/w 4 and 12 is 8 so 4*8=32
similarly difference b/w 32 and 80 is 48 so 4*48=192

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ravi jha   13 years AGO

sequence is
2^0*1 2^1*2 2^2*3 2^3*4 2^4*5 so next term will be 2^5*6=192
so option is 6

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Raushan Kumar   13 years AGO

series are: 2^0*1,2^1*2,2^2*3,2^3*4,2^4*5,2^5*6

so ans is: 2^5*6=32*6=192

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C.T.Narayanan   13 years AGO

third no is second no multiplied by 2 and 3/2 , fourth - 2 and 4/3 ... so on

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~Sandeep~   13 years AGO

nth number of series is n*2^(n-1)
So 6th number of series would be = 6*(2^5) =192 (Option 6)

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RAVI   13 years AGO

sequence pattern is like this:
1*1=1
2*2=4
3*4=12
4*8=32
5*16=80
so the next would be
previously we had 1,2,3,4,5 so next is 6* twice of the previous value ie 16*2=32so the next no is
6*32=192

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Ravi B Mali   13 years AGO

Next number in the series is 192.

series given 1,4,12,32,80,....
1*4=4
(4-1)*4= 12
(12-4)*4= 32
(32-12)*4= 80
(80-32)*4= 192

Like? Yes (1) | No (1)