M4maths Previous Puzzles

11 Mar 2011 numbers

How many numbers between 1000 and 99999 (including these 2 numbers too) can be formed by using the numbers 1, 3, 5, 8, 9 ( Repetition of any integer is allowed)

OPtion

1) 2750
2) 2875
3) 240
4) 14400
5) 3750
6) 13589
7) 89999
8) 4560
9) 25
10) 20

Solution

Total numbers of 4 digits = 5*5*5*5 = 625
Total numbers of 5 digits = 5*5*5*5*5 = 3125
Sum these two.

Correct Option: 5 Best Solution (2)